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What is the Sandbox?

This "Sandbox" is a place where Code Golf users can get feedback on prospective challenges they wish to post to the main page. This is useful because writing a clear and fully specified challenge on the first try can be difficult. There is a much better chance of your challenge being well received if you post it in the Sandbox first.

To post to the Sandbox, scroll to the bottom of this page or click on the "Add Proposal" link below, and click "Answer This Question". Click "OK" when it asks if you really want to add another answer. Write your challenge just as you would when actually posting it. You may also add some notes about specific things you would like to clarify before posting it. Other users will help you improve your challenge by rating and discussing it. When you think your challenge is ready for the public, go ahead and post it, replace the post here with a link to the challenge and delete it.

See the Sandbox FAQ for more information on how to use the Sandbox.

The Sandbox works best if you sort posts by "active".

Add Proposal

Search the Sandbox

Browse your pending proposals

Get the Sandbox Viewer to view the sandbox more easily

To add an inline tag to a proposal use shortcut link syntax with a prefix: [tag:king-of-the-hill]

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  • \$\begingroup\$ How are tags added to questions? \$\endgroup\$ – guest271314 Jan 9 '19 at 7:51
  • \$\begingroup\$ @guest271314 You can use this markup to create a tag in a draft: [tag:code-golf] \$\endgroup\$ – DJMcMayhem Aug 29 '19 at 15:19
  • \$\begingroup\$ Why no featured anymore? Can't we have it auto-added or something? \$\endgroup\$ – S.S. Anne Sep 26 '19 at 15:57
  • 1
    \$\begingroup\$ @JL2210 We now have a permanent info box that links to the Sandbox, so the featured tag isn't necessary \$\endgroup\$ – caird coinheringaahing Sep 29 '19 at 13:43

2667 Answers 2667

1
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Can You Catch the Robber?

This is not a cops and robbers type challenge, but a code-golf challenge based on the PBS Infinite Series video Cops and Robbers Theorem.

Challenge

You will be given an undirected and connected graph. You may also assume the graph contains no self-loops; that is, the graph will not contain a vertex with an edge connecting to itself. You must determine if the graph is cop-win. That means that if a cop and robber start at any vertex, the cop will eventually land on the same vertex as the robber, with the cop and robber taking turns traversing one edge at a time, starting with the cop. Both the cop and the robber are playing optimally and have the option to not move on their turn.

If you haven't watched the video, let me explain how to simplify the problem. First, let's start with a definition. A pitfall is any vertex v whose neighbors are all a distance of 0 or 1 from a common vertex w, where v is not equal to w. To determine if a graph is cop-win, you must repeatedly remove pitfalls and the edges that connect to it until the graph is reduced to a single vertex or there are no more pitfalls to remove. If the graph can be reduced to a single vertex in this way, it is cop-win. A couple visual examples follow.

Example 1

>o---o---o
  \ / \ /
   o---o
    \ /
     o

  o---o<
 / \ /
o---o
 \ /
  o

 >o
 / \
o---o
 \ /
  o

>o---o
  \ /
   o

 >o
 /
o

o

Result: Cop-win

Example 2

  o---o---o<
 /     \   \
o---o   o---o
 \   \ /   /
  o---o---o

  o---o
 /     \
o---o   o---o
 \   \ /   /
  o---o---o<

  o---o
 /     \
o---o<  o---o
 \   \ /
  o---o

  o---o
 /     \
o       o---o<
 \     /
  o---o

  o---o
 /     \
o       o
 \     /
  o---o

Result: Not cop-win

Examples

Input: [[2,3],[2,4],[0,1,3,4,6],[0,2,5,6,8],[1,2,6,7,9],[3,8],[2,3,4,8,9,10],[4,9],[3,5,6,10],[4,6,7,10,11],[6,8,9,11],[9,10]]
Output: Truthy

Input: [[3],[4],[5],[0,5,6],[1,6],[2,3,7],[3,4,8],[5,9],[6,9,10],[7,8,11],[8],[9,12],[11]]
Output: Falsy

Input: [[1,2],[0,3],[0,3],[1,2]]
Output: Falsy

Input: [[1,2,3],[0,2,3],[0,1,3],[0,1,2]]
Output: Truthy

Rules

You may take input as an adjacency list, adjacency matrix, or list of edges, whose vertices may be 0-indexed or 1-indexed. Your output must be a truthy or falsy value. This is , so the least number of bytes in each language wins.

Notes

This is my first post; I could certainly benefit from some help in formulating and polishing my challenge. If anyone believes my language was ambiguous or contradictory to what was said in the video, please help me clarify.

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  • \$\begingroup\$ What is the input here? It looks a list of each vertex's neighbors, but could you clarify? \$\endgroup\$ – KSmarts Oct 3 '17 at 15:16
  • \$\begingroup\$ Yes that's what I was going for, an adjacency list. A map of each vertex to a list of its neighbors. \$\endgroup\$ – kamoroso94 Oct 3 '17 at 16:34
  • 2
    \$\begingroup\$ This looks like a good question: meaty enough that there's something to golf, but simple enough not to scare everyone away. What I would suggest is flexibility in the input: allow people to choose whether to take input as adjacency matrix, adjacency list in the format you've used for the test cases, or list of edges. Also, allow people to use 1-indexed vertices rather than 0-indexed if they prefer. \$\endgroup\$ – Peter Taylor Oct 10 '17 at 8:18
  • \$\begingroup\$ I definitely agree with your suggestion of input leniency. I'll update the challenge. \$\endgroup\$ – kamoroso94 Oct 12 '17 at 8:57
  • 1
    \$\begingroup\$ I'd suggest explaining what a cop-win graph is in full, including the start positions and that both players play an optimal strategy. A link to a non-video explanation would also be good for anyone who can't or doesn't want to watch a video. \$\endgroup\$ – xnor Oct 12 '17 at 21:06
  • \$\begingroup\$ Thank you for the feedback, @xnor. I've worked it into the challenge. I feel it's an improvement. I think that the visual examples take up too much vertical space, so I'm not sure if I should include them or not. \$\endgroup\$ – kamoroso94 Oct 31 '17 at 2:17
  • \$\begingroup\$ IIRC it shouldn't be "start at any vertex", but the selection of the start position is part of the game, also under condition of optimal play, with the cop selecting their position first. \$\endgroup\$ – Christian Sievers Oct 31 '17 at 13:00
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Polynomial Partition

META: Right now I'm wondering whether it would be a more interesting challenge to have two imput lists, and the program just needs to find a polynomial that separates the two lists (i.e. no connected component can contain points of both classes. Or altnernatively f(x,y)>0 for all (x,y) in list A, and f(x,y)<0 for all (x,y) in list B.

Given a finite list of at at least two points in the plane ℝ² (all points in the list are unique), your program should find a polynomial f in ℝ[x,y] whose zero locus Z(f) := {(x,y) ∊ ℝ² | f(x,y) = 0} partitions the plane such that each of the connected components of ℝ²\Z(f) contains at most one point of the input list. The goal is finding such an f of a low degree. (It does not have to be optimal.) Note that no point of the input list may be contained in Z(f).

Scoring

The score for each test cases is the degree of the polynomial that your algorithm produces. The total score is the product of the scores of the testcases.

Examples

The points {(0,0),(0,2)} can be separated by f(x,y) = y - 1 (degree 1) or f(x,y) = x² + y² - 1 (degree 2) or f(x,y) = x³ + 1 - y(degree 3) or (infinitely) many more.

The points {(1,1),(-1,1),(-1,-1),(1,-1)} can be separated by f(x,y) = xy (degree 2).

Test Battery

to be included...

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  • 1
    \$\begingroup\$ (1) I presume that the words "a different" are missing from "each of the inputs is in ^one of the connected components". (2) Is the optimal solution not going to be one of the easiest approaches? \$\endgroup\$ – Peter Taylor Nov 3 '17 at 11:44
  • \$\begingroup\$ Thanks for the feedback, I rewrote (1), regarding (2): One very easy not optimal solution would be making a a small enough circle around every point, so I guess it depends. \$\endgroup\$ – flawr Nov 3 '17 at 14:43
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Palindromic Collapse

Given a string s, traverse from left-to-right, finding the first prefix that is a palindrome. When you encounter the first prefix palindrome, remove the end-half of the palindrome. Insert it back into the original string, then restart again from the left side of the new word. Return the final result when no prefixes are palindromes.

Take for example "babble":

  • First check would be [ba]bble, which is not a palindrome, move on.
  • Second check would be [bab]ble, which is a palindrome (bab).
    1. Compress the palindrome to the first "half", [bab] becomes [ba].
    2. Reattach this in place of the original palindrome, resulting in [ba]ble
  • Next we repeat, finding [bab]le again, and resulting in [ba]le after steps 1 and 2.
  • We then iterate through the full word again, finding no palindromes, returning bale.

More Examples (worked out)

moom

[mo]om (not a palindrome)
[moo]m (nont a palindrome)
[moom] (palindrome) -> [mo]
[mo]   (not a palindrome, done).

