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Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length, and can contain any real number representable by a 32 bit float. Then output a vector that perfectly classifies them. 

This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples. You may take the length of the tuples as a extra input if desired.

Note: It's fine to output a slightlyMany of these can be bisected by many different hyperplanes, any of them would be a valid result as long as. Your code may still be correct if it perfectly classifies the inputproduces very different values from this.

PositiveNegativeResult
[(1,0, 1)][(0,1,1)](1,-1,0)

More test cases tbd

[
    {
        "positive": [[1,0, 1]],
        "negative": [[0,1,1]],
        "result": [1,-1,0]
    },
    {
        "positive": [[12.12958530911699, 71.71547437602891, 17.615042787292396, 1.0], [22.894324259518754, 7.747740085241489, -16.379692578583914, 1.0], [-77.19508767650036, 26.391457800328325, -34.128081828012256, 1.0], [96.46713849700853, 8.223882871718914, 95.59810235088628, 1.0], [95.47166665625838, 36.07081574287895, 20.660512993212635, 1.0]],
        "negative": [[-41.92974660410673, -42.941790456679854, 21.407959882725905, 1.0], [-99.40397441836177, 26.174868779681844, 56.51788064358769, 1.0], [34.482060088467364, -96.36102804944655, 1.5810491199434153, 1.0], [-43.06995918058733, -65.8456447109237, -99.04122951157478, 1.0], [7.7462310407688335, -10.894130800401939, 77.86204331190197, 1.0], [44.47180923569721, -93.53543659179937, 6.715910740415197, 1.0], [71.16273132699712, -80.16856861976358, 48.05726245445331, 1.0]],
        "result": [78.64936114023355, 237.2180619264857, -42.5708443640236, 10.0]
    },
    {
        "positive": [[19.891204296811196, 10.95935510782877, 25.985095341720097, -39.87626202198886, 13.054847014298801, -0.8134570474536389, -54.24129976411458, 1], [-16.576268085926657, 4.5002152868197385, 6.698984554370156, -49.780067496976976, 3.9392362908185703, -11.457246915347255, -3.84485029930714, 1], [-6.424223219895211, -67.86203596702003, 0.6670934629448197, -67.56926034741468, -34.71326779844648, -19.40781793399796, -38.93217338522913, 1], [-55.06122442753092, -46.49216596542017, -28.522294222446035, -30.89448675440849, 25.85546157303159, -28.753484757197114, -67.37074950075419, 1], [12.753734640663126, -42.688681313433065, -37.073894323478854, -22.678023584770216, -12.23724620287598, 4.467063264393019, -28.749388172615724, 1], [-25.894264060028036, -4.384289071814308, 25.545930397049247, -53.005653882689884, -17.7501576060518, -19.66585588898353, -33.29502103119091, 1], [-32.104636572417846, -61.44888846917201, -41.89407929533455, 20.32097494020971, 8.703788581939762, 12.493571659393822, -35.255247777162495, 1], [24.15536843650885, -25.610207061176325, 16.08185788882571, -34.478497500787185, -18.915615320612233, 24.782283056323323, -24.770226555932894, 1], [6.765979248514711, -1.6248990886835486, 19.091220818794667, 14.715692506417057, 7.953257187955259, 12.722665623234263, 14.914783085366352, 1]],
        "negative": [[-2.7270414497182855, 8.676310678740919, -72.98709301742022, -7.70910010724549, 10.477333664984855, -17.506198964389014, 18.233248667960424, 1], [-43.3010158973477, -20.807005424922295, -77.5083019019948, 16.126838313178908, -40.490353240152864, -11.81562605632648, -8.902497984641357, 1], [-31.71159835398403, -14.73301578999785, 13.902967116929815, -21.834371921202447, -40.86878402777407, 6.742152812766307, -16.213431636063206, 1], [-66.57071699396832, -2.6930106603672783, 24.856421108284607, 26.02555433076685, -45.195502153813656, -60.583102046347044, 18.622821621702442, 1], [-47.07567023723187, 8.668277396085415, -55.64099369519978, -24.3651014072761, -77.50500543887348, -29.67008512028478, -27.6004244984169, 1], [16.02465948636585, -64.28947887797132, -18.663992818184852, 11.001922130635734, -65.96111461946506, -70.07973218635979, -41.525576739268594, 1], [-33.6451045267202, -8.496296235717935, -20.129571219612984, 9.152732883489037, 10.242775447179753, -61.865587395289765, -32.78507965995476, 1], [-59.32306321222039, 12.522731642519034, 22.026994802405454, -18.062615366497297, -8.713470639955815, -44.04186584475624, 27.84951438666559, 1], [15.30669132488326, 4.865567302204951, -2.782248675090557, 24.252984759612147, -31.883249650258065, 0.5697927616565579, 22.431436239098076, 1], [1.0357436812954433, -32.44164907799862, 13.942522314820707, 16.30751529733827, -12.905194523861582, -22.446463524560656, 12.651474924205772, 1], [-56.03563699153419, 12.024854226295957, -39.90028407341309, 26.9268535257967, 23.808505964904285, 0.34968582027003947, -29.362006601750707, 1], [-85.14402438073334, -15.501824729148709, -63.38128746811267, -42.15734961052637, -4.1615796887736565, -7.25189532732314, -27.223088213381402, 1], [2.7529807581849184, -23.668062096200217, -9.028343561579462, 2.5495275958544283, 15.88901518194605, -59.28742737700396, 25.402434735936126, 1], [-49.514159298902705, -24.01610873489301, 19.949647054069544, -41.1158129509881, -53.808681913915706, -11.175092994514387, 16.753648710377945, 1], [13.052884356788013, -29.298799492103925, -11.675938518634197, -11.229831992030299, -82.661335125941, 0.4488670991709114, 15.5168860373427, 1], [-10.923814330565236, -44.964063927868544, -38.9909686186201, 15.763631832856007, -44.00734436715622, -54.69686019599016, -52.81999206838163, 1], [-43.815947420234714, 19.90446963235277, 4.773988726751696, -47.12560089860667, 13.028054180292472, -39.81105100874389, 16.639915018971934, 1], [-60.88215048423795, 18.63815015768826, 27.157195120177462, -31.93335885907136, -6.562377024790365, 20.3179674395969, 9.210423673803817, 1], [-20.199358866077134, -50.594347683405196, -65.49273675929138, 19.37323156150201, -13.877303200574588, 19.536120330891066, -17.908737459942998, 1], [-11.03148069515855, 18.400073052625856, -65.34212863735566, -5.32988003172234, 0.7010084382675785, 26.36787095325562, 22.718825279142763, 1], [-30.028696420764177, -20.038640467728513, -47.66006964061526, 1.669739637216125, 3.3366149257696947, -20.495524621115493, 11.79886970131642, 1]],
        "result": [53.402165827630355, -96.34048665666451, 46.75018310196545, -58.648563298215464, 167.65173848467344, 54.84963473487821, -66.47771531555354, 6]
    }
]

