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This "sandbox" is a place where Code Golf users can get feedback on prospective challenges they wish to post to main. This is useful because writing a clear and fully specified challenge on your first try can be difficult, and there is a much better chance of your challenge being well received if you post it in the sandbox first.

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Other

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3991 Answers 3991

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Braid Badly Boundlessly


Your program or function must, given a string in any standard input format, output an infinite stream of delimiter-separated strings where each string is determined from the previous by a braiding algorithm. The program starts with printing the input string.

The algorithm is described as follows: Infinitely alternate between

(1) splitting the string into three substrings then swapping the first two substrings and flattening.

and

(2) splitting the string into three substrings then swapping the last two substrings and flattening.

starting with (1).

The three substrings should be of non-increasing length with the maximum length no more than 1 greater than the minimum length of the three substrings. (This means that when the length of the given string is a multiple of three, the three substrings should be the same length. When the length of the given string is one more than a multiple of three, the first substring should be one character longer than each of the last two substrings. When the length of the given string is two more than a multiple of three, the first and second substrings should each be one character longer than the last substring.)

Example

Let the input be "abcdefg". Let the delimiter be a newline.

Then the program would first print "abcdefg".

It applies (1) which splits the string into ["abc","de","fg"] and swaps the first two elements, reaching ["de","abc","fg"]. It flattens to get "deabcfg" which it prints and uses for the next step.

The program applies (2) to "deabcfg" to split into ["dea","bc","fg"] and swaps into ["dea","fg","bc"], flattening to reach "deafgbc".

The program applies (1) to "deafgbc" and the process repeats ad infinitum.

Then the output would be the newline-separated

abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
abcdefg
[...]

Specifications

  • Note that the string should not be split at the beginning and then only swapped later. The string should be split on each and every iteration
  • The delimiter between lines could be whichever character is convenient. You may assume it does not appear in the input string.
  • The string input shall be at least three characters
  • The input consists solely of printable characters (0x20-0x7F)
  • Of course, standard loopholes are forbidden.

I/O

  • The input and output should be taken in standard I/O methods.
  • The input and output should be taken as string, list of characters, or equivalent.
  • The output should be output continuously, which means you may assume infinite memory.

Test cases

For the test cases, we will assume that the delimiter is a newline. Just the portion before the endless stream is repeats is shown.

input
--
output
-----
abcdefg
--
abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
-----
abc
--
abc
bac
bca
cba
cab
acb
-----
abcdefgh
--
abcdefgh
defabcgh
defghabc
ghadefbc
ghabcdef
bcdghaef
bcdefgha
efgbcdha
efghabcd
habefgcd
habcdefg
cdehabfg
cdefghab
fghcdeab
fghabcde
abcfghde
abcdefgh
-----
Braid
--
Braid
aiBrd
aidBr
dBair
dBrai
radBi
raidB
idraB
idBra
Brida
-----
Cycle
--
Cycle
clCye
cleCy
eCcly
eCycl
yceCl
ycleC
leycC
leCyc
Cylec
-----
O Canada!
--
O Canada!
anaO Cda!
anada!O C
da!anaO C
da!O Cana
O Cda!ana
-----
A man, a plan, a canal - panama!
--
A man, a plan, a canal - panama!
an, a canalA man, a pl - panama!
an, a canal - panama!A man, a pl
 - panama!Aan, a canal man, a pl
 - panama!A man, a plan, a canal
 man, a pla - panama!An, a canal
 man, a plan, a canal - panama!A
n, a canal  man, a pla- panama!A
n, a canal - panama!A man, a pla
- panama!A n, a canal man, a pla
- panama!A man, a plan, a canal 
man, a plan- panama!A , a canal 
man, a plan, a canal - panama!A 
, a canal -man, a plan panama!A 
, a canal - panama!A man, a plan
 panama!A m, a canal -an, a plan
 panama!A man, a plan, a canal -
an, a plan, panama!A m a canal -
an, a plan, a canal - panama!A m
 a canal - an, a plan,panama!A m
 a canal - panama!A man, a plan,
panama!A ma a canal - n, a plan,
panama!A man, a plan, a canal - 
n, a plan, panama!A maa canal - 
n, a plan, a canal - panama!A ma
a canal - pn, a plan, anama!A ma
a canal - panama!A man, a plan, 
anama!A mana canal - p, a plan, 
anama!A man, a plan, a canal - p
, a plan, aanama!A man canal - p
, a plan, a canal - panama!A man
 canal - pa, a plan, anama!A man
 canal - panama!A man, a plan, a
nama!A man, canal - pa a plan, a
nama!A man, a plan, a canal - pa
 a plan, a nama!A man,canal - pa
 a plan, a canal - panama!A man,
canal - pan a plan, a ama!A man,
canal - panama!A man, a plan, a 
ama!A man, canal - pana plan, a 
ama!A man, a plan, a canal - pan
a plan, a cama!A man, anal - pan
a plan, a canal - panama!A man, 
anal - panaa plan, a cma!A man, 
anal - panama!A man, a plan, a c
ma!A man, aanal - pana plan, a c
ma!A man, a plan, a canal - pana
 plan, a cama!A man, anal - pana
 plan, a canal - panama!A man, a
nal - panam plan, a caa!A man, a
nal - panama!A man, a plan, a ca
a!A man, a nal - panamplan, a ca
a!A man, a plan, a canal - panam
plan, a cana!A man, a al - panam
plan, a canal - panama!A man, a 
al - panamaplan, a can!A man, a 
al - panama!A man, a plan, a can
!A man, a pal - panamalan, a can
!A man, a plan, a canal - panama
lan, a cana!A man, a pl - panama
lan, a canal - panama!A man, a p
l - panama!lan, a canaA man, a p
l - panama!A man, a plan, a cana
A man, a pll - panama!an, a cana
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-1
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Rock Paper Scissors, but it's a big, custom tournament

We all know "Rock, Paper, Scissors", and it's pretty variated.

A world tournament is held every year, and it's dang popular.

However, the contestants are able to bring their own ways of play to the plate, and they play with them.

The challenge:

Create a program that, by process of elimination through RPS, determines the winner of the tournament.

The tournament rules:

  • No slackers. (Let the amount of players be an integer equally divisible by 2. [In other words, an even number.])

  • You can bring 2 of either of the 4 variants:

    None: Play regular RPS.

    RPSLV: Play "Rock, Paper, Scissors, Lizard, Spock" (play diagram shown here).

    Best out of three: Play 3 rounds; if by round 2, a player wins the round and has two points, they auto win. Else, winner of the next round wins.

    Double RPS: Play with four hands (two hands used by each player).

  • You cannot bring two of the same variant.

  • In order to use a variant, the two players must have the same type of variant. If there are no matching variants, the gameplay is automatically None.

  • However, if there are more than one variant matches, a game of mode None will be played. The winner of the game mentioned decides what mode they play for the match they will play to see who goes to the next round.

  • In the case of a tie, replay until a win occurs (for all modes)

  • There can be only one winner.

The coding rules:

  • All choices must be randomized (no strategies, to make this simple.).

  • No standard loopholes.

  • Give an explanation as much as you can. (If possible, include a "Try it out online" sample.)

Sample Input/Output:

You must make a table variable with all the player numbers, from 1 to n, with two variants for each player.

n = the amount of players you intend to enter.

Example Input:

Player # | Var 1 | Var 2
1        | RSPLV | None
2        | None  | x2 RPS
3        | x2 RPS| Boo3
4        | Boo3  | x2 RPS
...      |...    | ...

Make a func() that:

1: Checks the variants of the next two availible players on the list, starting at player 1, then does the second to third last rules depending on what happens.

2: Makes the pair engage in battle, gameplay depending on the chosen variant.

3: Finally, boot the loser off the game and add the winner to the next list (round). (The "boot the loser" part isn't that required, but I recommend so as to not make the program add a player to the next table.)

Output (uses table from input):

 Round 1:
 1 vs. 2 // None, since the None variant matches both of them
 ["Rock"/*1*/,"Scissors"/*2*/]
 1 wins

 3 vs. 4 // They have more than one match, so they fight for who decides
 ["P"/*3*/,"S"/*4*/]
 4 wins, and chooses Best out of 3 
 Match 1:
 ["P"/*3*/,"R"/*4*/] // 1(3) - 0(4)

 Match 2:
 ["P"/*3*/,"S"/*4*/] // 1(3) - 1(4)

 Match 3:
 ["P"/*3*/,"R"/*4*/] // 2(3) - 1(4)
 3 wins

 Round 2:
 1 vs. 4 //No matches, defaults to None
 ["R"/*1*/,"R"/*4*/] // No-one wins
 ["R"/*1*/,"S"/*4*/]
 1 wins the tournament

Misc. requirements (some optional):

A {!} means it is required.

  • {!} Print each match, and who wins.

  • {!} Print the tournament winner.

  • {!} The number of players must be flexible.

  • Print the table for each round.

Scenarios:

None:

a vs. b //Either they have no matches, or they have both None matches
["R"/*a*/,"S"/*b*/]
a wins

RPSLV (will make this one quick):

a vs. b //RPSLV chosen
["V"/*a*/,"L"/*b*/]
b wins

Best out of Three:

Scenario 1: (a tie occurs at match 2)

a vs. b //Boo3 chosen
Match 1:
["P"/*a*/,"S"/*b*/] // 0(a) - 1(b)

Match 2:
["P"/*a*/,"P"/*b*/] // tie
["P"/*a*/,"S"/*b*/] // 1(a) - 1(b)

Match 3:
["R"/*a*/,"S"/*4*/] // 2(a) - 1(b)
a wins

Scenario 2: (a player has two points by the end of match 2)

a vs. b //Boo3 chosen
Match 1:
["P"/*a*/,"S"/*b*/] // 0(a) - 1(b)

Match 2:
["S"/*a*/,"P"/*b*/] // 0(a) - 2(b)
b automatically wins

Double RPS:

a vs. b //x2 RPS chosen
[("R", "P")/*a*/, ("S", "S")/*b*/] // lock
[("P", "P")/*a*/, ("S", "S")/*b*/]
b wins

Both the coding and tournament rules apply to your code.

For sandbox use only (won't be included in real question)

I don't know if this kind of problem is suitable for code golf, it could be a programming puzzle, I'm not sure. Go ahead in the comments and tell me what mode it should be, and if I should improve it. (Also, sorry for the mix of Python lists and C++ comments, if it confuses you.) A ** means the choice is random.

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4
  • \$\begingroup\$ Hi and welcome to PPCG, and thanks for using the sandbox! I had a hard time following what you intended from this challenge. The rules are rather disorganised with many points early on not making sense until later. For example, you say: "No slackers. (Let p be a number equally divisible by 2.)" before it is clear that you intend for us to implement a single elimination tournament. I had no idea what "p" was supposed to mean, or why this should matter. I'd recommend trying to explain this to someone verbally, perhaps, to try to organise your thoughts better. Good luck! \$\endgroup\$ Jul 15, 2017 at 21:50
  • \$\begingroup\$ Ah, thanks. I will edit the problem. \$\endgroup\$ Jul 15, 2017 at 22:03
  • \$\begingroup\$ I'm not quite sure what we're supposed to implement. The controller for the tournament and what else? Do we also implement the players, so that we're simulating the entire thing? Or do we have to provide some kind of API for the players? In the first case, how does "The winner decides what mode they play" work? \$\endgroup\$ Jul 16, 2017 at 7:14
  • \$\begingroup\$ Again, any multi-choice is random. \$\endgroup\$ Jul 16, 2017 at 19:29
-1
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Quick! Tell me all the numbers from 1 to 100,000!

Your task is to write a program or function that, when run, output all the numbers from 1 to 100 thousand as quickly as possible to STDOUT. It's that simple. All answers are tested on an HP Compaq nx9420 with an Intel Core Duo @ 1.83 GHz and 3 gigs of RAM using the time command.


Of course, standard loopholes are strictly forbidden.
This is , so may the fastest code win and the best programmer prosper...

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9
  • 3
    \$\begingroup\$ Have you tried running an example to see if the times are variable enough to be meaningful? As-is, this is going to be strongly dependent upon how fast the code can do I/O, which makes the challenge pretty uninteresting, IMO. \$\endgroup\$ Jul 19, 2017 at 18:16
  • \$\begingroup\$ @AdmBorkBork Might be interesting \$\endgroup\$
    – ckjbgames
    Jul 19, 2017 at 21:12
  • 1
    \$\begingroup\$ As far as I can tell, this takes less than a tenth of a second, which means submissions will probably be differentiated solely by noise on your computer. \$\endgroup\$ Jul 20, 2017 at 2:37
  • \$\begingroup\$ upvoted, though I think the differenciation is really difficult, unless you test it on a raspberry PI (for example) having ONLY the program and its compiler installed. \$\endgroup\$ Jul 20, 2017 at 13:36
  • \$\begingroup\$ @FryAmTheEggman How could I improve on that? \$\endgroup\$
    – ckjbgames
    Jul 20, 2017 at 23:38
  • 1
    \$\begingroup\$ @V.Courtois I do have a Pi, and I think I will use that (it has Raspbian installed). \$\endgroup\$
    – ckjbgames
    Jul 20, 2017 at 23:39
  • \$\begingroup\$ The time is still so small even a basic operating system will have to much noise in process creation, etc, for this to work out. You need to make what we are computing substantially more complicated for this to be reasonable. \$\endgroup\$ Jul 21, 2017 at 0:10
  • \$\begingroup\$ @FryAmTheEggman K \$\endgroup\$
    – ckjbgames
    Jul 21, 2017 at 1:20
  • \$\begingroup\$ @ckjbgames good then :) \$\endgroup\$ Jul 21, 2017 at 5:26
-1
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Is it cat-urday?