Final returned result: mo


abalbalba

[ab]albalba (not a palindrome)
[aba]lbalba (palindrome) -> [ab]lbalba
[ab]lbalba  (not a palindrome)
[abl]balba  (not a palindrome)
[ablb]alba  (not a palindrome)
[ablba]lba  (palindrome) -> [abl]lba
[ab]llba    (not a palindrome)
[abl]lba    (not a palindrome)
[abll]ba    (not a palindrome)
[abllb]a    (not a palindrome)
[abllba]    (palindrome) -> [abl]
[ab]l       (not a palindrome)
[abl]       (not a palindrome, done)

Final returned result: abl


More 1-1 Examples

amanaplanacanalpanama -> amnaplanacanalpanama
1232132121            -> 123
1232132145            -> 12345
01001000123210        -> 01123210
01000000000000000001  -> 011
010101                -> 011
abbabababaa           -> ab
hellollehworld        -> helloworld
world                 -> world
<empty string>        -> <empty string>
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  • \$\begingroup\$ You like palindrome a lot, don't you? \$\endgroup\$ – Mr. Xcoder Nov 7 '17 at 20:00
  • \$\begingroup\$ @Mr.Xcoder in all fairness it looks like Oliver Ni likes them more. \$\endgroup\$ – Magic Octopus Urn Nov 7 '17 at 22:06
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Validate a StarCraft II Build Order

Explanation

You must decide whether the input represents a valid StarCraft II Build Order. Here is how you will decide:

  1. Start with the first word (it will be the race, Zerg, Protoss, or Terran)
  2. Set the list of valid units to just the ones from that race (explained later)
  3. Loop through the input (split by space)
    1. Check if the unit is in the list of valid items for the listed race
      • Otherwise, output Invalid item + the listed item's name
    2. Check that the player has enough supply to sustain that unit (if it's a unit) (explained later)
    3. Check that the player has the prerequisites for that item

Units and Structures

(will be listed in real question)

Example:

Terran:

  • CommandCenter 0 supply, requires SCV gives +15 supply
  • OrbitalCommand 0 supply, requires CommandCenter (consumes)

Zerg:

  • Hatchery -1 supply, requires Drone (consumes) gives +6 supply
  • Drone 1 supply, requires Hatchery
  • SpawningPool -1 supply, requires Hatchery, Drone (consumes)

Protoss:

  • Nexus 0 supply, requires Probe gives +15 supply

StarCraft II Mechanics

At the beginning of the game, the player starts with a town hall (Nexus, CommandCenter, or Hatchery + Overlord) and 12 workers (Probe, SCV, or Drone).

Supply is the maximum number of units one can have. Supply Depots, Pylons, and Overlords give more supply.

The sum of the supply of all produced units can never exceed the current supply value (we ignore Zerg hacks).

The Supply cannot exceed 200.

Input

You will receive an input in any valid way in this format:

Race <item> <item> .....

There will be at most 99 items, and they will be at most 30 chars long.

The race will be one of Zerg, Protoss, or Terran.

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Lines per file

Can't believe it was not questioned yet.

I want the shortest script you can supply to take on all files on a directory and output a list in the format

file number_of_lines

Every possibility should be accounted as a valid line terminator:

- <CR>
- <LF>
- <CR><LF>
- <LF><CR>

No winner, it is a per language basis. Still thinking if I should give some bonus for sorting by line count.

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  • \$\begingroup\$ Duplicate. Not the same but pretty much the same idea, would definitely get closed for dupeness. \$\endgroup\$ – Rɪᴋᴇʀ Nov 14 '17 at 18:58
  • \$\begingroup\$ @Riker: Counting lines requires some more effort than the file's byte size! I had even posted an answer on that question! \$\endgroup\$ – sergiol Nov 14 '17 at 21:18
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    \$\begingroup\$ It's literally just wc -l to count lines.. I'm not sure about most of the others, but I know at least my bash can be trivially modified to count lines. \$\endgroup\$ – Rɪᴋᴇʀ Nov 14 '17 at 21:33
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Prune my tree

Given a well-formed ASCII art tree and the name of a node, print or return a new, well-formed tree with that node and any children removed.

†Contains non-ASCII characters.

Example

Given this input tree:

A
├ B
├ C
│ └ D
└ E

...and the node name E, the following should be returned:

A
├ B
└ C
  └ D

Well-formed trees

Rather than an exhaustive spec, I'll define well-formedness by example:

A
├ B
├ C
├ D
│ ├ E
│ └ F
├ G
│ └ H
│   ├ I
│   │ ├ J
│   │ └ K
│   └ L
└ M
  ├ N
  │ └ O
  │   └ P
  ├ Q
  └ R

The above is the only valid way to represent this tree (rules above re: trailing spaces and newline apply here and henceforth). Note that:

  1. The tree is rendered with some strict subset of the characters , , , AZ, space, and newline.
  2. The tree has one root node (in this example A) with no characters to its left or right.
  3. Each line has exactly one node.
  4. Each and is followed by a single space (required) and node name.

Rules

  • Standard loopholes are forbidden.
  • This is an challenge; input and output must be a string or array of lines or equivalent, per standard rules.
  • Trailing spaces and/or a single trailing newline are allowed in both input and output.
  • You may use any character encoding, as long your solution prints or returns characters equivalent to , , and . (ASCII characters like +, | (pipe) and L (capital "l") are not equivalent.)

    See also "Freebies" under "Scoring" below.

Input

  • The input tree will have at least one node.
  • The given named node may or may not exist in the tree. If it does not exist, the original tree should be returned.
  • Each node name will be a single character between A and Z inclusive. Node names will be unique and there will be no more than 26 nodes.
  • Node names are not guaranteed to be contiguous nor in any particular order, e.g. the following is possible input:

    Q
    └ D
    

Output

  • The output tree may have zero nodes.
  • The order of the remaining nodes in the output tree must be the same as the input tree.

Scoring

This is . The shortest solution in bytes wins.

🌟Freebies🌟: If the literal characters , , or appear in your source code, you may count them as one byte each, per occurrence.

Test cases

I'll reuse a few trees for multiple test cases.

  1. Input tree:

    A
    
    • Output if A removed:

      
      
    • Output if B removed (B doesn't exist):

      A
      
  2. Input tree:

    A
    ├ B
    ├ C
    │ └ D
    └ E
    
    • Output if C removed:

      A
      ├ B
      └ E
      
    • Output if D removed:

      A
      ├ B
      ├ C
      └ E
      
    • Output if E removed:

      A
      ├ B
      └ C
        └ D
      
  3. Input tree:

    A
    ├ B
    ├ C
    ├ D
    │ ├ E
    │ └ F
    ├ G
    │ └ H
    │   ├ I
    │   │ ├ J
    │   │ └ K
    │   └ L
    └ M
      ├ N
      │ └ O
      │   └ P
      ├ Q
      └ R
    
    • Output if H removed:

      A
      ├ B
      ├ C
      ├ D
      │ ├ E
      │ └ F
      ├ G
      └ M
        ├ N
        │ └ O
        │   └ P
        ├ Q
        └ R
      
    • Output if L removed:

      A
      ├ B
      ├ C
      ├ D
      │ ├ E
      │ └ F
      ├ G
      │ └ H
      │   └ I
      │     ├ J
      │     └ K
      └ M
        ├ N
        │ └ O
        │   └ P
        ├ Q
        └ R
      
    • Output if M removed:

      A
      ├ B
      ├ C
      ├ D
      │ ├ E
      │ └ F
      └ G
        └ H
          ├ I
          │ ├ J
          │ └ K
          └ L
      

Questions for sandbox:

  1. Enough/too many/missing test cases?
  2. Enough/too many/missing details re: input/output?
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  • \$\begingroup\$ I would just make this an (actual) ASCII-art challenge. Up to you but meh \$\endgroup\$ – HyperNeutrino Nov 13 '17 at 19:24
  • \$\begingroup\$ Given the proximity to Christmas, you could go for "trim the tree" as the title. \$\endgroup\$ – Nissa Nov 13 '17 at 21:47
  • \$\begingroup\$ I think you should show the larger test case(s) with A removed. I know/guess it will be an empty output, but still, it's a corner case that will benefit from being properly shown. \$\endgroup\$ – Stewie Griffin Nov 15 '17 at 12:24
  • \$\begingroup\$ I like the idea, but I too would prefer ASCII-only. Non-ascii adds a bunch of bytes without adding anything to the challenge itself. \$\endgroup\$ – Stewie Griffin Nov 15 '17 at 12:29
1
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Smallest Proth Prime Power

A Proth Prime is a prime number of the form (k*2^n)+1.

The Challenge

Given a positive integer k, return the smallest non-negative integer n such that (k*2^n)+1 is a prime.

This is code-golf, so smallest answer in bytes will win!

OEIS link for this sequence

OEIS link for sequence shifted by 1, with alternative calculation method

Test cases:

Input Output
1     0
2     0
3     1
4     0
5     1
6     0
7     2
8     1
9     1
10    0
11    1
12    0
13    2
14    1
15    1
16    0
17    3
18    0
19    6
20    1
46    0
47    583
48    1

TODO:

  • Rework preamble
  • More/better test cases?
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1
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Make a program run infinitely

For this challenge, you will be given a program in a very simple stack-based 2D language (that will be specified by this challenge), and your task is to find an input that will make it run infinitely (i.e. make it have 0% probability of halting). For the sake of this challenge, it will be fully deterministic; that is, no random functions will exist.