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length, and can contain any real number representable by a 32 bit float. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

PositiveNegativeResult
[(1,0, 1)][(0,1,1)](1,-1,0)

More test cases tbd

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length, and can contain any real number representable by a 32 bit float. Then output a vector that perfectly classifies them. 

This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples. You may take the length of the tuples as a extra input if desired.

Note: Many of these can be bisected by many different hyperplanes, any of them would be a valid result. Your code may still be correct if it produces very different values from this.

[
    {
        "positive": [[1,0, 1]],
        "negative": [[0,1,1]],
        "result": [1,-1,0]
    },
    {
        "positive": [[12.12958530911699, 71.71547437602891, 17.615042787292396, 1.0], [22.894324259518754, 7.747740085241489, -16.379692578583914, 1.0], [-77.19508767650036, 26.391457800328325, -34.128081828012256, 1.0], [96.46713849700853, 8.223882871718914, 95.59810235088628, 1.0], [95.47166665625838, 36.07081574287895, 20.660512993212635, 1.0]],
        "negative": [[-41.92974660410673, -42.941790456679854, 21.407959882725905, 1.0], [-99.40397441836177, 26.174868779681844, 56.51788064358769, 1.0], [34.482060088467364, -96.36102804944655, 1.5810491199434153, 1.0], [-43.06995918058733, -65.8456447109237, -99.04122951157478, 1.0], [7.7462310407688335, -10.894130800401939, 77.86204331190197, 1.0], [44.47180923569721, -93.53543659179937, 6.715910740415197, 1.0], [71.16273132699712, -80.16856861976358, 48.05726245445331, 1.0]],
        "result": [78.64936114023355, 237.2180619264857, -42.5708443640236, 10.0]
    },
    {
        "positive": [[19.891204296811196, 10.95935510782877, 25.985095341720097, -39.87626202198886, 13.054847014298801, -0.8134570474536389, -54.24129976411458, 1], [-16.576268085926657, 4.5002152868197385, 6.698984554370156, -49.780067496976976, 3.9392362908185703, -11.457246915347255, -3.84485029930714, 1], [-6.424223219895211, -67.86203596702003, 0.6670934629448197, -67.56926034741468, -34.71326779844648, -19.40781793399796, -38.93217338522913, 1], [-55.06122442753092, -46.49216596542017, -28.522294222446035, -30.89448675440849, 25.85546157303159, -28.753484757197114, -67.37074950075419, 1], [12.753734640663126, -42.688681313433065, -37.073894323478854, -22.678023584770216, -12.23724620287598, 4.467063264393019, -28.749388172615724, 1], [-25.894264060028036, -4.384289071814308, 25.545930397049247, -53.005653882689884, -17.7501576060518, -19.66585588898353, -33.29502103119091, 1], [-32.104636572417846, -61.44888846917201, -41.89407929533455, 20.32097494020971, 8.703788581939762, 12.493571659393822, -35.255247777162495, 1], [24.15536843650885, -25.610207061176325, 16.08185788882571, -34.478497500787185, -18.915615320612233, 24.782283056323323, -24.770226555932894, 1], [6.765979248514711, -1.6248990886835486, 19.091220818794667, 14.715692506417057, 7.953257187955259, 12.722665623234263, 14.914783085366352, 1]],
