Timeline for Sandbox for Proposed Challenges
Current License: CC BY-SA 4.0
16 events
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Oct 3, 2023 at 17:56 | comment | added | Philippos | If you want to thank me, please comment on my idea. someone downvoted, but did not write why. | |
Oct 3, 2023 at 17:11 | comment | added | thejonymyster | @Philippos (1) lmao how did i miss that twice, thanks (2) Thank you, I'll keep working on it based on your suggestion :-) | |
Oct 3, 2023 at 16:58 | history | edited | thejonymyster | CC BY-SA 4.0 |
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Oct 3, 2023 at 16:51 | comment | added | Philippos | (1) The same typo is in the final line of the demonstrated example; I'm sorry I can't correct it myself. (2) Of course you can, maybe with some more words to make it more comprehendable. | |
Oct 3, 2023 at 15:10 | comment | added | thejonymyster | @Philippos (1) Yes, typo, corrected, thanks! (2) Yes! Can I include that wording / a version of it? that seems like the way to go as far as making this more explicit/formally stated... Thanks :-) | |
Oct 3, 2023 at 15:09 | history | edited | thejonymyster | CC BY-SA 4.0 |
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Oct 3, 2023 at 12:25 | comment | added | Philippos |
(1) For your example 11010010 , the answer should be 0011001 , shouldn't it? (2) Can I rephrase the task to »For each position to break the string into two, starting from the left, place a 1 if the number of 0 digits on the shorter part is equal to the number of 1 digits among the neighboring substring of the same length on the other side, otherwise, put a 0 .«?
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Oct 2, 2023 at 16:26 | history | edited | thejonymyster | CC BY-SA 4.0 |
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Sep 25, 2023 at 21:44 | history | edited | thejonymyster | CC BY-SA 4.0 |
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Sep 25, 2023 at 19:23 | comment | added | Someone | It's good—I was just making sure. I think the examples explain it well enough. | |
Sep 25, 2023 at 19:12 | history | edited | thejonymyster | CC BY-SA 4.0 |
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Sep 25, 2023 at 19:08 | comment | added | thejonymyster | @Someone exactly. Would tacking "in any order" onto it fix that, or would you suggest a full rephrasing? EDIT: actually tried something out here, any better or still off? | |
Sep 25, 2023 at 12:55 | comment | added | Someone | So order doesn't matter? | |
Sep 25, 2023 at 1:05 | comment | added | thejonymyster |
@Someone im not sure how to phrase it, but if you have X 1 s and Y 0 s on one end, you need to have Y 1 s and X 0 s on the other side.
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Sep 25, 2023 at 0:22 | comment | added | Someone | What does "opposite digits" mean? | |
Sep 24, 2023 at 20:19 | history | answered | thejonymyster | CC BY-SA 4.0 |