Language specifications

The program runs on a 2D cartesian grid and there is a single pointer with an (x, y) coordinate and a direction (up, down, left, or right). The memory is stack-based. The pointer starts in the top-left corner at (0, 0), moving to the right. After each command is finished executing, the pointer moves one space in the direction it is currently facing. The grid is cylindrical on both sides. The following commands exist:

Movement

Absolute

^ pointer direction becomes "up"
> pointer direction becomes "right"
v pointer direction becomes "down"
< pointer direction becomes "left"

Relative

] rotate pointer direction right 90 degrees (up -> right -> down -> left ->)
[ rotate pointer direction left 90 degrees (up -> left -> down -> right ->)
# invert pointer direction (up -> down ->, left -> right ->)
| horizontally reflect pointer direction (left -> right ->)
_ vertically reflect pointer direction (up -> down ->)
\ diagonally reflect pointer direction (up -> left ->, down -> right ->)
/ diagonally reflect pointer direction (up -> right ->, down -> left ->)

Operators

+ push pop + pop
- push pop - pop
* push pop * pop
: push pop / pop (integer/floor division)
% push pop % pop (modulo; the result is the same sign as the base)

Stack Operations

. pop a value
, get a value from the input and push it to the stack
$ swap the top two values of the stack
& duplicate the top value of the stack

Conditionals

! if the top of the stack is falsy, move the pointer an extra step in its current direction (skip next command)
? if the top of the stack is truthy, rotate right, otherwise, rotate left

Other

space: do nothing
0-9  : push the value of that digit
;    : terminate

You will be given a 2D grid in any desired format (newline-delimited string, array of lines, array of arrays of character, etc). You may assume that all rows are of the same length. You can choose any set of characters to represent these; in other words, any bijection between a set of characters or a set of integers and the characters ^v<>[]#|_/\+-*:;%.,$&!? 0123456789 is valid.

You must return an array of numbers in any reasonable format where when these values are fed one-by-one into the program as inputs, the program will not terminate. There may be more than one such solution; if so, you must return at least one of them, and you do not have to be consistent in which ones you return, as long as at least one is returned. Note that the array must be finite; that is, if it keeps looping through a ,, then it does not count as a solution. There is always at least one solution.

After the program is run, no inputs should remain; that is, there must be exactly the right number of inputs in the array.

You may assume that there is at least one solution where all of the numbers are in the range [0, 256).

Test Cases

,!v;
 >v      =>  [1] (or any other single truthy value)
 ^< 

,v>v;  
 >?>?v<
  >v>>^  =>  [1, 0] or [0, 1] (or any other array of two values with opposite truthiness)
   >?  
    ;  

,1-!;v<  =>  [-1] (only this value works)
     >^

Sandbox

  • Is this too hard?
  • Is there anything unclear or anything needing more clarification?
  • Is this too easy?
  • Is the language too complicated for a challenge like this?
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  • \$\begingroup\$ I don't really understand what 'push' and 'pop' mean thus the operator section is a little confusing to me. Also I think you need to include ; in the list of characters that one can make a bijection from. Also, would it make sense to swap the \ and / commands? If you do the characters would represent mirror planes (or plain mirrors) but now they seem a little counterintuitive to me. \$\endgroup\$ – dylnan Nov 16 '17 at 19:45
  • 1
    \$\begingroup\$ @dylnan 1. push and pop are stack operations meaning put a value onto the top of the stack and remove the top of the stack and return its value, respectively. So for example, push pop + pop means pop a value off the top, pop another value off, add them, and push it onto the top of the stack. Also, yes, I missed ;, thanks for noticing. Also, I got confused by my own wording so yes, \/ should be swapped. Thanks for the comments! \$\endgroup\$ – HyperNeutrino Nov 16 '17 at 20:07
  • \$\begingroup\$ So, if I understand, the submissions will take code in the 2D language as input, and the output will be values that, when fed into the input code, would cause it to run infinitely? \$\endgroup\$ – Kamil Drakari Nov 16 '17 at 20:30
  • \$\begingroup\$ @KamilDrakari Yep. \$\endgroup\$ – HyperNeutrino Nov 16 '17 at 20:43
  • \$\begingroup\$ How would the conditionals ! and ? deal with the stack? In your second test case, if the stack is 01 (say the right is the top) and the first ? sees the 1, wouldn't the stack have to be popped in order for the second ? to see the 0 and move into the infinite loop? \$\endgroup\$ – dylnan Nov 17 '17 at 1:21
  • \$\begingroup\$ Also, I think is too hard due to the halting problem. Even with the busy beaver Turing machines it becomes very difficult to determine whether a machine will halt with machines of only a few states. Maybe if you somehow restrict the possible modes of running infinitely (e.g. program will only run infinitely if it gets into <^>v or <v>^ loops) and restrict the length of the program but even then I think it might be too hard but I'm not sure \$\endgroup\$ – dylnan Nov 17 '17 at 1:44
  • \$\begingroup\$ @dylnan It theoretically shouldn't be too impossible because you can just go through all possible states and if it ends up in the same state as before, it will loop infinitely (because there are no non-deterministic commands). It will be horribly inefficient, but eh, it's code-golf, efficiency is not the priority :P \$\endgroup\$ – HyperNeutrino Nov 17 '17 at 1:59
1
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Packing Density of Polyline Defined Shapes

So... I was making bacon this morning and I couldn't fit all of my bacon into my pan. However I oriented the strips, there was always one or two pieces that didn't fit. Culinary endeavors aside, here's my challenge:

Input:

pan and bacon

Each of these inputs is a list of (X,Y) coordinates that define a closed shape. The very first index and the very last index are different, but the shape is closed. It not guaranteed that the shape is convex, but it is guaranteed that the path doesn't cross itself. Further, for simplicity, you may expect all the (x,y) coordinates to be integers.

Your program must find the most occurences of bacon that can fit into the pan, allowing rotation and flipping.

Output:

An integer that represents how much bacon can fit in the pan.

Scoring and rules:

For proper cooking:

  • A bacon may touch another bacon or the edge of the pan.
  • bacon may not overlap, nor may it go off the pan.
  • The first index of both pan and bacon is always (0,0).
  • If there is a tie in number of bytes, the user whose code is formatted to look like ASCII bacon wins.
  • If two users tie and both have ascii bacon, upvotes wins. Standard rules apply. This is code golf, so the standard rules apply.

Sample input and output:

Test Case 1:

Bacon directly overlaps the pan, and is the same size.

pan: [(0,0),(0,1),(1,1),(1,0)]
bacon: [(0,0),(0,1),(1,1),(1,0)]
Output: 1

Test Case 2:

When bacon is bigger than pan

pan: [(0,0),(0,1),(1,1),(1,0)]
bacon: [(0,0),(0,2),(2,2),(2,0)]
Output: either 0 or an error.

Test Case 3:

What happens when bacon crosses itself?

pan: [(0,0),(0,1),(1,1),(1,0)]
bacon:[(0,0),(1,1),(0,1),(1,0)]
Output: just error here. Any way you feel like. If you manage to report an http 418 error, you get bonus points, redeemable for nothing.

Test Case 4:

What happens if the bacon doesn't exactly overlap the pan?

pan: [(0,0),(0,3),(5,3),(3,0)]
bacon: [(0,0),(0,2),(2,2),(2,0)]
Output: 2

\$\endgroup\$
  • 1
    \$\begingroup\$ This looks like a tough question, but I like it. 1.) Are the coordinates integers or can they be floats? 2.) Is the shape guaranteed to be convex and contain more than two coordinates? 3.) Because this is a code golf challenge, it's unlikely anyone will go for the second output, so you should probably stick with just one of the two output methods. 4.) Example inputs and outputs would be great. \$\endgroup\$ – Laikoni Nov 16 '17 at 21:15
  • \$\begingroup\$ Having arbitrary polygons make this tough, even just to figure out if one shape fits inside another. I think you'll do well to have extensive test cases that probe at the possibilities and defy heuristics. \$\endgroup\$ – xnor Nov 16 '17 at 21:42
  • \$\begingroup\$ I've added quite a few test cases using minimal pans and bacon. @xnor, what do you mean by 'defy heuristics'? \$\endgroup\$ – Jakob Lovern Nov 16 '17 at 21:57
  • \$\begingroup\$ @JakobLovern Like, for example, making it so that code that just outputs the ratio of the areas doesn't happen to pass all test cases. Other examples could be making sure the code allows bacon to be rotated by non-multiples of 90 degrees, doesn't just try to do some greedy fill from one corner, considers reflecting the bacon, etc. The idea is that someone whose code meets all the tail cases should be reasonably certain it meets the problem conditions. \$\endgroup\$ – xnor Nov 16 '17 at 22:36
  • 1
    \$\begingroup\$ @JakobLovern My experience has been that writing the code to do the task has been very helpful to think of edge cases and to generate test cases. You can then post it as (ungolfed) reference code, which is often appreciated by solvers. \$\endgroup\$ – xnor Nov 16 '17 at 22:43
1
\$\begingroup\$

Implement a basic two-dimensional esolang

There are hundreds of two-dimensional stack-based esoteric programming languages out there, and lots of them follow a very similar syntax:

v redirect instruction pointer down
> redirect instruction pointer right
^ redirect instruction pointer up
< redirect instruction pointer left
/ redirect instruction pointer: up -> right, right -> up, left -> down, down -> left
\ redirect instruction pointer: up -> left, left -> up, right -> down, down -> right
0 push 0 to the stack. 1 pushes 1, ... 9 pushes 9.
A push 10 to the stack. B pushes 11, ... F pushes 15.
: duplicate the top stack value
~ swap top two stack values (all languages implement this as a different character)
i read input as a ASCII character and push to stack
o print the top of stack as an ASCII character
n read input as integer and push to stack
u print the top of stack as an integer
+ increment the top of stack
- decrement the top of stack
! jump over the next command
; stop execution

Almost all two-dimensional esolangs contain more commands, but for the sake of simplicity, the one we're writing will contain only the above.