        "negative": [[-2.7270414497182855, 8.676310678740919, -72.98709301742022, -7.70910010724549, 10.477333664984855, -17.506198964389014, 18.233248667960424, 1], [-43.3010158973477, -20.807005424922295, -77.5083019019948, 16.126838313178908, -40.490353240152864, -11.81562605632648, -8.902497984641357, 1], [-31.71159835398403, -14.73301578999785, 13.902967116929815, -21.834371921202447, -40.86878402777407, 6.742152812766307, -16.213431636063206, 1], [-66.57071699396832, -2.6930106603672783, 24.856421108284607, 26.02555433076685, -45.195502153813656, -60.583102046347044, 18.622821621702442, 1], [-47.07567023723187, 8.668277396085415, -55.64099369519978, -24.3651014072761, -77.50500543887348, -29.67008512028478, -27.6004244984169, 1], [16.02465948636585, -64.28947887797132, -18.663992818184852, 11.001922130635734, -65.96111461946506, -70.07973218635979, -41.525576739268594, 1], [-33.6451045267202, -8.496296235717935, -20.129571219612984, 9.152732883489037, 10.242775447179753, -61.865587395289765, -32.78507965995476, 1], [-59.32306321222039, 12.522731642519034, 22.026994802405454, -18.062615366497297, -8.713470639955815, -44.04186584475624, 27.84951438666559, 1], [15.30669132488326, 4.865567302204951, -2.782248675090557, 24.252984759612147, -31.883249650258065, 0.5697927616565579, 22.431436239098076, 1], [1.0357436812954433, -32.44164907799862, 13.942522314820707, 16.30751529733827, -12.905194523861582, -22.446463524560656, 12.651474924205772, 1], [-56.03563699153419, 12.024854226295957, -39.90028407341309, 26.9268535257967, 23.808505964904285, 0.34968582027003947, -29.362006601750707, 1], [-85.14402438073334, -15.501824729148709, -63.38128746811267, -42.15734961052637, -4.1615796887736565, -7.25189532732314, -27.223088213381402, 1], [2.7529807581849184, -23.668062096200217, -9.028343561579462, 2.5495275958544283, 15.88901518194605, -59.28742737700396, 25.402434735936126, 1], [-49.514159298902705, -24.01610873489301, 19.949647054069544, -41.1158129509881, -53.808681913915706, -11.175092994514387, 16.753648710377945, 1], [13.052884356788013, -29.298799492103925, -11.675938518634197, -11.229831992030299, -82.661335125941, 0.4488670991709114, 15.5168860373427, 1], [-10.923814330565236, -44.964063927868544, -38.9909686186201, 15.763631832856007, -44.00734436715622, -54.69686019599016, -52.81999206838163, 1], [-43.815947420234714, 19.90446963235277, 4.773988726751696, -47.12560089860667, 13.028054180292472, -39.81105100874389, 16.639915018971934, 1], [-60.88215048423795, 18.63815015768826, 27.157195120177462, -31.93335885907136, -6.562377024790365, 20.3179674395969, 9.210423673803817, 1], [-20.199358866077134, -50.594347683405196, -65.49273675929138, 19.37323156150201, -13.877303200574588, 19.536120330891066, -17.908737459942998, 1], [-11.03148069515855, 18.400073052625856, -65.34212863735566, -5.32988003172234, 0.7010084382675785, 26.36787095325562, 22.718825279142763, 1], [-30.028696420764177, -20.038640467728513, -47.66006964061526, 1.669739637216125, 3.3366149257696947, -20.495524621115493, 11.79886970131642, 1]],
        "result": [53.402165827630355, -96.34048665666451, 46.75018310196545, -58.648563298215464, 167.65173848467344, 54.84963473487821, -66.47771531555354, 6]
    }
]
added 65 characters in body
Source Link