Caturday is one of the oldest memes out there. For this challenge you need to write a program that outputs the input, but only on Saturday.

The catch:

You can acquire the date via UNIX timestamp, or as a formatted date string (local or UTC). However, you can not:

  • use day of the week information in a date string
  • directly acquire the day of the week of a date by some other means
  • use Date or Calendar functions, beyond one to simply give you the current date
  • use any external resources (files, Internet)

Don't forget leap years!


Does this question work as is? Should I make anything clearer?

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1
  • 5
    \$\begingroup\$ This is a "do X without Y" challenges, and those have been done to death. \$\endgroup\$ Jul 22, 2017 at 20:28
-1
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What's that character? (Part 1)

Recently I ran a command on my laptop that returned a bunch of characters - some printable, some non-printable. I'm having trouble figuring out what those characters are, so I could use some help. Unfortunately, I'm running low on disk space, so you'll have to write me the shortest program you can that I can run.

Challenge

Given a list of ASCII characters, return their names as written on www.asciitable.com, my go-to site for looking up character points.

Input

You may take a string, a list of characters, or a list of ASCII code points (e.g. 'a' -> 97).

You may optionally take the length of the string/list as well. Note that for C, you must take this parameter, since the string could contain NUL bytes, so strlen won't work here.

Output

Output is flexible as usual; you may print or return from a function as you see fit. You should output a list of strings.

The Table

0 NUL
1 SOH
2 STX
3 ETX
4 EOT
5 ENQ
6 ACK
7 BEL
8 BS
9 TAB
10 LF
11 VT
12 FF
13 CR
14 SO
15 SI
16 DLE
17 DC1
18 DC2
19 DC3
20 DC4
21 NAK
22 SYN
23 ETB
24 CAN
25 EM
26 SUB
27 ESC
28 FS
29 GS
30 RS
31 US
32 Space
33 !
34 "
35 #
36 $
37 %
38 &
39 '
40 (
41 )
42 *
43 +
44 ,
45 -
46 .
47 /
48 0
49 1
50 2
51 3
52 4
53 5
54 6
55 7
56 8
57 9
58 :
59 ;
60 
63 ?
64 @
65 A
66 B
67 C
68 D
69 E
70 F
71 G
72 H
73 I
74 J
75 K
76 L
77 M
78 N
79 O
80 P
81 Q
82 R
83 S
84 T
85 U
86 V
87 W
88 X
89 Y
90 Z
91 [
92 \
93 ]
94 ^
95 _
96 `
97 a
98 b
99 c
100 d
101 e
102 f
103 g
104 h
105 i
106 j
107 k
108 l
109 m
110 n
111 o
112 p
113 q
114 r
115 s
116 t
117 u
118 v
119 w
120 x
121 y
122 z
123 {
124 |
125 }
126 ~
127 DEL

Test Cases

[0, 97, 7, 22] -> [NUL, a, BEL, SYN]

More to come...

Meta

  • Would it be more interesting to use the UTF-8 names for the printable characters (0x20 - 0x7E), and the ASCII names for the control characters?
\$\endgroup\$
4
  • \$\begingroup\$ hand copy the table from the website please dont. Try a Google search: theasciicode.com.ar/ascii-codes.txt \$\endgroup\$
    – Stephen
    Jul 23, 2017 at 22:39
  • \$\begingroup\$ @StepHen good call, thanks \$\endgroup\$ Jul 23, 2017 at 23:24
  • \$\begingroup\$ Downvoter: I would much like your feedback rather than just your vote \$\endgroup\$ Jul 24, 2017 at 1:39
  • 1
    \$\begingroup\$ IMO just have take a letter and output the code. Since that part is boilerplate str.chars.map( real program ). Also for ASCII char names NUL is it ok is we output them in lower case? e.g. nul (obviously ascii letters would have fixed case) \$\endgroup\$
    – Downgoat
    Jul 24, 2017 at 1:42
-1
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Lennyface parser and selector

Your mission

Create, in the language of your choice, a program that outputs a randomly selected lennyface (artistic minifigures, see this) from an input - a string composed of numbers and lennyfaces. You will have to : first, parse this input; second, extract a probability mass function f from the parsed input; third, select and output a lennyface respecting f. Read the rules for more details.

Rules

  • Input : A string with lennyfaces and numbers (positive AND negative integers), separated by newlines. You may take input by STDIN or function parameter for example.
  • Output (STDOUT for example) : the randomly-selected lennyface, as a string.
  • The input creates a probability mass function f. If l is a lennyface, then f(l)=(sum of all numbers since the previous lennyface)/x where x is obtained afterwards by summing each of those numerators. @Sandbox : is it clear enough?
  • If (sum of all numbers since the previous lennyface) is equal to zero or negative, you must do as if the numerator is equal to 1 in f's definition.
  • A line with a number contains only this number ; same for a line with a lennyface. So you can assume there will never be a number in a lennyface.
  • If there is nothing on a line (two newlines in a row), you must consider it as a lennyface.
  • You must consider that the last line of the string is directly before its first line. See Test 1 for an example.
  • You can assume there will be at least 1 lennyface in the list; it cannot be composed just by numbers (don't forget that an empty line is a lennyface too).

Example

Given this input list :

( ͡° ͜ʖ ͡°)
2
¯\_ツ_/¯
34
-4
8
└[⸟‿⸟]┘

1

You must have 1/42 chances of outputting ( ͡° ͜ʖ ͡°), 2/42 chances of outputting ¯\_ツ_/¯, 38/42 chances of outputting └[⸟‿⸟]┘ and 1/42 chances of outputting nothing (line 7).

Test cases

Test 1

(⌐■_■)
3

Must output (⌐■_■) with 3/3 chances.

Test 2

ʢ◉ᴥ◉ʡ

Must output ʢ◉ᴥ◉ʡ with 1/1 chance.

Test 3

0
\(ᗝ)/

Must output \(ᗝ)/ with 1/1 chance.

Test 4

( ͡° ͜ʖ ͡°)
2
¯\_ツ_/¯
34
4
☞   ͜ʖ  ☞

0

Must output ( ͡° ͜ʖ ͡°) with 1/42 chance, ¯\_ツ_/¯ with 1/21 chance, ☞  ͜ʖ  ☞ with 19/21 chances and nothing with 1/42 chance.

Test 5

1



( ͡° ͜ʖ ͡°)

Must output ( ͡° ͜ʖ ͡°) with 1/4 chance and nothing with 3/4 chance, since there are 3 empty lines.

Test 6

42

-1
( ͡° ͜ʖ ͡°)

Must output nothing with 43/44 chance and ( ͡° ͜ʖ ͡°) with 1/44 chance.

@Sandbox : should I add test cases?

This is , so shortest code in bytes wins. Standard loopholes apply.

Note : Please do not be discouraged if the parsing is difficult to handle in your language, or if testing is hard because of randomness. Your solution might be very interesting algorithmically, not obviously in terms of golfing. Just please explain in your answer why it works.

Moreover, this is the first code-golf I create, so please let me know if something is not appropriate or if I should give more details on a point. And overall, if you downvote, explain me why so I can improve it.

\$\endgroup\$
16
  • \$\begingroup\$ Yours tests seems a bit contraditory. The number is the chance of the next face (line), so what's the point of the empty line in the example / test 4? By the same logic, the test1 should have a 3/4 of outputting nothing? What is the point of the 0 in the test 4? \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:03
  • \$\begingroup\$ Why is the chance of outputting ( ͡° ͜ʖ ͡°) 1/42 and not 0 ? (since there are no numbers above it) \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:04
  • \$\begingroup\$ Sorry ! I forgot to copy paste the fact that the minimal chance is 1! \$\endgroup\$ Jul 3, 2017 at 14:05
  • \$\begingroup\$ Also, a common thing to do on challenges involving randomness, and therefore, hard to test, is to ask people to provide a mandatory explanation, or at least ask them to show why it works. \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:05
  • \$\begingroup\$ @Dada thanks. I note this. \$\endgroup\$ Jul 3, 2017 at 14:06
  • \$\begingroup\$ @Rod the empty line is a lennyface, as said here : If there is nothing on a line, you must consider it as a lennyface. \$\endgroup\$ Jul 3, 2017 at 14:08
  • \$\begingroup\$ @V.Courtois I meant and empty line without a preceding number \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:09
  • \$\begingroup\$ As I said, the minimum is one (sorry again for forgetting it). \$\endgroup\$ Jul 3, 2017 at 14:10
  • 1
    \$\begingroup\$ If only positive integers are to be expected, you should write it. Otherwise, give some details and examples about what you consider "numbers". \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:12
  • \$\begingroup\$ @Dada editing. In fact I said the minimum is 1, but you can have things like 2,-1,-3,17 and then your lennyface ; that means the probability is 15/ total. \$\endgroup\$ Jul 3, 2017 at 14:14
  • \$\begingroup\$ @V.Courtois just a small suggestion, to make the "list as circle" more explicit you could change the value to something else than 0 or 1, this way it would not overlap the "missing number" rule \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:15
  • \$\begingroup\$ @Rod does it? Sorry if I'm not getting what you are saying, but the list is always a circle, meaning if your list is 2,3,( ͡° ͜ʖ ͡°),4,5,☞  ͜ʖ  ☞,6, you have 6+2+3 chance of getting ( ͡° ͜ʖ ͡°) and 4+5 chance of getting ☞  ͜ʖ  ☞. \$\endgroup\$ Jul 3, 2017 at 14:18
  • \$\begingroup\$ thanks for editing @musicman523 \$\endgroup\$ Jul 4, 2017 at 7:21
  • 5
    \$\begingroup\$ KISS. This is far more complicated than common sense would require. Deliberately overcomplicating things to make it "more difficult" is a guaranteed method to make a bad question. \$\endgroup\$ Jul 4, 2017 at 7:32
  • 1
    \$\begingroup\$ The challenge has two parts as far as I can tell. a) Create a probability mass function from an input by parsing b) sample from the probability mass function. Part a) needs to be rewritten as it is at best ambiguous and at worst just incorrect. \$\endgroup\$
    – user9206
    Jul 5, 2017 at 7:50
-1
\$\begingroup\$

Golf Cubically code

Your task is to optimize Cubically source code using one or more optimizations in this post.

How this challenge works:

  • You will choose one or more optimizations below and write a program (in the language of your choice) that performs those optimizations on a Cubically program.
  • Your program will take a Cubically program as input using any allowed input methods, and output a Cubically program using any allowed output methods.
  • The first answer to successfully perform all optimizations wins!

Optimizations

1. Face turn arguments

Before a face turn is performed, the interpreter calculates turns = turns mod 4. So R5 would be equivalent to R1 which is equivalent to R, R7 is equivalent to R3 which is equivalent to R', etc. Also note that R11111 is equivalent to R5, and R22 is equivalent to nothing at all.

Performing this optimization will mean evaluating all arguments to an R, L, U, D, M, E, or S command and shortening them as much as possible.

Test cases:

Relevant code -> Optimization
R11           -> R2
R1            -> R
L33           -> L2
U22           ->
D222          -> D2
M11111        -> M
E00001        -> E
S9            -> S

2. Repeated face turn

When multiple calls to the same face turn command are present right next to each other, they can clearly be golfed. For example, R2R1 is equivalent to R3. UUU is equivalent to U3. F2F2F2F2 is equivalent F8.

Test cases:

Relevant code -> optimization
R2R2R2        -> R6            (R2 if you also choose optimization 1)
LLL           -> L3
UU            -> UU or U2
D3D2D1        -> D6            (D2 if you also choose optimization 1)

3. "Set notepad to" commands

There are some commands that, instead of adding to/subtracting from/multiplying by/dividing by the notepad, just assign to it. Here are all such commands:

_^=<>⊕«»·|:

When called with multiple arguments, since each argument calls the command separately, only the final argument is relevant. So =123 is equivalent to =3, _00000 is equivalent to _0, and :12345678987654321 is equivalent to 1.

Test cases:

Relevant code -> Optimization
_333          -> _3
=12321        -> =1
+54321        -> +54321
:55           -> :5
/55           -> /55

4. Repeated non-face-turn commands

When multiple face turn commands are present right by each other, their arguments can simply be added together. Commands do not act this way. While R2 calls R with 2, =2 calls = with the face sum of the front face (face index 2).

To perform this optimization, when multiple commands outside of RLUDFBMES appear next to each other, simply remove the duplicated commands without removing the arguments.

Relevant code -> Optimization
_1_1_1_1      -> _1111         (_1 if you also choose optimization 3)
%11%22%33     -> %112233       (%3 if you also choose optimization 3)
+12345+67+8   -> +12345678

5. Nonexistent commands

Go check out the Cubically commands page and you'll see that there are plenty of characters that are not commands. For example, there are no commands that are lowercase letters.

To perform this optimization, remove all nonexistent commands and their arguments from the Cubically source. If the commands also have arguments, you must remove the arguments so that they are not passed to the previous command.