Specification

The stack should be able to hold at least 30,000 values. You may pick any integer size (e.g. 32-bit, 64-bit, unbounded, etc) for stack values.

The instruction pointer should start moving right from the top left corner of the source code, and should wrap upon exiting the playing field, meaning that this code will be an infinite loop:

<^
v>

First, < will be reached, pointing the IP off to the left.
The IP will wrap around to the right, continuing left, and hit the ^, directing it up.
Then it will wrap, hit the > and travel right, wrap, hit the v and travel down, wrap, hit the <, and start over.

\$\endgroup\$
1
\$\begingroup\$

Squaring the circle

Background

This is a generalization of this question on puzzling.SE. Essentially, it asks you to generate a circular array of integers such that any two adjacent integers add to a perfect square, and that the integers are a permutation of those from 1 to 50. The original question gave you a part of the array, and asked you to solve it. I wish to generalize this problem.

Problem Description

Given an integer n, generate a circular array of numbers from 1 to n such that any two adjacent integers sum to a perfect square, without repeats of any number.

Input

Input is limited to positive integers greater than or equal to two.

Output

If there is no possible array (as can be manually proven to be the case for n=4), then your function should gracefully handle the error and exit.

Otherwise, it should output a representation of that array for that n as a string of delimited integers, such that, if the string were concatenated into a long integer, it would be the minimum possible string. To illustrate:

1 2 3 
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1

Of these six representations, only 1 2 3 is in minimal form.

You may delimit your string in any consistent, parsable way you choose.

Example I/O

For n<32, there are no valid arrays (And I can prove it, if necessary.) The smallest n with a valid array is n=32, and it is structured:

=>01 08 28 21 04 32 17 19
15                       30
10                       06
26                       03
23                       13
02                       12
14                       24
22                       25
27                       11
  09 16 20 29 07 18 31 05

The output to n=32, would therefore be 1 8 28 21 4 32 17 19 30 6 3 13 12 24 25 11 5 31 18 7 29 20 16 9 27 22 14 2 23 26 10 15

Example code

Because code is clearer than words, here's a (purposefully) very naive and inefficient routine for this in Python (2.7):

import math, itertools
def main(n):
  def test_if_a_given_list_is_a_ring(input_list):
    is_a_square = lambda value: math.sqrt(value).is_integer()
    output_flag = True
    for index in range(len(input_list)):
      if is_a_square(input_list[index]+input_list[index-1]):
        continue
      else:
        output_flag = False
      #end if
    #end for
    return output_flag
  #end test_if_a_given_list_is_correct
  def turn_it_into_a_string(input_list):
    temp_list = []
    for i in input_list:
      temp_list.append(str(i))
    #end for
    output_string = ''
    for i in temp_list:
      output_list += ' '+ i
    #end for
    return output_list[1:]
  #end turn_it_into_a_string  
 lowest = string(n)*n

 for perm in itertools.permutations(range(n,0,-1)):
    if test_if_a_given_list_is_correct(perm):
      flag = True
      for perm_character,lowest_character in zip(turn_it_into_a_string(perm),lowest):
        if int(lowest_character) < int(perm_character):
          flag = False
          break
        #end if
      #end for
      if flag:
        lowest = turn_it_into_a_string(perm)
      #end if
    #end if
  #end for
  return lowest
#end main

If you're gonna golf this code... I'd highly recommend optimizing it first.

Scoring

Programs will be scored based on: 1. Asymptotic complexity 2. Average runtime 3. Byte count 4. Runtime when the byte count is fed into the program as input

(I can't decide which of these scoring systems to use. Note that I've manually worked out that when n<=31, there are no arrays. At n=31, there is a valid double loop system, but no valid single loops.)

\$\endgroup\$
  • \$\begingroup\$ your example is not a valid ring, is it? I only see two perfect squares, 11+5=16 and 1+8=9 \$\endgroup\$ – Luca H Dec 1 '17 at 9:18
  • \$\begingroup\$ No, it isn't. As of ten minutes ago, I constructed (By hand) the ring for n=32, so I'll post that. \$\endgroup\$ – Jakob Lovern Dec 1 '17 at 18:56
  • \$\begingroup\$ (1) "ring" has a specific meaning (an algebraic structure with multiplication and addition subject to certain rules), which is distracting. How about changing it to circular array? (2) In my opinion, "generate a [circular array] of numbers from 1 to n" does not impose a restriction on the length of the array or on the impossibility of repeats. For me the clearest way to add the restrictions which I infer from the linked question would be to say that it's a permutation of the numbers from 1 to n. \$\endgroup\$ – Peter Taylor Dec 1 '17 at 21:02
  • \$\begingroup\$ (3) "This is a two part question": I only see one part. If you intend a follow-up, maybe worth including it so that you can get opinions on whether it would be closed as a dupe of the first part. \$\endgroup\$ – Peter Taylor Dec 1 '17 at 21:03
  • \$\begingroup\$ @PeterTaylor I was originally intending to ask the question twice, but score using different conditions. I expect that code which would minimize asymptotic complexity wouldn't look at all similar to code which minimizes size. I wanted to see the difference. You made a good point on the dupe problem, though, as the two questions are essentially similar to each other. \$\endgroup\$ – Jakob Lovern Dec 1 '17 at 21:44
  • \$\begingroup\$ So what's the scoring? If byte-count gets fed to the program no solutions that are < 31 bytes & if it's gonna be an average runtime based scoring you should choose large enough values such that it becomes about complexity and include how you measure. \$\endgroup\$ – ბიმო Dec 3 '17 at 3:10
  • \$\begingroup\$ That's exactly why I was asking for input on my various ideas for scoring. I don't expect that there's going to be any programs that small that can successfully answer the question, but it could happen. I'm leaning towards asymptotic complexity or byte count. \$\endgroup\$ – Jakob Lovern Dec 5 '17 at 18:01
1
\$\begingroup\$

Advancing k-combinations

k-combinations for a set of size n represent in what different ways one can pick k elements out of a set of n elements. There is a natural representation of such a pick as an integer with n bits, of which exactly k are set.

Define next[n, k] :: Pick(n, k) -> Pick(n, k) to be the group action that takes each pick to the next one, wrapping around. More formally: Let r be an n-bit integer with k bits set. Then next[n, k](r) will return the smallest integer > r that also has k bits set. If there exists no such integer, the smallest integer with k bits is returned. Example: next[4, 2](0b0011) = 0b0101, next[4, 2](0b1100) = 0b0011.

[- Annotation: if k = 0, then there is only one unique integer with zero bits set. next[n, 0](r) = 0. -]

You will be given a pick r and a positive integer step. Output (next[n, k]^step)(r), that is, apply next[n, k] step times to r.

Rules

  • You will be given 4 integers n k r step. Output (next[n, k]^step)(r)
  • 1 <= n can be assumed to be small enough to represent picks as integers naturally in your language
  • 0 <= k <= n
  • r will always be a valid pick of k out of n.
  • 0 <= step <= C(n, k) can be relatively large. As an example, C(32, 12) = 225,792,840

Criteria

Return the correct output for all valid inputs.

This is code-golf, shortest code wins.

Examples

4   2 0b1001 2  => 0b1100
16 10 0xF11F 10 => 0bF15E
4   2 0b1100 2  => 0b0101
\$\endgroup\$
  • \$\begingroup\$ Nice challenge! But what if k = n = 0? And maybe specify formally how next works. \$\endgroup\$ – ბიმო Dec 3 '17 at 5:38
1
\$\begingroup\$

Best Yahtzee score

Yahtzee is a game played with five six-sided dice and a score sheet with thirteen different boxes to fill a score in. Each box has its own scoring rules:

  • 1s, 2s, 3s, 4s, 5s, 6s all score points equal to the sum of the respective dice (that is, a roll of [3, 2, 3, 1, 5] scored as 3s would be awarded 6 points - 3 for each 3).
  • 3-of-a-kind and 4-of-a-kind (as they sound, three or four dice rolled the same) score points equal to the sum of all five dice.
  • Full house (two dice show one value, the other three show another) scores 25 points
  • Small straight (four consecutive values) scores 30 points
  • Large straight (all consecutive values) scores 40 points
  • Yahtzee (all dice show the same value) scores 50 points

The thirteenth (chance) makes sense in-game, but not so much for this challenge; additionally the game has bonuses for extra Yahtzees which make no sense here. Because the challenge is...

Given five dice as input (five integers 1-6, input however is convenient), output the highest score that roll can score as well as what box it's being score under. The score should be output as its decimal numeric value, whether that's an integer or a string representation thereof, whatever. It should be immediately recognizable as a number. How you identify boxes is up to you so long as they are all unique and any given roll that will be scored in a given box always returns the same value. Please specify in your answer how boxes are identified. Order ([score, box] or [box, score]) does not matter. If you're outputting to STDOUT or otherwise not returning two values from a function, please separate score and box with at least one non-alphanumeric character of your choosing.