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

The dot product is defined as follows:

$$(A_0, A_1, \dots, A_n) \cdot (B_0, B_1, \ldots, B_n) = A_0 B_0 + A_1 B_1 + \ldots + A_n B_n$$

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length, and can contain any real number representable by a 32 bit float. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

The dot product is defined as follows:

$$(A_0, A_1, \dots, A_n) \cdot (B_0, B_1, \ldots, B_n) = A_0 B_0 + A_1 B_1 + \ldots + A_n B_n$$

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

The dot product is defined as follows:

$$(A_0, A_1, \dots, A_n) \cdot (B_0, B_1, \ldots, B_n) = A_0 B_0 + A_1 B_1 + \ldots + A_n B_n$$

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length, and can contain any real number representable by a 32 bit float. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

added 141 characters in body
Source Link

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

The dot product is defined as follows:

$$(A_0, A_1, \dots, A_n) \cdot (B_0, B_1, \ldots, B_n) = A_0 B_0 + A_1 B_1 + \ldots + A_n B_n$$

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

Perceptron

There was a previous perceptron question but it was closed. Also it required a lot of extra stuff that's not normally part of the perception algorithm like I know it. This question will be much simpler

The Percepron is a extremely basic classification algorithm. While it still has some limited use it's been mostly overtaken by gradient descent based algorithms that can match much more complex functions. Still its fun and easy to implement, and is the foundation for many more complex algorithms.

The dot product is defined as follows:

$$(A_0, A_1, \dots, A_n) \cdot (B_0, B_1, \ldots, B_n) = A_0 B_0 + A_1 B_1 + \ldots + A_n B_n$$

Algorithm Description

Percepron can classify vectors into 2 categories, simply by taking the dot product with some vector. If this is positive, you are in category A, if negative, then not.

The algorithm to compute this vector works as follow:

set the initial vector to <0, 0, ..., 0>

while not every data point is classified correctly:
    let p be the first incorrectly classified point
    if the dot product is positive or zero but it should be negative:
        add p to the vector
    if the dot product is negative or zero but it should be positive:
        subtract p from the vector

Among the many weaknesses of this algorithm is that it runs forever if no solution exists, that it can only classify categories separated by a straight plane, and that that plane must pass through the origin.

You do not need to follow this exact algorithm as long as you can guarantee a correct vector in all the cases this algorithm would.

The task

Take as input a list of positive tuples and a list of negative tuples. All tuples will all be the same length. Then output a vector that perfectly classifies them. This is . Shortest answer in each language wins.

You may also take input as a single list of ((x0, ..., xn), category) tuples.

You may assume a solution exists for the input given.

The tuples in the input will always have 1 as their last value, representing bias.

Test Cases

Note: It's fine to output a slightly different result as long as it perfectly classifies the input.

Positive Negative Result
[(1,0, 1)] [(0,1,1)] (1,-1,0)

More test cases tbd

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