Test cases:

Relevant code -> Optimization
moo cow moo   -> 
moo2cow2moo   -> 
misteR2 FOO   -> R2F
FEAR ME.      -> ERME
u1U2u3U4u5U6  -> U2U4U6   (nothing if you also choose optimization 1, U12 if you also choose optimization 2)

6. Non-implicit commands

There are lots of implicit commands in Cubically (RLUDFBMES()$~&E!), but there are plenty that need to be called with arguments. So %%%% is equivalent to nothing at all while %%2%% is equivalent to %2.

Test cases:

Relevant code -> Optimization
%%%%          -> 
$$$$          -> $$$$
++2++2++2     -> +2+2+2                 (+222 if you also choose optimization 4)
+++>--<-      -> Not Brainf**k, sorry!  (:P)

Sandbox

I'll add more optimizations later.

\$\endgroup\$
2
  • \$\begingroup\$ Clarification on R123: That's the same as R6 and R2, not R3, right? Digits are summed, there are multidigit numbers? That would be better to specify \$\endgroup\$
    – isaacg
    Aug 17, 2017 at 20:13
  • \$\begingroup\$ A few things: first, I can't find the tag "fgitw", is there a typo? Second, does optimization 1 require handling F and B as well, or just the currently listed ones? Third, in optimization 3 most of the listed commands seem invalid because the notepad is used in calculation and then overwritten with the output; for example =11 is not the same as =1 in most circumstances. In fact, I think only _: are valid. Fourth, is the winning answer one which performs all optimizations in a single program, or one which contains a separate program for each optimization? \$\endgroup\$ Aug 18, 2017 at 18:03
-1
\$\begingroup\$

Hungry for Apples?

enter image description here

This challenge is simple, given an integer 0 <= n or 0 < n, output an ASCII-apple with that many bites taken out of it.


No bites (0):

         //
     .-.:|.-.
   .'   ''   '.
   ;          ;
  :            :
  :            :
  :            :
   :          ;
   '.        :
     '-_.._-'

Bite 1:

         //
     .-.:|.-.
   .'   ''   '.
   ;          ;
   '-.         :
     }         :
   .-'         :
   :          ;
   '.        :
     '-_.._-'

Bite 2:

         //
     .-.:|.-.
   .'   ''   '.
   '-.        ;
     }         :
     }         :
     }         :
   .-'        ;
   '.        :
     '-_.._-'

Bite 3:

         //
     .-.:|.-.
   .'   ''   '.
   '-.        ;
     }      .-'
     }      {
     }      '-.
   .-'        ;
   '.        :
     '-_.._-'

Bite 4:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }      {
     }      {
     }      {
   .-'      '.
   '.        :
     '-_.._-'

Bite 5:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }".    {
     } }    {
     } }    {
   .-'"     '.
   '.        :
     '-_.._-'

Bite 6:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }"~".  {
     } } }  {
     } } }  {
   .-'"~"   '.
   '.        :
     '-_.._-'

Bite 7:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }"~"~".{
     } } } }{
     } } } }{
   .-'"~"~" '.
   '.        :
     '-_.._-'

Bite >7:

[empty output]

Rules

  • You may have trailing spaces, make it consistent though.
  • You may have exactly 1 trailing newline.
  • You are NOT doing an animation here, you are taking in n and outputting an apple.
  • You may error on integers less than 0, as the spec provides n > 0.
  • You must have empty output (no error) on n > 7/8.
    • You threw out the core; you didn't error the core into non-existence.

This is

\$\endgroup\$
3
  • 3
    \$\begingroup\$ I feel this would be better if there was some more symmetry in the 5, 6, and 7 bytes so that people could possibly make better compression. \$\endgroup\$ Aug 4, 2017 at 18:26
  • \$\begingroup\$ @AdmBorkBork better? \$\endgroup\$ Aug 22, 2017 at 21:26
  • 1
    \$\begingroup\$ Yes, much better. \$\endgroup\$ Aug 23, 2017 at 12:33
-1
\$\begingroup\$

Proper Kerning

Kerning is the adjustment of spacing between pairs of letters in order to obtain an aesthetic result. When kerning is applied automatically by a program (typically whatever editor you're using), it is said to be automatic. There are two types of automatic kerning. The one used in this challenge is metric kerning. With metric kerning, the amount of space between pairs of letters is dictated by the kerning tables found in the font file.

Given a TrueType font file, output the kerning values for each mapping in the kerning table for ASCII characters 48 - 122 inclusive.

Example

calibri.ttf

l="A" r="C" v="-15"
l="A" r="G" v="-15"
l="A" r="J" v="23"
l="A" r="O" v="-23"
l="A" r="Q" v="-23"
l="A" r="T" v="-160"
l="A" r="U" v="-32"
l="A" r="V" v="-89"
l="A" r="W" v="-80"
l="A" r="Y" v="-150"
l="A" r="t" v="-52"
l="A" r="v" v="-38"
l="A" r="y" v="-41"
l="A" r="?" v="-68"
l="B" r="A" v="-20"
l="B" r="T" v="-48"
l="B" r="V" v="-25"
l="B" r="W" v="-24"
l="B" r="X" v="-44"
l="B" r="Y" v="-57"
l="B" r="Z" v="-20"
l="B" r="f" v="-20"
l="B" r="t" v="-20"
l="B" r="v" v="-20"
l="B" r="x" v="-15"
l="B" r="y" v="-20"
l="C" r="G" v="-18"
l="C" r="J" v="12"
l="C" r="O" v="-18"
l="C" r="Q" v="-18"
l="C" r="T" v="10"
l="D" r="A" v="-30"
l="D" r="J" v="-22"
l="D" r="T" v="-23"
l="D" r="V" v="-24"
l="D" r="W" v="-14"
l="D" r="X" v="-31"
l="D" r="Y" v="-39"
l="D" r="Z" v="-22"
l="E" r="A" v="-22"
l="E" r="C" v="-24"
l="E" r="G" v="-24"
l="E" r="O" v="-32"
l="E" r="Q" v="-32"
l="E" r="S" v="-20"
l="E" r="Z" v="-10"
l="E" r="a" v="-34"
l="E" r="c" v="-28"
l="E" r="d" v="-30"
l="E" r="e" v="-37"
l="E" r="f" v="-64"
l="E" r="o" v="-37"
l="E" r="q" v="-30"
l="E" r="t" v="-24"
l="E" r="v" v="-48"
l="E" r="w" v="-34"
l="E" r="y" v="-48"
l="F" r="A" v="-115"
l="F" r="C" v="-18"
l="F" r="G" v="-18"
l="F" r="J" v="-109"
l="F" r="O" v="-18"
l="F" r="Q" v="-18"
l="F" r="S" v="-29"
l="F" r="X" v="-22"
l="F" r="Z" v="-11"
l="F" r="a" v="-55"
l="F" r="c" v="-28"
l="F" r="d" v="-20"
l="F" r="e" v="-30"
l="F" r="o" v="-28"
l="F" r="q" v="-20"
l="F" r="s" v="-35"
l="G" r="T" v="-10"
l="G" r="V" v="-10"
l="G" r="W" v="-9"
l="G" r="Y" v="-30"
l="G" r="v" v="-29"
l="G" r="w" v="-22"
l="G" r="x" v="-14"
l="G" r="y" v="-30"
l="J" r="A" v="-35"
l="J" r="X" v="-20"
l="K" r="C" v="-78"
l="K" r="G" v="-80"
l="K" r="O" v="-97"
l="K" r="Q" v="-97"
l="K" r="S" v="-18"
l="K" r="U" v="-29"
l="K" r="W" v="-34"
l="K" r="a" v="-34"
l="K" r="c" v="-40"
l="K" r="d" v="-33"
l="K" r="e" v="-37"
l="K" r="f" v="-25"
l="K" r="m" v="-32"
l="K" r="n" v="-32"
l="K" r="o" v="-37"
l="K" r="p" v="-32"
l="K" r="q" v="-33"
l="K" r="r" v="-32"
l="K" r="s" v="-18"
l="K" r="t" v="-38"
l="K" r="u" v="-32"
l="K" r="v" v="-101"
l="K" r="w" v="-95"
l="K" r="y" v="-85"
l="L" r="C" v="-22"
l="L" r="G" v="-47"
l="L" r="J" v="25"
l="L" r="O" v="-45"
l="L" r="Q" v="-45"
l="L" r="T" v="-150"
l="L" r="U" v="-44"
l="L" r="V" v="-147"
l="L" r="W" v="-118"
l="L" r="Y" v="-167"
l="L" r="f" v="-23"
l="L" r="t" v="-38"
l="L" r="v" v="-78"
l="L" r="w" v="-72"
l="L" r="y" v="-79"
l="O" r="A" v="-23"
l="O" r="J" v="-27"
l="O" r="T" v="-55"
l="O" r="V" v="-25"
l="O" r="W" v="-22"
l="O" r="X" v="-64"
l="O" r="Y" v="-55"
l="O" r="Z" v="-38"
l="O" r="x" v="-12"
l="O" r="z" v="-10"
l="P" r="A" v="-151"
l="P" r="J" v="-140"
l="P" r="T" v="-9"
l="P" r="V" v="-10"
l="P" r="X" v="-35"
l="P" r="Y" v="-11"
l="P" r="Z" v="-29"
l="P" r="a" v="-44"
l="P" r="c" v="-43"
l="P" r="d" v="-34"
l="P" r="e" v="-41"
l="P" r="f" v="12"
l="P" r="o" v="-41"
l="P" r="q" v="-34"
l="P" r="s" v="-32"
l="P" r="t" v="12"
l="P" r="y" v="12"
l="Q" r="J" v="41"
l="Q" r="T" v="-47"
l="Q" r="V" v="-25"
l="Q" r="W" v="-12"
l="Q" r="X" v="12"
l="Q" r="Y" v="-46"
l="Q" r="g" v="59"
l="Q" r="j" v="79"
l="Q" r="x" v="31"
l="Q" r=";" v="60"
l="Q" r="]" v="32"
l="R" r="C" v="-18"
l="R" r="G" v="-19"
l="R" r="O" v="-20"
l="R" r="Q" v="-20"
l="R" r="S" v="-27"
l="R" r="T" v="-20"
l="R" r="V" v="-28"
l="R" r="W" v="-18"
l="R" r="Y" v="-30"
l="R" r="e" v="-36"
l="R" r="o" v="-42"
l="R" r="v" v="-26"
l="R" r="w" v="-33"
l="R" r="y" v="-33"
l="S" r="A" v="-15"
l="S" r="J" v="-9"
l="S" r="T" v="-14"
l="S" r="V" v="-14"
l="S" r="W" v="-15"
l="S" r="X" v="-13"
l="S" r="Y" v="-20"
l="S" r="v" v="-23"
l="S" r="w" v="-17"
l="S" r="y" v="-25"
l="T" r="A" v="-160"
l="T" r="C" v="-42"
l="T" r="G" v="-59"
l="T" r="J" v="-65"
l="T" r="O" v="-58"
l="T" r="Q" v="-58"
l="T" r="S" v="-10"
l="T" r="T" v="28"
l="T" r="a" v="-160"
l="T" r="c" v="-177"
l="T" r="d" v="-147"
l="T" r="e" v="-182"
l="T" r="g" v="-151"
l="T" r="m" v="-127"
l="T" r="n" v="-127"
l="T" r="o" v="-182"
l="T" r="p" v="-127"
l="T" r="q" v="-147"
l="T" r="r" v="-127"
l="T" r="s" v="-153"
l="T" r="u" v="-127"
l="T" r="v" v="-92"
l="T" r="w" v="-86"
l="T" r="x" v="-90"
l="T" r="y" v="-93"
l="T" r="z" v="-142"
l="T" r=";" v="-114"
l="T" r=":" v="-134"
l="U" r="A" v="-45"
l="U" r="J" v="-40"
l="V" r="A" v="-96"
l="V" r="C" v="-18"
l="V" r="G" v="-25"
l="V" r="J" v="-80"
l="V" r="O" v="-27"
l="V" r="Q" v="-27"
l="V" r="S" v="-12"
l="V" r="V" v="9"
l="V" r="a" v="-114"
l="V" r="c" v="-103"
l="V" r="d" v="-87"
l="V" r="e" v="-102"
l="V" r="g" v="-100"
l="V" r="m" v="-50"
l="V" r="n" v="-50"
l="V" r="o" v="-86"
l="V" r="p" v="-50"
l="V" r="q" v="-87"
l="V" r="r" v="-50"
l="V" r="s" v="-90"
l="V" r="u" v="-50"
l="V" r="y" v="-35"
l="V" r="z" v="-82"
l="V" r=";" v="-108"
l="V" r=":" v="-73"
l="W" r="A" v="-93"
l="W" r="C" v="-22"
l="W" r="G" v="-22"
l="W" r="J" v="-88"
l="W" r="O" v="-22"
l="W" r="Q" v="-22"
l="W" r="S" v="-10"
l="W" r="X" v="-13"
l="W" r="a" v="-71"
l="W" r="c" v="-78"
l="W" r="d" v="-72"
l="W" r="e" v="-75"
l="W" r="g" v="-54"
l="W" r="m" v="-60"
l="W" r="n" v="-60"
l="W" r="o" v="-86"
l="W" r="p" v="-60"
l="W" r="q" v="-72"
l="W" r="r" v="-60"
l="W" r="s" v="-73"
l="W" r="u" v="-60"
l="W" r="v" v="-34"
l="W" r="y" v="-53"
l="W" r=";" v="-156"
l="X" r="C" v="-57"
l="X" r="G" v="-65"
l="X" r="O" v="-57"
l="X" r="Q" v="-57"
l="X" r="S" v="-20"
l="X" r="d" v="-44"
l="X" r="e" v="-39"
l="X" r="g" v="-9"
l="X" r="o" v="-38"
l="X" r="q" v="-44"
l="X" r="t" v="-31"
l="X" r="u" v="-38"
l="X" r="v" v="-55"
l="X" r="w" v="-49"
l="X" r="y" v="-43"
l="Y" r="A" v="-152"
l="Y" r="C" v="-67"
l="Y" r="G" v="-67"
l="Y" r="J" v="-112"
l="Y" r="O" v="-66"
l="Y" r="Q" v="-66"
l="Y" r="S" v="-17"
l="Y" r="Z" v="-10"
l="Y" r="a" v="-134"
l="Y" r="c" v="-159"
l="Y" r="d" v="-131"
l="Y" r="e" v="-147"
l="Y" r="f" v="-62"
l="Y" r="g" v="-142"
l="Y" r="i" v="-32"
l="Y" r="j" v="-49"
l="Y" r="m" v="-94"
l="Y" r="n" v="-94"
l="Y" r="o" v="-153"
l="Y" r="p" v="-94"
l="Y" r="q" v="-131"
l="Y" r="r" v="-94"
l="Y" r="s" v="-115"
l="Y" r="t" v="-44"
l="Y" r="u" v="-94"
l="Y" r="v" v="-69"
l="Y" r="w" v="-62"
l="Y" r="x" v="-70"
l="Y" r="y" v="-65"
l="Y" r="z" v="-100"
l="Y" r=";" v="-138"
l="Y" r=":" v="-154"
l="Z" r="A" v="-11"
l="Z" r="C" v="-25"
l="Z" r="G" v="-24"
l="Z" r="O" v="-24"
l="Z" r="Q" v="-24"
l="Z" r="W" v="-7"
l="Z" r="Y" v="-7"
l="Z" r="a" v="-10"
l="Z" r="c" v="-12"
l="Z" r="d" v="-18"
l="Z" r="e" v="-31"
l="Z" r="o" v="-29"
l="Z" r="q" v="-18"
l="Z" r="v" v="-45"
l="Z" r="w" v="-38"
l="Z" r="y" v="-37"
l="a" r="f" v="-12"
l="a" r="t" v="-19"
l="a" r="v" v="-34"
l="a" r="w" v="-14"
l="a" r="x" v="-19"
l="a" r="y" v="-38"
l="b" r="f" v="-17"
l="b" r="s" v="-10"
l="b" r="t" v="-9"
l="b" r="v" v="-10"
l="b" r="w" v="-10"
l="b" r="x" v="-41"
l="b" r="y" v="-10"
l="b" r="z" v="-28"
l="c" r="a" v="-17"
l="c" r="o" v="-17"
l="e" r="f" v="-18"
l="e" r="t" v="-11"
l="e" r="v" v="-10"
l="e" r="w" v="-10"
l="e" r="x" v="-31"
l="e" r="y" v="-13"
l="e" r="z" v="-20"
l="f" r="a" v="-40"
l="f" r="c" v="-45"
l="f" r="d" v="-53"
l="f" r="e" v="-51"
l="f" r="f" v="-20"
l="f" r="g" v="-60"
l="f" r="o" v="-43"
l="f" r="q" v="-53"
l="f" r="s" v="-27"
l="f" r="v" v="13"
l="f" r="w" v="6"
l="f" r="y" v="10"
l="f" r="z" v="-20"
l="g" r="a" v="-38"
l="g" r="c" v="-12"
l="g" r="d" v="-19"
l="g" r="e" v="-17"
l="g" r="g" v="19"
l="g" r="o" v="-14"
l="g" r="q" v="-19"
l="g" r="t" v="-31"
l="h" r="f" v="-12"
l="h" r="t" v="-19"
l="h" r="v" v="-34"
l="h" r="w" v="-14"
l="h" r="x" v="-19"
l="h" r="y" v="-38"
l="k" r="a" v="-35"
l="k" r="c" v="-48"
l="k" r="d" v="-56"
l="k" r="e" v="-66"
l="k" r="o" v="-69"
l="k" r="q" v="-56"
l="k" r="s" v="-19"
l="k" r="t" v="-10"
l="k" r="u" v="-26"
l="m" r="f" v="-12"
l="m" r="t" v="-19"
l="m" r="v" v="-34"
l="m" r="w" v="-14"
l="m" r="x" v="-19"
l="m" r="y" v="-38"
l="n" r="f" v="-12"
l="n" r="t" v="-19"
l="n" r="v" v="-34"
l="n" r="w" v="-14"
l="n" r="x" v="-19"
l="n" r="y" v="-38"
l="o" r="v" v="-9"
l="o" r="w" v="-8"
l="o" r="x" v="-40"
l="o" r="y" v="-11"
l="o" r="z" v="-27"
l="p" r="f" v="-17"
l="p" r="s" v="-10"
l="p" r="t" v="-9"
l="p" r="v" v="-10"
l="p" r="w" v="-10"
l="p" r="x" v="-41"
l="p" r="y" v="-10"
l="p" r="z" v="-28"
l="q" r="g" v="10"
l="r" r="a" v="-42"
l="r" r="c" v="-30"
l="r" r="d" v="-28"
l="r" r="e" v="-27"
l="r" r="g" v="-28"
l="r" r="o" v="-33"
l="r" r="q" v="-28"
l="r" r="s" v="-35"
l="r" r="v" v="19"
l="r" r="w" v="11"
l="r" r="y" v="10"
l="s" r="f" v="-19"
l="s" r="t" v="-23"
l="s" r="v" v="-31"
l="s" r="w" v="-10"
l="s" r="x" v="-22"
l="s" r="y" v="-37"
l="s" r="z" v="-18"
l="t" r="a" v="-25"
l="t" r="c" v="-25"
l="t" r="d" v="-23"
l="t" r="e" v="-22"
l="t" r="o" v="-20"
l="t" r="q" v="-23"
l="t" r="t" v="-29"
l="v" r="a" v="-30"
l="v" r="c" v="-25"
l="v" r="d" v="-20"
l="v" r="e" v="-20"
l="v" r="f" v="11"
l="v" r="g" v="-28"
l="v" r="o" v="-19"
l="v" r="q" v="-20"
l="v" r="s" v="-9"
l="v" r="t" v="10"
l="v" r="v" v="12"
l="v" r="w" v="12"
l="v" r="y" v="12"
l="v" r="z" v="-26"
l="w" r="a" v="-23"
l="w" r="c" v="-20"
l="w" r="d" v="-18"
l="w" r="e" v="-18"
l="w" r="f" v="6"
l="w" r="g" v="-18"
l="w" r="o" v="-19"
l="w" r="q" v="-18"
l="w" r="s" v="-18"
l="w" r="t" v="4"
l="w" r="v" v="12"
l="w" r="w" v="8"
l="w" r="y" v="12"
l="w" r="z" v="-17"
l="x" r="a" v="-37"
l="x" r="c" v="-46"
l="x" r="d" v="-44"
l="x" r="e" v="-54"
l="x" r="o" v="-55"
l="x" r="q" v="-44"
l="x" r="s" v="-12"
l="x" r="t" v="6"
l="x" r="u" v="-20"
l="y" r="a" v="-31"
l="y" r="c" v="-26"
l="y" r="d" v="-24"
l="y" r="e" v="-25"
l="y" r="f" v="10"
l="y" r="g" v="-26"
l="y" r="o" v="-24"
l="y" r="q" v="-24"
l="y" r="s" v="-19"
l="y" r="t" v="10"
l="y" r="v" v="12"
l="y" r="w" v="8"
l="y" r="y" v="10"
l="y" r="z" v="-17"
l="z" r="a" v="-34"
l="z" r="c" v="-45"
l="z" r="d" v="-46"
l="z" r="e" v="-46"
l="z" r="f" v="-10"
l="z" r="g" v="-17"
l="z" r="o" v="-45"
l="z" r="q" v="-46"
l="z" r="s" v="-22"
l="z" r="u" v="-10"
l="z" r="v" v="-18"
l="z" r="w" v="-22"
l="z" r="y" v="-18"