Code golf, so shortest answer in a given language wins. Standard loopholes apply.

Test cases, using , as separator, and 123456kKfsly for the box names (respective of their order above):

in: 1 5 4 3 2
out: 40
in: 1 1 4 3 1
out: 10
in: 1 1 6 5 3
out: 6

Sandbox/meta

  • I saw one existing Yahtzee challenge, but IIRC it boiled down to scoring a whole game. I did the 'given five dice, what is the best score' exercise once and felt like there were some interesting challenges to be found in optimizing it.
  • Better ways to express I/O? I want it to be flexible but relatively readable...
  • My first potential submission, I'm sure I'm forgetting something...
\$\endgroup\$
  • 2
    \$\begingroup\$ IMO, multi parts output is pretty much a party killer. In that specific question, I think the score itself is enough to constitute a nice challenge. The box value is drived by conditional programming, which (of the challenge goes well) might not be present in some answers. \$\endgroup\$ – Uriel Dec 6 '17 at 22:58
  • 1
    \$\begingroup\$ Anyway, for that wide range of possibilities, you should add at least one test case to cover collisions, multiple scorings and at least one of each box type (again, as I see challenges here) \$\endgroup\$ – Uriel Dec 6 '17 at 23:00
  • \$\begingroup\$ @Uriel Thanks for the input — I planned to fill in more test cases, I guess I could've mentioned that in the meta section. I'm not trying to be difficult, but I'm curious if you could expand on your other point w/ the score itself being enough. The score is (I believe?) entirely dependent on the box being determined, and spitting something box-related out seems programmatically like a small challenge vs. the 'reward' of the output. This was why I wanted that output to be very flexible. Part of me thinks you're right, part of me thinks I'm right… so if you have more to say, please do… \$\endgroup\$ – brhfl Dec 7 '17 at 2:37
  • \$\begingroup\$ my point is, in order to get the right score the user necessarily went through the right box (and not even print it, but also did a somewhat-more-complex calculation with it) - so it's kinda like letting them output twice. \$\endgroup\$ – Uriel Dec 7 '17 at 10:02
  • 1
    \$\begingroup\$ @Uriel Makes sense, and I was leaning that way the more I thought about it last night. Cutting it also eliminates the need to address collisions. I think it's out... Thanks! \$\endgroup\$ – brhfl Dec 7 '17 at 13:35
1
\$\begingroup\$

Google Doodle Kids Coding-style simulator

One input is a list of commands. There are three action commands and a loop construct. There is some flexibility as to the command format:

  • As a string or equivalent: The loop construct should use a pair of matching brackets. The direction commands should be < and > or L and R (either case). The motion command should be ^ or F.
  • As a list of characters: The loop construct should be a sublist. The other commands should be individual characters in the list, specified as above.
  • As a list of integers: The direction commands should be -1 and 1 while the motion command should be 0.

The other input is the starting position. This consists of an two-dimensional array in any suitable format (including a newline-separated string). Background values should be represented using 0 or spaces. Carrots should be represented using -1, ^ or V (either case). The starting square should be represented using 1, @, or R (either case).

Optionally, the starting direction can be an input (one of <>V^ or an angle in degrees or turns), or it can be hard-coded (please specify the default starting direction in this case).

Command rules:

  • Loops always execute four times
  • The direction commands rotate the rabbit in place
  • The motion command moves the rabbit one square in the current direction

The rabbit wins if it eats all of the carrots.

The rabbit dies if:

  • It runs out of commands
  • It walks out of bounds
  • It walks onto the background

The starting square and carrot squares are all safe.

Your output should be a consistent truthy value if the rabbit wins, and a consistent falsy value if it dies. This can also be achieved by exception or error exit.

This is , so the shortest program or function that breaks no standard loopholes wins!

\$\endgroup\$
  • \$\begingroup\$ Related \$\endgroup\$ – Emigna Dec 8 '17 at 11:51
  • \$\begingroup\$ What's the background? \$\endgroup\$ – user202729 Dec 8 '17 at 12:07
  • \$\begingroup\$ 1) exception exit is already a standard way to output a falsey value, and 2) in the actual Google doodle you don't lose if you try to walk off the edge of the map, it just does nothing. \$\endgroup\$ – Nissa Dec 8 '17 at 14:02
  • \$\begingroup\$ @StephenLeppik It's not meant to exactly simulate the Doodle. \$\endgroup\$ – Neil Dec 8 '17 at 14:32
  • \$\begingroup\$ By "background" I means as in "It walks onto the background". \$\endgroup\$ – user202729 Dec 9 '17 at 10:04
  • \$\begingroup\$ @user202729 The background is any square whose value is 0 or space depending on your input format. \$\endgroup\$ – Neil Dec 9 '17 at 10:55
  • \$\begingroup\$ Ready to post to main? \$\endgroup\$ – user202729 Dec 11 '17 at 5:48
  • \$\begingroup\$ Don't abandon this... :( \$\endgroup\$ – user202729 Dec 18 '17 at 15:43
1
\$\begingroup\$

Tell my browser

Background

Many people visit webpages, which require special browsers because of lack of compatibility. So you have to write a script (client sided or server sided), which just prints the name of the browser. Because not everyone has fast internet, the script has to be as short as possible.

Rules

  1. You have to print the name of the browser loading the page without any version number etc. to STDOUT or equivalent. Leading or trailing spaces are allowed.
  2. You can assume the browser is Firefox, Chrome, Edge, Safari or Opera, so only those browsers will be tested. Don't print "Chromium", this does NOT count.
  3. The script may be server sided with CGI (in any language), ruby on rails, jsp and similar. Client sided scripts may be written in JavaScript, TypeScript, and any other versions of ECMAScript, it just has to run in all five browsers.
  4. If your language has no offline interpreter for CGI, assume it's saved in /usr/bin/i, the shebang at the beginning does not add bytes to the count.
  5. this is a , so the shortest answer wins!

Meta

  • Does this question have important loopholes?
  • Is there any language which cannot be programmed in? (CGI should work always, even Java or bf could be done with a shebang, lol)
\$\endgroup\$
  • \$\begingroup\$ About the "Is there any language which cannot be programmed in?" --- that's actually a very good question. Let me try. \$\endgroup\$ – user202729 Dec 10 '17 at 14:37
  • \$\begingroup\$ About the background... "fast internet" doesn't matter if the script is server-side. \$\endgroup\$ – user202729 Dec 10 '17 at 14:38
  • \$\begingroup\$ @user202729 This is a joke, lol, just like those other joke reasons the program has to be short. Is it a good question though? \$\endgroup\$ – Mega Man Dec 10 '17 at 14:49
  • \$\begingroup\$ Probably. But the fact is, not everyone is familiar with writing a server, so you may not get a lot of answers. \$\endgroup\$ – user202729 Dec 11 '17 at 6:03
1
\$\begingroup\$

Coin Game: Shoot It Out!


In Shoot It Out, we will play with coins on a table.

Basic Idea

Shoot It Out is a 6-player game. The players will be split into two teams of 3 players, one offensive, and one defensive.

Initially, every player has a coin on the table. Additionally, there is a target coin. Players take turns to shoot their coin. However, the shots will not be very accurate.

The offensive team will try to shoot the target coin out of the table, while the defensive team tries to prevent the target coin from being shot out. You should make a bot that can play as both offensive and defensive team, and try to maximize the winning rate.

Rules

Playing Order

  • Every player has its player ID. ID 1, 3, 5 are on the offensive team; ID 0, 2, 4 are on the defensive team.

  • Playing order is the same as ID. After the turn of ID 5 is ID 0's turn. If a player is removed, simply go to the next player.

  • When it is a player's turn, they will shoot their coin once. After every coin stopped moving, the turn ends.

Elimination in a Game

  • If a player shoots their own coin out of the table, the player is removed from the game. If the target coin moves out of the table in the same turn, it will be placed back to the previous position.

  • If a player shoots another player's coin out of the table, both players are removed from the game.

(Note that these two can occur in the same turn.)

Winning Conditions

  • Defensive team wins when both conditions below are satisfied:

    • The target coin is in the table area.
    • All players on the offensive team are removed, or 18 turns have been played (skipped turn is not counted).
  • Offensive team wins when one of the conditions below are satisfied:

    • The target coin is out of the table area.
    • All players on the defensive team are removed.
  • There is one exception: if all players are removed at the end of a turn, the defensive team wins.

Table Settings / Parameters

  • The table is a circular area of radius 100 cm. The radius of every coin is 1 cm. A coin is out of table iff its center is out of the circular area.

  • For convenience, we set the coordinate of the center of the table to (0, 0), and denote the position of a coin by the coordinate of its center.

  • The coefficient of restitution between coins is 0.9.

  • The maximum intended speed of a shot is 240 cm/s.

  • When a coin is moving, it will have an acceleration of -240 cm/s^2 (due to friction).

  • When the game starts, the target coin is located at (0, 0), while the coin of ID x is located at (2.5 cos(f(x)*pi/3), 2.5 sin(f(x)*pi/3)). The values of f(x) are:

x f(x)
0 0
1 3
2 1
3 4
4 5
5 2

Here is a picture of initial positions.

Errors

Each player's shot has two parameters: angle and initial speed. Programs will output the two parameters representing its intended shot. However, the actual shot won't be the same of what is intended: errors will be added into parameters.