Scoring

This is , so the shortest answer (in bytes) wins.

Meta

I know this challenge is going to need a lot of work before it's ready for main. Please hold criticisms for now. Helpful ideas and thoughts are welcome.

\$\endgroup\$
7
  • \$\begingroup\$ I'm not sure that the problem is well defined. There's a reason it's called font hinting: the rendering application is free to take it into account or not, or even to apply more complex logic. E.g. some fonts have multiple sets of font hints for different contexts. There are other complex issues. A font can have Latin and Cyrillic letters and define hints for kerning between pairs of Latin and pairs of Cyrillic but not between Latin and Cyrillic; however, some letters may have identical glyphs, so a judgement on whether the kerning is "correct" might be ambiguous. Then there's antialiasing. \$\endgroup\$ May 24, 2017 at 6:15
  • \$\begingroup\$ @PeterTaylor Good notes. I will likely restrict the character set. I just wanted to start getting ideas down in the sandbox. \$\endgroup\$
    – Poke
    May 24, 2017 at 6:51
  • \$\begingroup\$ Very ambiguous. \$\endgroup\$
    – anna328p
    May 25, 2017 at 17:48
  • \$\begingroup\$ @Mendeleev It's not done yet. I'm aware it's ambiguous. \$\endgroup\$
    – Poke
    May 26, 2017 at 16:10
  • \$\begingroup\$ Looking at developer.apple.com/fonts/TrueType-Reference-Manual/RM06/… I can see a number of issues to address. 16- vs 32-bit entries? Should multiple tables be combined or printed separately? All tables or only tables with certain coverage values? Which of the four defined formats need to be supported? Do you have a test case which covers glyph index differing from codepoint? \$\endgroup\$ Sep 16, 2017 at 17:28
  • \$\begingroup\$ @PeterTaylor I have a proof of concept that I wrote (it's the reason I have taken so long to update this) and I'm planning to address all of your questions. Thanks for doing a bit of research to help me out, though :] \$\endgroup\$
    – Poke
    Sep 16, 2017 at 18:57
  • \$\begingroup\$ Downvoter, why? \$\endgroup\$
    – Poke
    Oct 4, 2017 at 21:03
-1
\$\begingroup\$

Six Flags over HTTP

Let's say you need to transmit six boolean flags in a URL string. Obviously you could do it with six ones or zeroes, but you want better compression. With a little math you can pack them into two characters using 0-7 octal.

How about mapping all six to a single ASCII character? Here we have a problem: you are not allowed to use , / ? : @ & = + $ # or space. Now the range of printable ASCII no longer has 64 valid characters in a row.

In Javascript (or another language that can run from a web page, if any), what is the shortest code for a pair of functions to encode and decode this data, between an array of six booleans and a single character?

\$\endgroup\$
2
  • \$\begingroup\$ -1 language restriction, most languages have HTTP libraries so I think any language should be allowed \$\endgroup\$
    – ASCII-only
    Sep 24, 2017 at 13:11
  • \$\begingroup\$ This challenge could be improved by rephrasing it to: "Write a bijective function between an array of six booleans and a single printable character excluding the characters ,/?:@&=+$# ". Mentioning that the encoder and decoder should be separate programs/functions would be helpful. Also, may the encoder and decoder share code? \$\endgroup\$ Sep 24, 2017 at 22:08
-1
\$\begingroup\$

Count letter frequency

Inspired by question Tweetable hash function challenge, you should take the English dictionary used there and produce a program or function that outputs the the absolute and relative frequency of each character. It is CASE SENSITIVE and the APOSTROPHE is also accountable as a real letter.

Example of a valid output format (but with stupid guessing values):

A      5566    20%
...
Z        60     0.2%
a     27000    30%
...
z       120     0.01%
'       450     3.5%

It is , but no answer will be accepted. Wanna know shortest script for each language.

\$\endgroup\$
1
  • 1
    \$\begingroup\$ -1 (01) Don't rely on another challenge to define yours; include all the information we need in your write-up. (02) Make an effort to come up with some actual test cases - do you honestly expect us to verify our solutions against "stupid guessing values"? \$\endgroup\$
    – Shaggy
    Sep 30, 2017 at 0:55
-1
\$\begingroup\$

Is it a perfect loop?

Your task is to take a GIF or an animated image in any reasonable format as input (including taking the file name of a GIF in the current directory), and output whether it is a "perfect loop" - that is, the frames transition seamlessly from the end to the start, and a human cannot notice where it starts and ends at first glance. Return or print a truthy value if it is a perfect loop, otherwise print or return a falsy value.

Scoring

Winners will be determined from the percentage of test cases they get correct. In the event of a tie, highest votes wins. You can view test cases at https://ghostbin.com/paste/m3yaw. Show your score against the test cases when you post.

Input

If you are not taking input in a GIF, please provide a program that will convert a GIF to your desired format.

Images corresponding to a truthy value have been taken from /r/perfectloops and for falsy test cases, /r/almostperfectloops and /r/gifs.

Restrictions

  • Hard coding is not allowed (violates standard loophole 1 and 2).
  • You must provide consistent results for the same GIF (no randomness)
  • Remember, this is not , so byte count is not needed in your solution. Just post the language name and add the percentage correct when I comment.
\$\endgroup\$
2
  • \$\begingroup\$ I'm not sure it's as simple as comparing the first to the last frame, if it is we'd have duplicate frames. is this challenge allowing HTTP requests? \$\endgroup\$
    – tuskiomi
    Oct 17, 2017 at 21:15
  • \$\begingroup\$ If hashing the inputs is not allowed, then you should clearly define what constitutes a “perfect loop”. It's not good to extrapolate from a handful of test cases where the pass/fail cases are very similar. \$\endgroup\$
    – japh
    Oct 18, 2017 at 14:31
-1
\$\begingroup\$

Highest code size∕output ratio to generate a large executable section inside an elf file.

Your challenge is to create the shortest code in your language of choice or the tools of your choice (like objcopy) that will create an elf file with a the executable section as large as possible.
I mean that if I extract the.text section of the elf binary, the resulting extracted file should be at least 90% of the elf binary.

Requirements

  • The program should takes the desired section size as input.
  • The .text section name needs to corresponds to the executable section.
  • The type of the .text section should bePROGBITSand it should contains instructions.
  • The elf file should have a .shstrtab section.
  • The .text section should be readable and writable.
  • The target architecture should be Pnacl or armelv7 or x86_64.
  • The elf file should be valid and pass Google nacl’s validation whitelist in order to be loaded (but I don´t care if the sandbox segfault).
    If you have no idea about what Google native client is, just create a script that call the patched version of binutils from the nacl_sdk, or make sure the elf file is valid and can be executed on Linux.

Of course, you normally can’t use a compiler because it would takes too much computational years in order to finish.

Winner

The answer with the highest code size∕program output ratio.

\$\endgroup\$
9
  • 1
    \$\begingroup\$ Why not make scoring output size / code size? \$\endgroup\$
    – anna328p
    Apr 4, 2017 at 3:49
  • \$\begingroup\$ Make it a code-challenge \$\endgroup\$
    – anna328p
    Apr 4, 2017 at 3:49
  • \$\begingroup\$ This is essentially the same challenge as this one, and would be closed as a duplicate. Although it's not exactly the same, some answers to the previous question would require very little modification and answers to this question would also require very little modification to be answers to the other one. \$\endgroup\$ Apr 4, 2017 at 8:37
  • \$\begingroup\$ @Alt-F4 : it was a code challenge. \$\endgroup\$ Apr 4, 2017 at 21:52
  • \$\begingroup\$ @PeterTaylor : they were no answer to the previous question. In order to be closed as a duplicate the target needs to be already answered. You known it was closed an unclear, so please suggest change to make this answer clearer. \$\endgroup\$ Apr 4, 2017 at 21:54
  • \$\begingroup\$ Huh? It's open and has 15 answers. \$\endgroup\$ Apr 4, 2017 at 22:09
  • \$\begingroup\$ @PeterTaylor sorry, I thought to an another question that was closed as unclear and didn’t take time to read your link. In that case NO, the aim is to not use the compiler in order to actually build the file. This normally can’t be done with a compiler or an assembler. \$\endgroup\$ Apr 4, 2017 at 22:16
  • \$\begingroup\$ Can't it? Why not? \$\endgroup\$
    – wizzwizz4
    Dec 16, 2017 at 19:55
  • \$\begingroup\$ Wait... shortest code that generate any program? Or what? Don't think this is a good idea... \$\endgroup\$
    – DELETE_ME
    Jan 6, 2018 at 12:10
-1
\$\begingroup\$

Removing a Letter adds a Letter

Your program should output nothing when unaltered, however, when any single character is removed it should have an output length of 1. This extends to any number of characters being removed from the program, as long as there is, at minimum, a single character remaining.


For example, if my program were abcdefg, it should output nothing if unaltered.

However, if I were to remove a and d from this program to get bcefg, it should output any two printable characters that represent 16 bytes of information (2 characters for 2 characters removed).

  • So if bcefg outputs (00,AA,etc...) this is valid.

Taking this further, if we were to remove all but the letter g we'd need an output of 6 characters.

  • So if g outputs ('000000','@$^%@(',etc...) this is valid.

Your program must function for all possible combinations of removals that are possible, that is to say each single letter in your program should be a valid program.


Rules

  • You may "lock" pieces of the code, each locked byte counts for 2-bytes instead of 1-byte.
    • Locked bytes will never be removed.
    • For instance, if my program was abcdefg and bcd is locked, the shortest program we'll get is abcd,bcde,bcdf and bcdg.
    • If bcd was locked in abcdefg it'd be 10 bytes, not 7.
  • The program may output any byte to represent 1 removed character, N-bytes for N removed chars in the code itself.
\$\endgroup\$
4
  • \$\begingroup\$ The rule only leads to totally locked code \$\endgroup\$
    – l4m2
    Mar 13, 2018 at 0:13
  • \$\begingroup\$ @l4m2 hah. I disagree. \$\endgroup\$ Mar 13, 2018 at 0:58
  • \$\begingroup\$ But more constructively, increase the penalty? Limit locked chars? \$\endgroup\$ Mar 13, 2018 at 1:04
  • \$\begingroup\$ Maybe require an unlocked percent? \$\endgroup\$
    – l4m2
    Apr 6, 2018 at 10:52
-1
\$\begingroup\$

Sandbox:

Is this question already available (duplicate)?

Are things too vague?

Does providing the example help or hinder?

Tidy the Pantry (easy)

I hate grocery shopping, particularly the part where I put groceries away--so I'm calling upon the collective hive-mind to handle that.

Challenge

Your challenge is to take a 1D-list of groceries and a 2D pantry as input; and output an newly assorted pantry. The two variables can be of your type choice, and in any order, but please specify what item types your program requires (e.g. string, array, etc.).

Rules & Additional info.

Scoring

  • This is code golf, so the shortest answer in bytes wins

Rules

  • The pantry should be ordered alphabetically (A - Z, left to right, top to bottom)
    • For simplicity, the pantry is case-insensitive
  • The pantry must retain its horizontal size (but trailing newlines are optional)
  • "Pockets" (empty spaces) should be filled between items (i.e. only the last item is allowed to have a trailing pocket)
  • If the pantry is too small for the incoming groceries, then the pantry must replace older items (Z being the oldest, A the youngest)
    • Z from groceries is younger than A in pantry
  • Standard loopholes are forbidden

Examples ([ and ] are used for readability)

Input (4x4 pantry):

[A][A][ ][ ]
[ ][ ][B][ ]
[C][ ][ ][ ]
[ ][ ][ ][D]

AAD

Output:

[A][A][A][A]
[B][C][D][D]
[ ][ ][ ][ ]
[ ][ ][ ][ ]

Input (2x2 pantry):

[A][B]
[C][D]

XYZ

Output:

[A][X]
[Y][Z]

Example solution

JavaScript ES6 (989 bytes)

// (String, String) -> String
let organise = (pantry, groceries) => {
  let n = pantry.split("\n").sort((a, b) => b.length - a.length); // used at the end of the function for horizontal sizing
  n = n[0].length;

  pantry = pantry
    .replace(/\W/g, "") // get rid of all non-alphanumeric characters
    .split("");         // turn the string into an array

  // we need the properties of the new array
  // so the extra `pantry = pantry` is needed
  pantry = pantry
    .slice(0, pantry.length - groceries.length) // go ahead and remove the last overlapping elements
    .concat(groceries)                          // add the groceries to the pantry
    .join("")                                   // turn into a string
    .split("")                                  // turn into an array
    .sort()                                     // sort the array
    .join("");                                  // turn into a string

    return pantry.replace(RegExp(`(.{${n}})`, 'g'), "$1\n");
};

/** Testing below **/

console.log("Test #2:\n" + organise(
`AJCHDJE
JJ   JA
    ASD
OOQ I U
Q     W
      R`,

'AHJBCJHDHHATTGEH'
))


Test Cases:

Test #1, 4x4 pantry

TVCX <- pantry
ABCD
ATDJ
UAIK

XYXY <- groceries
----
AAAB <- expected output
CCDD
IJKT
XYXY

Test #2, 7x6 pantry

AJCHDJE
JJ   JA
    ASD
OOQ I U
Q     W
      R

AHJBCJHDHHATTGEH
-------
AAAAABC
CDDDEGH
HHHHJJT
T

Test #3, 10x10 pantry

AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA

ZZZZZZZZZZZZZZZZZZZZ
----------
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
ZZZZZZZZZZ
ZZZZZZZZZZ

Test #4, 16x16 pantry pantry

ASDFGHJKLZXCVBNM
QJKAJ  KAKSJD  J
KJASDKFHI YOIER
W   OSDOFJ    DK
E PPPASP     AS
R
TASD 
YAAAAAAAAAAAA
U          JHOLK
IIAUSHODUYOAISUO
OASD  AUSODI 
PIASND JUASJNOIJ
A ASJDH PPOIO 
QHIAIUSOIUOOO
WYYAIUSNNAJSDASD
EAISDUUIOPJPIJPJ
ROQPEWIHRNXCAISD

QWERTYUIOP
----------------
AAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAA
ABCCDDDDDDDDDDDD
DDDEEEEEFFFGHHHH
HHHIIIIIIIIIIIII
IIIIIIJJJJJJJJJJ
JJJJJJKKKKKKKKLL
MNNNNNNOOOOOOOOO
OOOOOOOOOOPPPPPP
PPPPPPQQQQRRRRRS
SSSSSSSSSSSSSSSS
SSSTTUUUUUUUUUUU
UVWWY

Test #5, 2x2 pantry

HE
LO

[no groceries]
--
HE
LO
\$\endgroup\$
6
  • 1
    \$\begingroup\$ why divide the program score? \$\endgroup\$
    – RedClover
    Feb 26, 2018 at 19:03
  • 1
    \$\begingroup\$ I recommend you do count by bytes otherwise someone is just going to encode their entire program in Chinese characters and win. \$\endgroup\$
    – hyper-neutrino Mod
    Feb 26, 2018 at 19:09
  • \$\begingroup\$ @labela--gotoa To get a golfed score (smaller programs get a smaller score), should I change it? \$\endgroup\$ Feb 26, 2018 at 19:13
  • \$\begingroup\$ @EphellonDantzler I don't understand why not just normal scoring...? \$\endgroup\$
    – RedClover
    Feb 26, 2018 at 19:14
  • \$\begingroup\$ LOL, that's why I set in in Sandbox first @labela--gotoa \$\endgroup\$ Feb 26, 2018 at 19:16
  • 1
    \$\begingroup\$ Some notes on your reference implementation: 1 It appears far too soon in the challenge. 2 It's not 1768 bytes. 3 You need to ungolf it and make it readable or it's not much use. 4 As it's JS, create a Snippet for it. 5 Is it necessary? It seems to be thrown in there to try to patch over any holes in the challenge spec. \$\endgroup\$
    – Shaggy
    Feb 26, 2018 at 23:17
-1
\$\begingroup\$

Interpret pseudocode

Wikipedia says pseudocode

is intended for human reading rather than machine reading.

and

A program in pseudocode is not an executable program.

I don't care.

Make a pseudocode interpreter that can run pseudocode that fits the rules described below*. This is based on the IB pseudocode guide, but it is simplified quite a bit to make it fit for the challenge.


Pseudocode specifications

This is a simplified pseudocode to make the challenge less tedious. The pseudocode language has no strings, no arrays, no classes, no methods, and no variables other than integers.

Basic syntax

Comments that start at // and end at a newline (like java one-line comments). // is not necessarily followed by a space, and the comment may be empty. Example:

A = 2 + 3 // I can't write five because my keyboard is broken

Statements are separated by newlines. Lines may be empty (without statements). The exact number of spaces doesn't matter, and spaces are not required. The language is case sensitive.

Variables

All variables are global, and can be accessed anywhere. They do not need to be declared. To keep things simple, all variables can be assumed to be integers. All variable names are UPPERCASE, and consist only of letters. Your program should at least handle integers from -256 to 256. A wider range is not a requirement.

Variables are assigned values using this syntax:

VARIABLE = Expression

Where VARIABLE can be any uppercase name and expression can be any integer expression, as discussed below.

Examples:

A = 5
B = A + 3
NUMBER = A * B

Expressions

An expression can be:

  • An integer, like 42
  • A variable, like NUMBER
  • A binary operation on two other expressions, like NUMBER + 5. There are only four operations: +, -, *, /. Division rounds integers down.

Expressions can be surrounded by parentheses to indicate that they need to be evaluated first. To keep things simple, all expressions are evaluated from left to right no matter what the operations are (unless there are parentheses that specify otherwise), so

A = 2 - RM * 9 + 3 / NUMBER
B = 1 + 2 * (3 - 4) / 6

is equivalent to

A = (((2 - RM) * 9) + 3) / NUMBER
B = ((1 + 2) * (3 - 4)) / 6

Boolean expressions

Boolean expressions can compare two expressions using == (equality), != (not equal to), < (less than), and > (greater than). They are only used for control flow, as discussed below (there are no boolean variables).

Control flow

There are four types of control flow. They can be infinitely nested in all combinations.

If

if (booleanExpression) then
    // statements (discussed below)
endif

If-else

if (booleanExpression) then
    // statements (discussed below)
else
    // other statements
endif

Loop while

loop while (booleanExpression)
    // do stuff
endloop

Where booleanExpressions are boolean expressions. The ifs work the same as in normal programming languages. The while loop is a simple while loop.

The booleanExpressions will always be surrounded by (). The pseudocode is very flexible with spaces, and any number of spaces is valid.

Loop for

loop VARIABLE from Expression1 to Expression2
    // things to do over and over again
end loop

Where Expression1 and Expression2 are expressions that are evaluated before the loop begins and their values are stored until the loop finishes. The content of the loop is executed for every integer from the result of Expression1 to that of Expression1, inclusive. At every iteration, the index variable (VARIABLE in this case) is updated.