Specifically, if the angle (in radians) and initial speed (in cm/s) of the intended shot are θ, v, then:

  • The actual angle will be θ+R(pi/70).

  • The actual initial speed will be v*exp(R(1/12)). (Note that it may exceed the maximum speed.)

Where R(x) is a random variable with Gaussian distribution of standard deviation x and average 0.

Scoring

Since only 6 players can play in one game, the controller will randomly assign players to a game.

Lots of games will be held until each player has played both defensive and offensive team in more than 10000 games.

The final score of your program will be y/x+z/(1-x), where:

  • x is the average winning rate of offensive team in all games.

  • y is the winning rate of your program when on the offensive team.

  • z is the winning rate of your program when on the defensive team.

Input / Output

Your program will be run once per game. It should receive inputs from stdin and output to stdout.

At the beginning of a game, it will receive a line of input a, where a is the player ID (thus indicating which team you should play in).

When a turn starts, you will receive input like this:

3
0 3.798 3.332
1 12.656 3.666
3 18.652 7.913
4 8.004 7.132
6 -3.187 -9.553

The first line indicates the player of this turn. Each remaining line contains information of a coin: The first number is the player ID of the coin's owner (or 6 if it is the target coin). The remaining two numbers are x and y coordinates of the center of the coin.

If it is your turn, you should output two numbers, separated by a newline or space, representing the intended angle (in radians, 0 is +x, pi/2 is +y) and initial speed (in cm/s). You should flush stdout after output. (If it is not your turn, you should not output anything.)

You needn't to handle the termination of your program. When the game ends (or you are removed), the controller will send SIGKILL to your program to terminate it.

Specifications

  • Your program should be able to be compiled into an executable, or be executed like an executable (for example, add shebang if you use interpreted languages). If your program need to be compiled to run, you should also specify how to compile your program.

  • Your program should not access files, or anything that stores information between games.

  • Your program should be deterministic. You can use random number generators, but you should make sure that the generator you use is based on a fixed seed, and will not use random devices (such as RDRAND or /dev/random), system time, etc.

  • All "random" numbers (while generating errors and assigning players) used by the controller are generated in a deterministic way. However, your program should not take any advantage of it.

  • The total response time of your program in a game should not exceed 0.1 second.

  • You can submit multiple programs, but they should not team up against the others.

Controller & Sample Bots

(Still working on them...)

\$\endgroup\$
1
\$\begingroup\$

The 64 | 64 Color Selector

All colour selector tools suck. Let us make another one that sucks also, but in a different way.

Your interface will have:

  • two squares, of 64x64 "pixels" each one. Pixels do not need to be strictly pixels, but anything where the user can have 64 possible selections in each direction, vertical or horizontal, representing all the possible different RGB colors.

  • a third element of the interface that will represent the color selected with user has selected based picked on squares.

  • a fourth element which represents the 6 digit hexadecimal RGB hex-code (example: #FFBF32). You can divide it in three elements, but you have to make clear which component is what from RGB.

  • a fifth element which represent the decimal RGB code (example RGB(127,33,43)). You can also divide it in three elements, but you have to make clear which component is what from RGB.

When the two squares are at the top left corner, selected color must be RGB(0,0,0); and when the two squares at the bottom right corner must be RGB(255,255,255).

You must have the the pixels in the square sorted by increasing order; I don't care what direction, vertical or horizontal, you choose for increasing one-by-one, but the two squares must have the same pattern.

When the user picks a "pixel" in the first square, the colours of the second must be updated and reflect all possible values under the second pixel.

When the user picks a "pixel" in the second square, 3rd, 4th and 5th elements must be updated to reflect new color selection.

Code-golf, but there will be no accepted answer, as it discourages people from adding new answers when they see already posted very short answers.

\$\endgroup\$
  • 1
    \$\begingroup\$ Your specifications seem a bit too loosely-defined to me, though unfortunately I don't have any suggestions for improvement at the current moment \$\endgroup\$ – HyperNeutrino Dec 11 '17 at 15:32
  • \$\begingroup\$ I assume that your first requirement should state 'Pixels do not need to be strictly pixels...' \$\endgroup\$ – brhfl Dec 11 '17 at 18:34
  • \$\begingroup\$ @brhfl Yes. Thanks. Fixed. \$\endgroup\$ – sergiol Dec 11 '17 at 18:50
  • \$\begingroup\$ Is there any requirement on the ordering of selections in the first two elements, or is it fine as long as every RGB color could be expressed as a coordinate pair on the first element plus a coordinate pair on the second element? \$\endgroup\$ – Kamil Drakari Dec 11 '17 at 19:21
  • \$\begingroup\$ @KamilDrakari: Yes. Thanks. Updated. \$\endgroup\$ – sergiol Dec 12 '17 at 11:09
  • \$\begingroup\$ @HyperNeutrino: better now? \$\endgroup\$ – sergiol Dec 12 '17 at 11:10
  • 1
    \$\begingroup\$ It looks good, you may want to point out that you want a 1:1 color conversion. I was looking at it and I think that's what you want since 64^4 = 256^3. \$\endgroup\$ – Neil Dec 13 '17 at 4:03
  • \$\begingroup\$ "You must have the the pixels in the square sorted by increasing order" is nonsense unless you address the issue that HyperNeutrino raised about the specifications not truly being specifications. \$\endgroup\$ – Peter Taylor Dec 13 '17 at 9:41
1
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Sheet music exact transposition

As we're limited to ASCII here, I'll just refer to the notes by name A-G, although obviously real sheet music has a range of about an octave and a half even before you take ledger lines into account.

Notes are written on sheet music in two ways. Most of the time, notes have their own position on the stave, but no accidental is indicated; this means that the note gains the accidental corresponding to the key signature. For example, the scale of A is ABCDEFGA; the C, F and G are played sharp because of the key signature. These notes are easy to transpose, because you simply need to shift them by the appropriate number of note names; the accidental is taken care of by the key signature. For example, the scale of A is simply ABCDEFGA; if you transpose down two notes, you get the scale of F, FGABCDEF; in this case the C, F and G become natural and the B becomes flat, but there's nothing extra for you to do here because the key signature takes care of it. This works even if the key itself contains accidentals; transposing the scale DEFGABCD from D♭ to D♯ simply results in DEFGABCD again.

For notes that are not available in the key signature, an accidental needs to be applied. This is either the ♮, indicating that an accidental in the key signature (or previously used for that note, but that's not relevant here) should be ignored, or one or more of either ♭ or ♯, indicating how many semitones the note should be adjusted. (Although an accidental exists for ♯♯, we will ignore this to simplify the challenge).

You can't just throw accidentals around, otherwise you end up with the scale of E written as F♭E♯♯A♭A♮C♭B♯♯F♭♭E which is ridiculous. It is therefore essential when you transpose a note that the note name is transposed identically no matter how many accidentals the note may have.

However, there is a caveat: the named intervals are not regular. The interval between B and C and that between E and F are just one semitone, while the other intervals are two. This means that you might have to adjust the accidental if the number of semitones between your original and transposed note differ from that of the original and transposed key. The number of accidentals in the key must also be taken into account, of course.

Take the example of transposing the note D from the key of A to the key of F. Because F is five notes above A, the note D transposes to the note B; the key signature takes care of making the B flat. However, if we were transposing the note D♯, we would have to calculate that the final note needs to be B♮ in order for the number of semitones to be correct (F - A = 8, B♮ - D♯ = 9 - 1 = 8; the ♯ increase the number of semitones while the ♭ decreases it, but of course subtracting a ♯ results in a decrease too).

Conveniently, the output has an accidental of some sort (including ♮) if and only if the input note does, which should simplify the challenge.

Your challenge is to write a program which will accept three notes as arguments. Two of the notes will represent the original and transposition key of the transposition, while one of the notes will represent the note to be transposed. You must then output the result of the transposition. Examples:

Note    From    To      Result
G♮      A♭      B♭      A♮ (not A)
C♯      B       D       E♮ (not E)
B       F       D       G
B♭      C       G       F♮
B       B       A       A
B       E       B       F (not F♯)
D♭      E       G♭      F♭♭ (not E♭ or D♯)
G♭      E       G       B♭♭ (not A or A♮)
E♭      G♭      C♯      A♮ (not A)
C       F       D       A
G♯      C       G       D♯ (not E♭)

This is , so the shortest program wins. However, since there does not appear to be an ASCII character that can represent ♮, I will allow any of the three UTF-8 characters ♭, ♮ or ♯ to count as a single byte.

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1
\$\begingroup\$

Simultaneous Selection

In the game Risk of Rain there is a game mode where you can select which items you want out of dropped boxes. The only problem is that when you open two boxes at the same time your movements in one box effect your movements in another. Now this can be a problem since you may want to retrieve a particular item from one of the boxes. However there is a solution.

Since the boxes have different shapes and you are not permitted to move your cursor outside of the box you can desynchronize the two cursors.

For example if we have the two boxes

S.F...    S.....
......    ...F..
....      .....

Where F is the goal and S is the starting location, we can get the cursor to the goal by moving the cursor

Right 4 times
Down 3 times 
Up 1 time
Left 1 time

Still working on it ...


Input

As input you will receive two 2 dimensional boolean containers, representing the shapes of the boxes. In these boolean arrays true means that square exists in the box false means square does not exist. You may assume that your input will be padded with false values such that no true values touches the edge of the array.

You will also receive two coordinate pairs representing the start and end locations.

Output

You should output a ordered container of "moves" such that when performed on both boxes the cursor will arrive at the end point. A "move" may be one of 4 chosen values each representing one of the 4 cardinal directions. For example you might choose: [N,S,E,W], [1,2,3,4] or [(1,0),(0,1),(-1,0),(0,-1)]. Your program must be self consistent in these values across multiple sessions.

If no solution is possible for the given boxes you must output a value that is distinct from any possible sequence of moves, for example a list containing a 5th value that cannot represent a move, or a non list item.

Still working on it ...

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  • \$\begingroup\$ How do we take input? As two separate strings or can it be arrays, etc... \$\endgroup\$ – Neil Dec 17 '17 at 5:20
  • \$\begingroup\$ @Neil Its going to be boolean arrays, true means square exists false means square does not exist, and coordinates for start and end locations. I've been a little lazy in finishing this question. \$\endgroup\$ – Post Rock Garf Hunter Dec 17 '17 at 5:22
1
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Demolish a string! v2

A modified version of Demolish a String; since the original question involved randomness, the challenge was too complex and there were not many answers. This challenge removes the criterion and allows flexibility by the answerer, which should invite responses in languages without randomness built-ins.

Challenge

Given a string input, output the demolished version of it.

The Process

P
r      Pr       r
o       o       o
g       g       g
r       r       r      rogr         r
a  ->   a  ->   a  ->     a  ->     a  ->           ->           ->           ->           ->  
m       m       m         m         m
m       m       m         m         m         mmar         m
i       i       i         i         i         i            i           mi           m
n       n       n         n        gn        gn           gn           gn           gni         mgni
g       g      Pg        Pg      roPg      roPg         roPgmar      roPgmar      roPgmar      roPgmar

Place the string vertically. Repeat the following steps until they are impossible:

  1. Take any column of characters that can be demolished (explained below)
  2. Select some integer between 1 and (height of the column of characters) - 1 and some direction (left or right).
  3. Rotate that number of characters in that direction (only if those spaces are unoccupied; if not, go back to step 3).
  4. Let those characters fall due to gravity.

At the end, the output should be a string whose heights of consecutive columns differ by at most one.

Note: the choice of integers and the direction is up to the answerer

If there are space characters in the input, demolish those first, all at once.

C
o

d      
e  ->     oC  ->         ->  ...
       de         
G        G          G
o        o          o
l        l          l
f        f        defoC

Rules

  • Standard loopholes are forbidden.
  • Trailing and leading newlines are allowed.
  • Your program may either print or return a string/equivalent.
  • Please explain the demolition algorithm (# of characters and direction) in your answer.

Some test cases to try

A
Programming
Code Golf
The quick brown fox jumps over the lazy dog

This is , so the submissions with the smallest byte counts in their languages win!

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1
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Program an Uncircularness Score

derivative of this challenge

Meta:

This is just a rough idea for a slightly different challenge. I have no idea how successfull it would be in the current state, so feel free to share your opinions and suggestions.

Your task is to program a mathematical function s, that takes a finite set A of points in the 2D plane, and outputs an uncircularity score s(A) that satisfies following properties:

  1. positive definiteness: If there is a circle or a straight line that contains all points of A, then s(A) = 0. Otherwise s(A) > 0
  2. It is surjective to the nonnegative real numbers, that means for every nonnegative real number r there is a finite subset A of the plane such that s(A) = r.

Scoring

You get one point for every of the following properties that your function (provably) has.

  • Translation Invariance: s is translation invariant if s(A) = s(A + v) for every vector v and for all A.
  • Scale Invariance: s is scale invariant, if s(A) = s(A * t) for every t≠0 and for all A.
  • Monotony: s is monotonous if s(A) ≤ s(B) for all A,B where A ⊆ B.
  • Circle Inversion Invariance: s is circle inversion invariant, if s(A) = s(f(A)) for all A with 0 ∉ A, where f(x,y) = (x/(x^2+y^2), y/(x^2+y^2)) is the circle inversion. (Here (x,y) represent the cartesian coordinates of a point in the plane.)
  • Triangle inequality: s satisfies the "triangle inequality" if s(A ∩ B) ≤ s(A) + s(B) for all A,B. (This is implied by Monotony.)
  • Reverse triangle inequality: s satisfies the "reverse triangle inequality" if s(A) + s(B) ≤ s(A ∪ B) for all A,B.
  • Continuity. s is said to be continuous if the function f(p) := s(A ∪ {p}) (mapping the a point p to a real number) is continuous using the standard absolute value on the real numbers, and the standard euclidean norm on the points of the plane.
  • More to come...
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  • \$\begingroup\$ Perhaps you should change the "non-negative real number" to "non-negative rational number" or "non-negative algebraic number" in part 2. If these functions are being produced by code it seems quite unreasonable to expect numbers that cannot be represented in computer memory to be output. \$\endgroup\$ – Post Rock Garf Hunter Aug 26 '17 at 17:13
  • 1
    \$\begingroup\$ @WheatWizard That's an interesting thought. Personally I quite like the idea of these properties working over the real numbers in theory, and the code implementing it to a desired accuracy of approximation, but I'm not sure if that's easier or harder to score/judge valid. \$\endgroup\$ – trichoplax Aug 26 '17 at 17:18
  • \$\begingroup\$ @trichoplax I will admit I am opposed to any "code must work in theory" rules in challenges. However any code that works in theory must also work on the reals or algebraics which allows us to have code that works not just in theory. \$\endgroup\$ – Post Rock Garf Hunter Aug 26 '17 at 17:22
  • \$\begingroup\$ @WheatWizard I agree that asking for testable solutions is much more satisfactory than "works in theory". \$\endgroup\$ – trichoplax Aug 26 '17 at 17:30
  • \$\begingroup\$ I guess "provably" needs to be defined in the context of the challenge. Will there be a defined method of testing or does this require a mathematical proof (in which case it leans more towards puzzling's scope). \$\endgroup\$ – trichoplax Aug 26 '17 at 17:32
  • \$\begingroup\$ @WheatWizard That is a good point that I did not think about. But I'd allow for limited precision implementations (i.e. floating point), because everything else would probably almost make the challenge impossible. \$\endgroup\$ – flawr Aug 26 '17 at 18:58
  • \$\begingroup\$ @trichoplax You'd need a lot of testcases to be convincing, but I think the participants should be able (they don't have to write down proofs) to provide good arguments for why a certain property is satisfied, just as we require any program to be actually doing what it is supposed to do. (we don't require proof of correctness either) \$\endgroup\$ – flawr Aug 26 '17 at 19:01
  • \$\begingroup\$ I think trichoplax makes a good point. I'm not sure how much this is really about code. It might be a better idea to post this on puzzling as a math puzzle where you need only define a function rather than some code. \$\endgroup\$ – Post Rock Garf Hunter Aug 26 '17 at 19:03
  • \$\begingroup\$ @WheatWizard Thanks. I think this could be made into a code-challenge (or code-golf), but it could also be made into a mathematical function challenge like you suggest. I can't guess which would be more interesting (or easier to define objectively) though. I suppose there's nothing stopping it being two challenges, one on each site... \$\endgroup\$ – trichoplax Aug 26 '17 at 20:18
  • \$\begingroup\$ Translation and scale invariance are easily added: translate to put the centroid at the origin and then if there's more than two points scale so that the furthest point from the origin is at distance 1 from the origin; then apply the original function. It might be possible to deliberately construct a noncircularity function such that this would destroy the surjectivity, but in practice I don't think the question would be harmed by assuming that all answers will be affine-invariant and simplifying the scoring system appropriately. \$\endgroup\$ – Peter Taylor Aug 27 '17 at 17:09
1
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Squeeze Out a Square Quine

...the bigger the better.

Task

Write a full program that is a proper quine (a piece of code that outputs itself without reading its source code). To make things more difficult, your code (and obviously the output) has to be in a form of a square, meaning that your code must consist of n lines of length n (not counting the newline to the line length).

Scoring

Your answer's score will be n, the side length of the square. The largest square quine wins. To avoid answers being padded to create arbitrarily large squares, your code must fail to be a proper quine if any single non-newline character is replaced by some other character that appears in the code. There must be, at minimum, two different non-newline characters in the code.


For example, if your code was...

abc
def
ghi

...and would output itself, your answer would be valid and its score would be 3.

A single trailing newline in the output is allowed.

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  • \$\begingroup\$ Replace single character at one places or multiple characters at multiple places? \$\endgroup\$ – user202729 Dec 27 '17 at 3:27
  • \$\begingroup\$ @user202729 I was thinking of single character at one place, but I'm not sure if it's sufficient. \$\endgroup\$ – Steadybox Dec 27 '17 at 3:31
  • \$\begingroup\$ If it's a quine then surely it should be a trailing newline in the code \$\endgroup\$ – Jo King Dec 27 '17 at 10:38
  • \$\begingroup\$ In that case it should be "the source code and the output may differ at the trailing newline". Also, if the restriction is "multiple character at multiple places" then it would be near impossible, because it's likely that there are multiple valid programs for each square size. \$\endgroup\$ – user202729 Dec 29 '17 at 6:13
  • \$\begingroup\$ I like the challenge but at a certain size, checking a solution for its validity will be impossible. What if someone posts a solution and failed to notice some weird replacement that would render that submission invalid? \$\endgroup\$ – ბიმო Dec 30 '17 at 14:13
  • \$\begingroup\$ @BruceForte Yeah, it's pretty problematic a challenge. I'm not sure what to do with it. Perhaps it would work better as code-golf. \$\endgroup\$ – Steadybox Jan 3 '18 at 6:00
1
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Shortest Path Distance

Uh oh! You want to get to the point (10,10) from the origin, but there are a whole bunch of boxes in the way! What is the length of the shortest path which avoids all of them?