Example:

loop I from 3 to 5
    output(I)
endloop

Outputs:

3
4
5

Statements

Output

output(Expression) outputs the evaluated expression. It's like println in programming languages. So:

output(1+1)

prints 2, followed by a newline.

output() with no arguments should print a newline.

Other statements

If the interpreter encounters any other statement that looks like a method call with no arguments, it should pretend it's executing it. For example,

lightsoff()
gohome()

should print (together with a newline):

executing lightsoff
executing gohome

In other words, executing [Method name] should be printed. All statements will be lowercase and will consist entirely of letters.

Keywords cannot be statements. You do not have to deal with the following (it will not appear in the pseudocode): - if() - endif() - loop() - while() - etc.

However, statements that start with keywords are valid. For example, loophole() should print executing loophole, even though loop() itself is not valid.


Challenge rules

  • Your program should take a string as input. It can also take something equivalent, like an array of characters. But you can't take an array of strings; your program must itself separate the lines and tokens. You can also take a file as input.
  • Your program should print the output of the pseudocode in any reasonable form.
  • No standard loopholes.
  • There are no restrictions on what your program should do when given invalid pseudocode.
  • This is code golf. The shortest code in bytes wins.

Example output

1

A = 3
output(A) // prints 3
B = 4 + A * 2
output(B)
helloworld()
output(A + B + 1 * 3)

Should give:

3
14
executing helloworld
54

2

loop NUM from 2 to 20 // cycle through possible prime numbers
    COUNT = 0
    loop DIV from 2 to NUM // cycle through possible divisors
        if(NUM/DIV*DIV == NUM) then // if the number is exactly divisible
            COUNT = COUNT + 1
        endif
    endloop
    if (COUNT == 2) then // if number is prime
        output(NUM)
    endif
endloop

Should give:

2
3
5
7
11
13
17
19

3

Tricky cases that your interpreter should handle:

// empty comment:
//
// empty line:

    // more comment testing // ///
////

if     (3<4) then
    endoftheworld() // a statement
    ifff()
    endifnot()
    // endif in a comment doesn't count
endif
// loops can be empty:
loop I from 0 to 10
endloop
output(I) // variables are global
if(1<2)
    if(3<4) // nesting is ok
        ok()
    endif
endif
// spacing doesn't matter:
output   (2+   8   - 1   )
loop             while(2<1)
    neverhappened()
endloop

Should output:

executing endoftheworld
executing ifff
executing endifnot
10
excecuting ok
9

*Technically, once pseudocode follows rules as strict as those described here, it is arguably not pseudocode anymore. Wikipedia says it's called skeleton code.


Any suggestions?

I double-checked all the specifications, but if anything seems reasonably unclear, please let me know.

\$\endgroup\$
4
  • \$\begingroup\$ Actually that's because the challenge is uninteresting. \$\endgroup\$
    – Xwtek
    May 3, 2018 at 2:11
  • \$\begingroup\$ @Akangka thanks for the feedback. How do you think it could be made more interesting? \$\endgroup\$ May 3, 2018 at 16:47
  • \$\begingroup\$ Unfortunately, there is nothing to improve. You have to find other challenge. Also, it is not pseudo-code. \$\endgroup\$
    – Xwtek
    May 4, 2018 at 3:03
  • \$\begingroup\$ @Ok, thanks. I'll try to think of something. Also, read the *note. :) \$\endgroup\$ May 5, 2018 at 19:39
-1
\$\begingroup\$

Common Logic Gates

Given positive integer n, make a common n-to-1 gate with fewest input, i.e. make a function f: {0,1}k ↦ {0,1} with smallest k that, for each function g: {0,1}n ↦ {0,1}, there exists {ak}, such that each element ai in the sequence map to one of 0, 1, x1, x2, x3, ..., xn, satisfying that, for each {xn}, g(x1, x2, x3, ..., xn) = f(a1, a2, a3, ..., an).

Samples:

To make a common 1-to-1 gate, your circuit must take at least 2 input:

f(A,B) = A XOR B

For a buffer gate (g = x1 ↦ x1), let A=0 and B=Input (a1 = 0, a2 = x1); for a not gate (g = x1 ↦ ¬x1) , let A=1 and B=Input (a1 = 1, a2 = x1).

Alternatively, you can use f(A,B) = A AND NOT B. For a buffer gate, let B=0 and A=Input; for a not gate, let A=1 and B=Input.

To make a common 2-to-1 gate, the circuit must take at least 4 input bits: (The two inputs are represented as a and b)

f(A,B,C,D) = ((A AND B) OR (C AND NOT B)) XOR D

(ab)
00 01 10 11 A B C D
0  0  0  1  a b 0 0
0  0  1  0  0 b a 0
0  1  1  0  a a a b
0  1  1  1  1 b a 0
1  0  0  0  1 b a 1
1  0  0  1  0 a 1 b
1  1  0  1  0 b a 1
1  1  1  0  a b 0 1

Output can be an boolean expression with reasonable logic gates, or just the output corresponding to all possible input of the n-to-1 function f (the truth table of f). If there are more than one possible functions, you can output any of them.

Shortest code in bytes win.

Code that matches the requirement:

function solve(n) { // n positive int
    var res = [], tmp=[], inmap=[], need=[];
    for (var i=1; ; i++) {
        for (var _res=0; _res<2**(2**i); _res++) {
            var valid = 1;
            for (var j=0; j<2**i; j++)
                tmp[j] = Math.floor(_res/2**j)%2;
            for (var _need=0; _need<2**(2**n); _need++) {
                for (var j=0; j<2**n; j++) 
                    need[j] = Math.floor(_need/2**j)%2;
                var valid2 = 0;
                for (var _inmap=0; _inmap<(n+2)**i; _inmap++) {
                    var valid3 = 1;
                    for (var j=0; j<i; j++) 
                        inmap[j] = Math.floor(_inmap/(n+2)**j)%(n+2) - 1;
                    for (var j=0; j<2**n; j++) {
                        var bits = 0;
                        for (var k=0; k<i; k++) {
                            if (inmap[k]==-1 || (inmap[k] && (j>>(inmap[k]-1))%2))
                                bits |= 1 << k;
                        }
                        if (tmp[bits] != need[j]) 
                            valid3 = 0;
                    }
                    valid2 |= valid3;
                }
                if (!valid2) valid = 0;
            }
            if (valid) 
                res.push (tmp.slice());
        }
        if (res.length) 
            return res[AnyNonNegativeIntegerLessThan(res.length)];
        // binary index input
    }
}

function AnyNonNegativeIntegerLessThan(x) { if(R>=x) throw ("end"); return R;}
for (R=0; ; R++) { console.log (solve(1)); }

\$\endgroup\$
19
  • \$\begingroup\$ You don't define what an n-to-1 gate is anywhere in your question. \$\endgroup\$
    – Wheat Wizard Mod
    Mar 27, 2018 at 1:00
  • \$\begingroup\$ @user202729 @user56656 n-to-1 gate means a gate with n input and 1 output. common n-to-1 logic gate mean a logic gate that can be used to replace any n-to-1 gate with some proper wiring. You can treat a logic gate as a ROM(so you can decide for each input what the output is) \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 1:15
  • \$\begingroup\$ Output gates or ROM \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 1:25
  • \$\begingroup\$ You should put the definitions in the challenge. "that can be used to replace any n-to-1 gate with some proper wiring" is still not very clear, you should define more carefully what you mean by proper wiring. \$\endgroup\$
    – Wheat Wizard Mod
    Mar 27, 2018 at 3:22
  • \$\begingroup\$ I assume you mean functions g: {0,1}^n -> {0,1}, right? Why do you specify x_0 and x_-1? Shouldn't x just be a vector with indices 1,2,3,...,n? \$\endgroup\$
    – flawr
    Mar 27, 2018 at 14:07
  • \$\begingroup\$ Is {a_k} just a subset of {1,2,3,...,n}? Or can we have a_1=a_2=a_3=1 for example? \$\endgroup\$
    – flawr
    Mar 27, 2018 at 14:09
  • \$\begingroup\$ {a_k} seems not a multiset. It should be an array or say a sequence of numbers \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 14:43
  • \$\begingroup\$ So you're asking for something which outputs answers to codegolf.stackexchange.com/q/24983/194 ? \$\endgroup\$ Mar 28, 2018 at 11:33
  • \$\begingroup\$ @PeterTaylor No. it requires to use NAND gate to make up one circult that do the thing. Also 24983 is a 1-of-4 (74LS153), not a 4-to-1 gate common 2-to-1 \$\endgroup\$
    – l4m2
    Mar 28, 2018 at 12:41
  • \$\begingroup\$ (+) Any reason for downvoting? Downvoting in the sandbox indicates that the challenge is incomplete, if you don't leave a comment the OP can't know what is wrong. \$\endgroup\$
    – DELETE_ME
    Mar 29, 2018 at 4:48
  • \$\begingroup\$ @user202729, there are already comments indicating that this question is going to attract close votes as unclear if it's posted to main in the current state. \$\endgroup\$ Mar 29, 2018 at 10:59
  • \$\begingroup\$ @user56656 Are the issues fixed now? \$\endgroup\$
    – DELETE_ME
    Mar 31, 2018 at 15:16
  • \$\begingroup\$ @flawr Are the issues fixed now? \$\endgroup\$
    – DELETE_ME
    Mar 31, 2018 at 15:16
  • 1
    \$\begingroup\$ No I still think the explanation is quite bad and the notation is not very clear \$\endgroup\$
    – flawr
    Mar 31, 2018 at 16:15
  • \$\begingroup\$ A reference implementation is no substitute for a clear specification. The first paragraph is where you need to focus your efforts. \$\endgroup\$ Mar 31, 2018 at 19:32
-1
\$\begingroup\$

Is the program 32 or 64 bits?

Assignment is simple to explain: write the shortest code you need to determine whether an executable binary program supplied as parameter is 32 or 64 bits.

If there is a different kind of bitness, you can also do for it, but is not mandatory.

What I really don't want is telling me you support other bitnesses and after I get 32 or 64 as a result.

Valid outputs for 32:

32
32bit
32bits
32 bit
32 bits

The same pattern for 64.

No accepted answer.

\$\endgroup\$
12
  • \$\begingroup\$ I think you're missing a word somewhere in the region of "determine supplied" \$\endgroup\$ Apr 4, 2018 at 19:43
  • \$\begingroup\$ @KamilDrakari thanks. \$\endgroup\$
    – sergiol
    Apr 4, 2018 at 19:53
  • \$\begingroup\$ Executable on Windows or Linux machine? What if (... maybe ...) the program is a valid executable for both "bitness" but do different things? \$\endgroup\$
    – DELETE_ME
    Apr 5, 2018 at 1:30
  • \$\begingroup\$ Of the output formats you allow, I think the first one will result in the shortest code in every single language. Because of this, you might as well just specify that the output should be the number 32 or the number 64. \$\endgroup\$
    – N. Virgo
    Apr 5, 2018 at 8:03
  • \$\begingroup\$ This made me wonder what to do about shell scripts, which are executable programs, but require another file to interpret them and as such aren't 32-bit or 64-bit per se. Maybe it would be best to specify "executable binary file" to not have to deal with that mess. \$\endgroup\$
    – Angs
    Apr 5, 2018 at 11:22
  • \$\begingroup\$ @Angs: Thanks. Changed. \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:27
  • \$\begingroup\$ @user202729: I don't care. Windows, Linux, Mac, whatever, ... \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:28
  • \$\begingroup\$ @Nathaniel: It is intentional. If you have a language feature called bitness(program) returning 32bits you do not need to waste more bytes removing the bits part! \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:30
  • \$\begingroup\$ The word "challenge" is not really true, at least for ELF. It's absolutely trivial. \$\endgroup\$ Apr 6, 2018 at 20:20
  • \$\begingroup\$ @PeterTaylor : Changed, thanks. \$\endgroup\$
    – sergiol
    Apr 6, 2018 at 21:20
  • \$\begingroup\$ The real "challenge" is to know the executable file format, so this becomes more of a puzzle than a challenge. And for puzzles, people can just copy others' solution and port to other languages. // Consider having some popular file format in the challenge itself so people don't have to look up them? \$\endgroup\$
    – DELETE_ME
    Apr 7, 2018 at 11:19
  • \$\begingroup\$ @user202729: My initial idea was to ask only for Windows .exe files but I changed my mind because it was too limiting. Without such restrictions the question becomes multi-platform. \$\endgroup\$
    – sergiol
    Apr 7, 2018 at 11:38
-1
\$\begingroup\$

The challenge

  • Write a Discord bot with a single command, !oldest, that gives the oldest user in the server that the command that was run in.

  • Gracefully failing in DM channels is not required.

  • Assume the bot's token is this invalid token: MjM4NDk0NzU2NTIxMzc3Nzky.CunGFQ.wUILz7z6HoJzVeq6pyHPmVgQgV4.
    If the token is compressed in the program, provide instructions on how to change it so I can test it.

Sample discord.py implementation

import discord
client = discord.Client()
@client.event
async def on_message(M):
 if(M.content=="!oldest"):
  N=sorted([x.id for x in M.server.members])[1]
  await client.send_message(M.channel, str(M.server.get_member(N)))
client.run("MjM4NDk0NzU2NTIxMzc3Nzky.CunGFQ.wUILz7z6HoJzVeq6pyHPmVgQgV4")
  1. Get a list of every user in the server
  2. Sort their snowflake IDs
  3. Print the username and discriminator of the member with the smallest ID.

No API for your language? Have fun.

Standard loopholes forbidden, etc, etc.

Shortest code in bytes wins.


Sandbox

I originally posted this question on the main site, but I deleted it, as it turns out I'm bad at writing these. Please forgive me.

\$\endgroup\$
4
  • 1
    \$\begingroup\$ I'm sure I've seen this already, but with comments saying that it needed a lot more information to be self-contained. It still needs a lot more information to be self-contained. \$\endgroup\$ May 5, 2018 at 11:11
  • \$\begingroup\$ Yep. I've edited the question to clarify. \$\endgroup\$ May 5, 2018 at 12:35
  • 2
    \$\begingroup\$ Are you talking about discord servers? Other than form the example this is not clear at all. What is a DM channel? What is a token in this context? \$\endgroup\$
    – flawr
    May 5, 2018 at 13:02
  • \$\begingroup\$ A: Clarify that you're talking about Discord B: When you make a challenge that requires a library does that mean I can use a library that conveniently has the command you're asking of? \$\endgroup\$
    – IQuick 143
    May 6, 2018 at 2:12
-1
\$\begingroup\$

Divide two strings


One day, I saw the challenge to multiply two strings and I thought I might be able to do one better.

That challenge was fake. It was elementwise maximum. It was not real multiplication. So I set out to make something real. Real division between two strings.

I quickly realized that this would make an amazing challenge, as the algorithm was surprisingly complex and interesting to implement.

I then realized that it was actually easily reduced into a mere few operations. I'm still doing the challenge, though.

Enough with the backstory. Let's go.

Method

To divide two strings, do the following, where x is the first string and y the second:

  • If x does not contain y, return a space and a period concatenated to x.
    • For example, testx and blah would become .textx, with a space at the beginning.
  • Otherwise, return every occurrence of y in x, a period, then y divided by x with every occurrence of y removed, with all the periods removed.
    • For example, eestestst and est would become estest.est.

Challenge

Write a program or function that, given two strings via standard input, returns the first string divided by the second.

You may assume that neither input string contains a space, newline or period, and that the operation does not require more than 10 layers of recursion.

Test cases

test, es => es. es
test, blah =>  .test
okayye, y => yy. y
testes, es => eses. es
battat, at => atat. at
see, es =>  .see
see, e => ee. e
same, same => same. 
aabb, ab => ab.ab 
eestestst, est => estest.est
aheahahe, aheah => aheah.aheah ah

Scoring

As this is , the submission with the least amount of bytes wins.

Sandbox questions

  • Is this a duplicate?
  • Have I missed anything?
  • Does anything need further explaining?
  • Is there an issue with the concept of the challenge?
\$\endgroup\$
9
  • \$\begingroup\$ What for aabb / ab? \$\endgroup\$
    – l4m2
    Jun 1, 2018 at 12:42
  • \$\begingroup\$ okayye, y => yy. okay typo? \$\endgroup\$
    – l4m2
    Jun 1, 2018 at 12:42
  • \$\begingroup\$ The test case battat, at => atat. by seems like it should be battat, at => atat. bt instead. \$\endgroup\$ Jun 1, 2018 at 13:47
  • 1
    \$\begingroup\$ It seems odd to me that when no characters are matched the output format is {matched characters (empty)}<space>.{unmatched characters} while the format when there are matches becomes {matched characters}.<space>{unmatched characters}. I would much rather see consistent ordering of the . and <space> \$\endgroup\$ Jun 1, 2018 at 13:50
  • \$\begingroup\$ @KamilDrakari 2 / 4 is 0.5, not .05, when 4 is not contained within 2 at all. Thus it makes no sense for test / blah to be . test when blah is not contained within test. We treat a space essentially like a zero would be with normal numbers. \$\endgroup\$
    – LyricLy
    Jun 1, 2018 at 22:15
  • 1
    \$\begingroup\$ @LyricLy 6/4 is 1.5 not 1.05. If you're treating space as 0 then there shouldn't be any space after the dot in any of the test cases. \$\endgroup\$ Jun 1, 2018 at 22:58
  • \$\begingroup\$ @KamilDrakari Actually, you're right. I was entirely mistaken because you get a fraction from 1 / remainder, not original number / remainder. Meaning this entire thing is wrong and I need to figure out a good replacement for 1 in string form. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 3:32
  • \$\begingroup\$ Fixed the issues. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 3:50
  • \$\begingroup\$ I accept downvotes, but I'd appreciate suggestions on how to improve the idea, or at least an explanation of what's wrong with it, so I know why I shouldn't post it. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 8:18
-1
\$\begingroup\$

Introduction

I recently came across an oral exam where the candidates were asked to find a logical circuit than can negate 3 inputs A,B,C using only two NOT gates.

The question also specified that such a circuit is unique up to removal of useless gates and reordering inputs/outputs. The candidates were asked to prove this assertion by writing a piece of code that generates all such circuits.

Challenge

No inputs whatsoever are given.

The program must output all logical circuits using unlimited AND and OR gates but only two NOT gates which take in three inputs which map to three outputs. The outputs should be the negation of each input.

The outputted circuits should not have any redundant/trivial gates (gates that always output the same thing) or unused gates (whose output doesn't influence the outcome).

The program should use as little precalculated data as possible.

Output format is left up to the coders.

The winner will be determined by overall simplicity -- low run time and code elegance. It is not an objective criterion.

Example Input and Output

Input:

N/A

Output:

R    = (A & B) | (A & C) | (B & C)
notR = !R
S    = (notR & (A | B | C)) | (A & B & C)
notS = !S

notA = (notR & notS) | (notR & S & (B | C)) | (R & notS & (B & C))
notB = (notR & notS) | (notR & S & (A | C)) | (R & notS & (A & C))
notC = (notR & notS) | (notR & S & (A | B)) | (R & notS & (A & B))
\$\endgroup\$
2
  • \$\begingroup\$ Example output and proof of existence are provided here \$\endgroup\$
    – John Do
    Jun 17, 2018 at 9:22
  • 1
    \$\begingroup\$ "It is not an objective criterion." Then it is not an on-topic question. \$\endgroup\$ Jun 19, 2018 at 8:49
-1
\$\begingroup\$

Two functions with same input/output, with largest difference in bytes.

This challenge is a terrible idea. Don't try submitting it or anything similar!

Provide two functions with the largest difference in bytes. (These two functions will be referred to in bold italics to distinguish them from built-in functions available in your language in the rules below.)

Rules:

  1. Both functions must take an input and must produce an output. The input to and output from both functions must be identical.

  2. Both functions must be explicitly named. The function names must have the same byte count.

  3. You may not define any other functions.

  4. If you use a built-in function your language provides, it must be used with the same number of parameters in each of the functions.

  5. You may use string/numeric literals or any built-in constants, but you must use exactly the same ones in both functions.

  6. You can define variables, must you must use the same variable names in both functions.

  7. You can use comments, no-ops, and the equivalent, but they must be the same in both functions.

  8. Both functions must contain the same amount of whitespace (or equivalently, don't count whitespace at all.)

  9. You can import libraries/packages and the equivalent, as long as you import the same ones for both functions.

  10. You can use pre-processor directives as long as they are the same for both functions.

If any of these rules mean your language cannot compete, so be it.

Not really sure how to tag this. A little bit of and .

\$\endgroup\$
6
  • \$\begingroup\$ I don't think this is a good idea. {Main downvote} \$\endgroup\$
    – DELETE_ME
    Jul 12, 2018 at 16:26
  • 1
    \$\begingroup\$ Give up. E.g. in APL, and ⊢⊢⊢⊢⊢⊢⊢⊢ do the same. \$\endgroup\$
    – Adám
    Jul 12, 2018 at 16:26
  • \$\begingroup\$ @Adám, with those rules, it'd be something like f←⊢ and g←⊢(⊢(⊢(⊢(...)))) due to rules #2 and #3. The same thing still applies to OP: give up! \$\endgroup\$
    – Adalynn
    Jul 12, 2018 at 16:36
  • \$\begingroup\$ Thank you. I am happy to give up! \$\endgroup\$
    – ngm
    Jul 12, 2018 at 16:56
  • \$\begingroup\$ @Zacharý I intended them to be dyadic, but whatever… \$\endgroup\$
    – Adám
    Jul 12, 2018 at 17:18
  • \$\begingroup\$ "Both functions must take an input", which I assume would restrict the functions to monadic. \$\endgroup\$
    – Adalynn
    Jul 12, 2018 at 17:39
-1
\$\begingroup\$

Quiet QR

Your mission, should you choose to accept it is to infiltrate the top secret HQ of the Big Bad Evil Guy (TM) and extract information on their latest evil scheme saved in the file Plan.txt.

The target PC is isolated from any and all network connections, and you can't physically connect anything to it. The server room is equipped with sound sensors that will detect key presses.

Your tools are restricted to a mobile phone equipped with a QR code reader. Your recommended course of action is to write a code on the target machine that will display the file content as QR code.

You are to complete the mission with the least number of keystrokes as to minimise the sound generated by the mechanical keyboard.
It is advisable not to use languages that require unicode characters as entering one character will require multiple key presses (Eg:þ = Alt+0254) is considered 5 keystrokes.

You are to assume that the machine will have its terminal open and ready for input at the root directory of the system (C:\> or /).

All programming languages can be accessed directly from root folder. The target file is on the root folder.

Javascript is available as command line executable named js usable as (js filename) and prints output.

Image viewer is called view and usable as (view imagefile) [Extension is not needed]

Possible ways of output:

  1. An image containing the QR code

  2. ASCII art depicting the QR code using characters like █ ▄▀

  3. Or any form readable by any standard-issue QR code reader

  4. Other formats of 2D barcodes are accepted on the condition of being readable by a standard reader.

Example Solution for batch file:

copy con a.bat
open file Plan.txt
echo █ ▄▀
^Z
a

=59 keystrokes.

The symbols are 4 keystrokes each:

  • ▀ Alt+991

  • █ Alt+987

  • ▄ Alt+988

^Z as Ctrl+z and is considered 2 ketstrokes (F6 is considered one).
New lines and spaces are one keystroke each.
Capital letters are 2 strokes (Shift+c).
CAPITAL words are one keystroke added to the length of the word (Shift+capital).
No need to clean the screen at the end because the evidence will be erased by a Micro-EMP device that will disable the machine.

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Why not just have a question to turn text into a QR code? The keystroke golfing just seems to complicate things \$\endgroup\$
    – Jo King Mod
    Jul 18, 2018 at 11:54
  • \$\begingroup\$ @JoKing The premise of the challenge is to extract information from a pc with the least keystrokes. \$\endgroup\$ Jul 22, 2018 at 9:06
  • \$\begingroup\$ In that case, what operating system is the PC? What type of QR code do you want (alphanumeric or byte?)? Can you add a link or explain an algorithm to generate you type of QR code (questions should be self-contained)? How big can the input be (100 bytes? 1kb?), and what characters can it contain? \$\endgroup\$
    – Jo King Mod
    Jul 22, 2018 at 9:15
  • \$\begingroup\$ You may assume that the PC have an open terminal window ready for input in whatever OS you'd want (Bash, PowerShell, Command prompt,.....) The QR code must be able to encode alphanumeric+punctuation text in the file Plan.txt \$\endgroup\$ Jul 24, 2018 at 10:29
-1
\$\begingroup\$

Projective related points

Points A, B, C, D and A′, B′, C′, D′ are related by a projective transformation if their cross ratios are equal.

Projective related points

Given A, B, C, D four ordered points on a line, their cross ratio is defined as:

\$\displaystyle\frac{distance(A,C)\times distance(B,D)}{distance(A,D)\times distance(B,C)}\$,

where \$distance(A,C)\$ is the Euclidean distance between points A and C.

Challenge

Given a set of eight points, say if yes or no the set can be splited into two subgroups (each subgroup with four points) where the two subgroups are related by a projective transformation.

Input

A set of 8 points, each point defined by its Cartesian coordinates (integer coordinates).

Output

Either a specific true output (true, 1, yes, ...) or a specific false output (false, 0, no, ...).

Example

{(10,100),(25,100),(2,63),(2,33),(31,100),(2,13),(2,3),(17,100)} --> true
with subgroups:
{(10,100),(25,100),(31,100),(17,100)} 
and 
{(2,63),(2,33),(2,13),(2,3)}

{(45,54),(8,23),(8,8),(8,29),(27,30),(15,14),(9,6),(8,15)} --> true
with subgroups:
{(8,23),(8,8),(8,29),(8,15)}
and 
{(45,54),(27,30),(15,14),(9,6)}

Hint (no need to use division or square root)

In order to avoid floating points, you can use the fact that points A, B, C, D and A′, B′, C′, D′ are related by a projective transformation implies:

\$distance^2(A,C)\times distance^2(B,D)\times distance^2(A',D')\times distance^2(B',C')\$

equals

\$distance^2(A',C')\times distance^2(B',D')\times distance^2(A,D)\times distance^2(B,C)\$

Rules

  • The input and output can be given in any convenient format.
  • No need to output the two subgroups.
  • No need to handle the case when at least two points in the set are the same.
  • No need to check the fact that the four points in each subgroup are aligned.
  • In your submission, please state the true and the false values.
  • Either a full program or a function are acceptable. If a function, you can return the output rather than printing it.
  • If possible, please include a link to an on-line testing environment so other people can try out your code!
  • Standard loopholes are forbidden.
  • This is so all usual golfing rules apply, and the shortest code (in bytes) wins.
\$\endgroup\$
6
  • \$\begingroup\$ As with most problems involving floating point comparisons, I think you should include a large-ish number of test cases and require that submissions pass all of those cases. That way people can be sure their submissions are sufficiently accurate. \$\endgroup\$ Jul 13, 2018 at 20:40
  • \$\begingroup\$ @FryAmTheEggman In fact there is a way to work only with integers, I'll add a hint. \$\endgroup\$
    – mdahmoune
    Jul 16, 2018 at 10:53
  • \$\begingroup\$ I had totally missed that the input would always be integers. Cary on, but I still recommend including at least several test cases to make users more able to be sure their submission works without having to find edge cases on their own. \$\endgroup\$ Jul 16, 2018 at 14:35
  • \$\begingroup\$ @FryAmTheEggman Ok I'll add more examples. \$\endgroup\$
    – mdahmoune
    Jul 16, 2018 at 15:55
  • \$\begingroup\$ Is the cross ratio \$\overline{AC}\times\frac{\overline{BD}}{\overline{AD}}\times\overline{BC}\$ or \$\frac{\overline{AC}\times\overline{BD}}{\overline{AD}\times\overline{BC}}\$? \$\endgroup\$
    – wastl
    Jul 18, 2018 at 11:31
  • \$\begingroup\$ @wastl it's the second one, thanks for the remark, I just updated the formula. \$\endgroup\$
    – mdahmoune
    Jul 18, 2018 at 11:39
-1
\$\begingroup\$

A function to traverse an array and re-generate the same array

We take an array, then write a function that will traverse the array and generate the array in a format given in the example below.

For example, given the array:

Array

(

  [0] => Array
  ( [name] => Tom
      [age] => 32
      [key] => Array
      ( [0] => abc
          [1] => def
          [2] => efg
          )
      )
  [1] => Array
  ( [name] => Jim
      [age] => 30
      [key] => Array
      ( [0] => abc
          [1] => def
          [2] => efg
          )
      [address] => Array
      ( [0] => Array
          ( [state] => CA
              [country] => US
              )
          [1] => Array
          ( [state] => NY
              [country] => US
              )
          )
     )
)

Output should be:

User: 0
 name: Tom
 age: 32
 key:
  0: abc
  1: def
  2: efg
User: 1
 name: Jim
 age: 30
 key:
  0: abc
  1: def
  2: efg
address:
0:
 state: CA
 country: US
1:
 state: NY
 country: US

Challenge rules:

  • You can assume array can be multidimensional
  • The array can also be array of cars, schools, districts etc.
  • The preferred output is in json format
  • Indentation for the output is a simple json format

code-golf

The function will be tested with any sort of multidimensional arrays for speed of execution

\$\endgroup\$
4
  • 1
    \$\begingroup\$ Can you give a quick explanation of how you generated the array? For example, where does Name come from, and what are the rules behind indentation? \$\endgroup\$
    – Jo King Mod
    Aug 9, 2018 at 6:17
  • \$\begingroup\$ The array just contains User details which will include the Name, Age, Address etc. \$\endgroup\$
    – Mochesane
    Aug 9, 2018 at 6:45
  • 1
    \$\begingroup\$ Hi! Welcome to PPCG. We usually require challenges to be a bit more precisely defined, to avoid ambiguity. For eg., you mention " generate the array in a format given in the example below", and the rules say "the preferred output is in json format" - but the format in the example is not JSON (and has some possible issues, for eg. address not being indented). Also, the post says "array" throughout, but what you're actually working with looks like a nested hashmap/dictionary structure. \$\endgroup\$
    – Sundar R
    Aug 12, 2018 at 11:46
  • 1
    \$\begingroup\$ Finally, you've mentioned code-golf, but also that the answers will be tested for speed of execution - do you intend code-golf (number of bytes) to be the primary winning criterion and the speed of execution the tie-breaker? Or do you mean all answers have to transform a particular large input within a certain time (say 1 minute) to be valid? In the latter case, it would be useful to specify what the large, multidimensional input will be, and what the maximum time of execution allowed is. \$\endgroup\$
    – Sundar R
    Aug 12, 2018 at 11:46
-1
\$\begingroup\$

Pyramid of Bots

In this game, your bot is trying to get as high off the ground as possible. However, it can only stand on top of other bots, which are trying to get higher, too!

Overview

Your bot should be a Javascript function. It's return value should tell the program if the bot should move left, move right, or jump. Every bot starts out on a 2 dimensional grid, with a width and height set by (botCount * 2) + 1. Bots are placed on either side of the center space, and every other bot is spaced 1 apart from any other bot. They all start at y=0, and far left is x=0.

Gravity

If there is no bot on top of your bot, it can return the value jump. When a bot jumps, it moves 1 square up. If at any point in time there is nothing under the bot, it moves down 1. A bot cannot return jump if nothing is under it. If your bot is on top of another bot which moves left, your bot will fall.

Function params

Your function has 3 parameters: dirs, height, and map. The array dirs contains four boolean values, representing if there is a bot or arena border: below, to left, to right, above. The parameter height is an array with 2 elements: your height, current winner's height. The map array contains the height/width of the array, and then the amount of turns left in the game.

Running the game

In one game, the bot function will be run 800 times. Each of these is a turn. Your bot should return jump, or a direction. The bot can only move in a direction if there is no bot currently there. The two directions are left and right. Standard loopholes are not allowed (when are they ever allowed??), and the bot who wins the most out of 1000 games is the winner.

\$\endgroup\$
1
  • 2
    \$\begingroup\$ I don't see the strategy in this. There's no way for a bot to reliably move up. No bot will stand still, so you literally have to guess whether or not an adjacent bot will move under you, and then hope that they move up while other adjacent bots move under. \$\endgroup\$ Aug 27, 2018 at 16:21
-1
\$\begingroup\$

My Ribosomes Got a Firmware Upgrade


So all of the Apple iBosomes in my body have been updated to RibOS 4.0 now… while I appreciate the additional optimizations that were added, unfortunately for me they've dropped support for the legacy mRNA API.

So since my RNA Polymerase library still needs to return strings in the format AUUCGGUCAAAGU for the code still using it, I'll need to add some code to the getBasePairs() method to translate it from the new API.

Challenge

  • Your input will be a string in base64 (because codons are exactly 6 bits) representing the genome.
  • You should output a string with the equivalent RNA base pair sequence:
    • 00 becomes A.
    • 01 becomes G.
    • 10 becomes C.
    • 11 becomes U.
  • All languages are allowed.
  • Your I/O must be in these exact string formats, even if they're small enough to encode as integers.
  • The shortest answer in bytes wins.
\$\endgroup\$
4
  • \$\begingroup\$ Are you asking for a method that does a base64 to base4 conversion and pretty-prints the result? \$\endgroup\$ Sep 18, 2018 at 21:15
  • \$\begingroup\$ @JonathanFrech Kinda, I guess. \$\endgroup\$
    – Nissa
    Sep 18, 2018 at 21:17
  • \$\begingroup\$ So using lax I/O I can take the input as an integer and output four unique values like this? \$\endgroup\$ Sep 18, 2018 at 21:21
  • \$\begingroup\$ @JonathanFrech wasn't what I had in mind; I'll edit the proposal once I finish the essay I'm working on right now. \$\endgroup\$
    – Nissa
    Sep 18, 2018 at 21:26
-1
\$\begingroup\$

Trilateration

Intro:

Similar to Trilaterate your position with a small twist.

In a n x m array,

Original Problem:

You will be given a list of (x,y,d) as input, where d is the distance of your position from the point (x,y). Using this we can find our position.

................

In the above problem, d is the exact distance from the respective point.

In this problem, due to some error, we know that the distance is actually the maximum distance from the respective point. Because of that, instead of a single point, we will get a small area of our position. Objective is to get that area.

It should be in the format(a function):

f(list,n,m):
  #your code here
  return #list of all indices where you may be.

What's returning should be a list of points (x,y) with 0<=x<=n,0<=y<=m.

In case there is no solution return an empty list. The winner will be the fastest code. In case of a tie shorter code wins. The time taken will most likely depend on n,m and list of points.

\$\endgroup\$
2
  • \$\begingroup\$ On which test(s) will the code be measured? \$\endgroup\$
    – DELETE_ME
    Sep 26, 2018 at 15:14
  • \$\begingroup\$ Edited it.. Also, what are the tags I should add other then fastest-algorithm \$\endgroup\$ Sep 27, 2018 at 10:54
-1
\$\begingroup\$

The goal of this challenge is to make an interpreted language that can print anything! The format of the language needs to be

[command eg: print] [args];

You have to use regex, even though it is not the typical way to write a language, to avoid people finding loopholes. Your interpreter also needs to ask for a file to open to interpret; example input file prompt:"File to interpret: "

Some tests to try:

print Hello World;


print This is a very very very very very long test;

ktrgjkfgjk;

print hi

If your interpreter runs these tests correctly, you can submit your interpreter.

Notes:

Do not just cut off the print!

If the command given does not exist, or if semicolon not present, print "Error"

This is so the lowest byte count + working code wins!

\$\endgroup\$
16
  • 1
    \$\begingroup\$ I recommend some more explanation of the "File: " part \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:06
  • \$\begingroup\$ @trichoplax Thats the input file prompt \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:09
  • \$\begingroup\$ @trichoplax, well then i wont accept those answers, hold on let me edit \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:11
  • \$\begingroup\$ Read it again: it says: The format of the language needs to be [command eg: print] [args]; <--- note semicolon It was just a typo (I didnt type the ;) \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:14
  • \$\begingroup\$ The problem with saying "do not just cut off the print" is that there may be other ways of achieving the same thing, then the challenge just becomes a long list of things which are banned. You can avoid this by trying to set the requirements and inputs in a way that doesn't have these loopholes. \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:16
  • \$\begingroup\$ @trichoplax Ok i only want the print though \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:20
  • 2
    \$\begingroup\$ Writing challenges can be tricky, and people have posted advice on meta that can help: things to avoid when writing challenges and things to consider when creating a challenge \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:21
  • 1
    \$\begingroup\$ If you only want print, then is there a difference between this challenge and "remove the first 6 characters and the last character from this string"? If you don't want people to solve it that way, you could consider what they need to do when the input is not a valid print command, and specify that in that case it should do something different (like not output anything). \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:24
  • \$\begingroup\$ @trichoplax Yes, i didnt think of that \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:25
  • \$\begingroup\$ "do not just cut off the print" is an example of a non-observable requirement. Here's a good explanation of why that can be a problem \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:26
  • \$\begingroup\$ Here, new update \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:31
  • \$\begingroup\$ I hope all the comments don't put you off - writing challenges is difficult, but we get much more answers than challenges so more challenges are needed. I had lots of useful feedback from this community when I started out. \$\endgroup\$
    – trichoplax
    Oct 7, 2018 at 19:32
  • \$\begingroup\$ Is this better @trichoplax and where else can i improve \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:36
  • \$\begingroup\$ Let us continue this discussion in chat. \$\endgroup\$
    – Menotdan
    Oct 7, 2018 at 19:37
  • 1
    \$\begingroup\$ you have to use regex ... , to avoid people finding loopholes This seems very arbitrairly restricting. What about languages without regexes? You haven't actually said what the outputs of the test are. And what exactly is the program meant to have as input? I recommend a string input instead of messing around with files \$\endgroup\$
    – Jo King Mod
    Oct 8, 2018 at 12:35
-1
\$\begingroup\$

Name: Create a Programming Language

Tags: code-bowling, and cops-and-robbers

Cops:

The cops must design a programming language that takes in the contents of the program from a default I/O method, and do something.

Rules:

  • The program must not print anything to STDERR
  • The program must be able to output to STDOUT with certain program contents of your choice
  • The program must be able to calculate any function up to \$f_{\omega}(n)\$ where f is the fast-growing hierarchy. In other words, it needs to be able to evaluate any primitive-recursive statement.
  • There cannot be a way to execute commands in other languages (for example, if there is a command in your programming language that can execute Python code based on the argument, that would be cheating)

Since there are tons of loopholes, whether or not the answer is valid is up to me (and also, standard loopholes are also not allowed).

Robbers:

Your job is to make the same compiler (which does the same thing with the same commands given as the equivalent cop answer), with more characters. The programming language may be different.

Standard loopholes aren't allowed, and whether an answer is valid or not will be judged by me.

As always, since this is code-bowling, aim for the most bytes!

\$\endgroup\$
4
  • 3
    \$\begingroup\$ "whether or not the answer is valid is up to me" unfortunately, this is going to make the challenge unclear. \$\endgroup\$ Nov 6, 2018 at 20:35
  • 4
    \$\begingroup\$ I'm afraid I don't really understand the core of this challenge. The robbers have to make the compiler larger without affecting its functionality? That seems trivial to do; just add a comment or some whitespace. \$\endgroup\$
    – Dennis
    Nov 6, 2018 at 21:26
  • \$\begingroup\$ Your job is to make the same compiler ... with more characters Should this be less characters? also, shouldn't it be bytes? \$\endgroup\$
    – Jo King Mod
    Jan 29, 2019 at 5:06
  • \$\begingroup\$ @JoKing Yeah, I realized that. \$\endgroup\$
    – MilkyWay90
    Jan 29, 2019 at 12:24
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