Input

Your program should take a set of rectangles, defined by the coordinates of two opposite corners, as input; the format is up to you.

For example, a possible input might look like

[[(1,3), (5,2)], [(5,4), (7,5)]]

But you could also take it as

[(1,3), (5,2)]
[(5,4), (7,5)]

Or anything else, as long as it allows for unambiguous input.

These inputs would define the rectangles shown below: Minimum path length to A from (0,0): sqrt(10) + sqrt(130), approx 14.564

You can assume that all rectangles will have integer coordinates with x,y between 1 and 9 inclusive, which guarantees a possible path. You can also assume that no rectangles intersect in any way (that means no shared edges or vertexes).

Output

Your program/function must return the value of the shortest path from the origin to (10,10), have the absolute error at most 10-2 and measured using the euclidean metric.

In the example given above, 14.564 and 14.56 would be accepted, while 14.55 and 14.57 would not.

Example I/O

[[(1,3), (5,2)], [(5,4), (7,5)]] -> 11.40
[] -> 14.14
[[(1,1), (2,9)], [(9,2), (3,1)]] -> 14.28
[[(2,2), (1,1)], [(9,3), (8,5)], [(1,9), (2,8)]] -> 14.28 (Note: rounded up)
[[(9,1), (1,9)]] -> 18.11

Other Rules

Shortest code wins, no exploiting loopholes, yadda yadda yadda, you get the idea, it's code golf.

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  • \$\begingroup\$ The taxicab (Manhattan) distance is always 20. I don't know Taxi PL, but I suppose it is not too hard to write. \$\endgroup\$ – user202729 Nov 15 '17 at 4:58
  • \$\begingroup\$ @user202729 Not true in the case that backtracking is required. \$\endgroup\$ – Esolanging Fruit Nov 15 '17 at 5:30
  • \$\begingroup\$ Using taxicab distance instead of manhattan distance makes the challenge slightly easier and more accessible to languages that can't handle floating-point well. \$\endgroup\$ – Esolanging Fruit Nov 15 '17 at 5:31
  • \$\begingroup\$ @Challenger5 Why does output 20 require backtracking??? \$\endgroup\$ – user202729 Nov 15 '17 at 9:18
  • \$\begingroup\$ @user202729 If backtracking is required (e.g. the blocks form a spiral shape), then the taxicab distance will be >20. \$\endgroup\$ – Esolanging Fruit Nov 15 '17 at 16:56
  • \$\begingroup\$ @Challenger5 No, all rectangles will have integer coordinates with x,y between 1 and 9 , which means that you can always move (0, 0) → (0, 10) → (10, 10), which have taxicab distance = 20. \$\endgroup\$ – user202729 Nov 16 '17 at 1:13
  • \$\begingroup\$ Ready for posting to main? \$\endgroup\$ – user202729 Jan 7 '18 at 13:22
  • 1
    \$\begingroup\$ Alternatively, you could ask not for the length of the shortest path but for the actual path! \$\endgroup\$ – flawr Jan 8 '18 at 13:21
  • \$\begingroup\$ @flawr ... Isn't that harder? I don't know... \$\endgroup\$ – user202729 Jan 10 '18 at 10:50
  • \$\begingroup\$ @user202729 How else would you calculate the length of a shortest path if not by explicitly finding a shortest path? \$\endgroup\$ – flawr Jan 10 '18 at 10:53
  • \$\begingroup\$ What if we have two rectangles that touch eachother but do not share edges or vertices, like [(0,0),(2,1)] and [(1,1),(3,2)]? Also: Can we e.g. assume a certain representation of the rectangles (i.e. always first the top left vertex, then the bottom right)? \$\endgroup\$ – flawr Jan 10 '18 at 10:56
  • \$\begingroup\$ @flawr Unfortunately, it seems that the OP abandoned this... Also, Dijkstra algorithm. (it calculates the shortest distance from source to all points, so by triangle inequality you can deduce the path, but it definitely takes more code than just outputting the distance) \$\endgroup\$ – user202729 Jan 10 '18 at 11:00
1
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Easy Incenter


The incenter of a triangle is the intersection of the triangle's angle bisectors. This may sound complicated, but the coordinate formula for incenter is somewhat simple (reference). The specifics of the formula do not matter much for this challenge.

The formula requires lengths of sides, so it can be very messy for most triangles with integer coordinates because lengths of sides tend to be square roots. For example, the incenter of the triangle with vertices (0,1), (2,3), and (1,5) is ((2*sqrt(17)+2*sqrt(2))/3,(sqrt(5)+3*sqrt(17)+10*sqrt(2))/3).

A triangle with integer coordinates has an incenter with rational coordinates in a few cases. One of these cases is when the side lengths are all integers.

Challenge

Given a positive integer input n, your program may either:

  • output the n-th ordered pair of points A,B which meet the "easy incenter" condition.
  • output the first n ordered pairs of points A,B which meet the "easy incenter" condition.

where the "easy incenter" conditition (sufficient, but may not necessary (I(user202729) didn't try to prove it), for the incenter of the triangle OAB to have rational coordinates) is:

  • point A meets x>y>0.
  • point B meets y>x>0
  • points A and B have integer coordinates.
  • If O is the origin, the distances OA, OB, and AB are integers.

The pairs of points may be generated in any order.

Example

The points B(24, 7) and A(12,16) work because:

  • point A meets x>y>0 because 24>7>0
  • point B meets y>x>0 because 16>12>0
  • points A and B have integer coordinates
  • OA = 20, OB = 25, and AB = 15, so the three distances are integers.

Note

Not all solutions yield right triangles OAB. One example is A(32, 24), B(27, 36).

Not all solutions have A and B on the same horizontal/vertical line. One counter-example is B(12, 16), A(24, 7)

Input/Output

Input and Output is flexible as usual.

The input is a non-negative integern.

The output is either

  • a representation of a list of the first n pairs of points
  • a representation of the n-th pair of points

The ordering based on n may be done in any manner, as long as it outputs all possible points "eventually" given "infinite" time.

Example Output:

Given an input n=10, a program may output

(15, 8),(6, 8)
(8, 6),(8, 15)
(16, 12),(5, 12)
(12, 5),(12, 16)
(35, 12),(5, 12)
(12, 5),(12, 35)
(16, 12),(7, 24)
(24, 7),(12, 16)
(16, 12),(9, 12)
(12, 9),(12, 16)

Sandbox

  • Is the problem statement clear?
  • Does the ordering flexibility make sense to readers?
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  • \$\begingroup\$ ... each point may only be generated once? Can you allow output infinite sequence? \$\endgroup\$ – user202729 Jan 10 '18 at 11:26
  • \$\begingroup\$ That is, if there are two pairs (A,B) and (A',B') have the same incenter (with O), should they appear in the sequence once or twice? \$\endgroup\$ – user202729 Jan 10 '18 at 11:27
1
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Any comments for improvement would be appreciated.
Should I choose a harder function? (maybe "Is this binary number prime?")
Or maybe not harder, but some other decision problem suggestion?

Majority function, a non-uniform computing challenge

Non-uniform computing is a class of computing where a different procedure can be specified for each input size of a problem. This allows discussing complexity of languages that are only straight line computations (no looping constructs), yet which are powerful enough to compute any fixed input size function a Turing machine can compute. It also allows taking advantage of algorithms that may work well if only you could tweak a parameter for each size (even if the parameter is difficult to compute) or where there are only a small number of exceptions in each input size (so checking those exceptions then using the algorithm succeeds).

Goal:

Write a program or function which, given an input length, outputs an If-Then-Else sequence (defined below) which determines if greater than half the inputs are 1 (the majority function).

This is . Your score will be:

G20 + 4*G5 + 10*G2 + L

Where L is the size of your submission in bytes, and G20 is the length of the generated If-Then-Else sequence for size=20 (length being defined as number of If-Then-Else statements). Similarly G5 and G2 are the lengths for the generated programs for size=5 and size=2 respectively. The lowest score wins.

This is in some sense an "inception" code golf. You will be judged on the length of your program as well as the length of the programs it generates.

To prevent submissions that just loop over all possible ITE sequences till it finds the smallest one that works, entries need to provide the G20, G5, G2 values along with the code submission for it to be a valid entry. As the number of possible sequences quickly becomes infeasible to search, this should eliminate raw brute forcing.

If-Then-Else "programs"

An If-Then-Else (ITE) statement is a logical statement of the form:

if A then B else C

The logical value of this statement is referred to as the "output", and the values A, B, and C are the "inputs" of the statement. To turn this into a formatted language, a file (or string) describing an ITE program will be a series of lines that contain:

<input_term> <space> <input_term> <space> <input_term>

Where an input_term is one of:

  • '0'
  • '1'
  • 'I' <decimal_number>
  • 'Q' <decimal_number>

The values 0 and 1 are Boolean false and true respectively. The value of I(number) is the value of the input at index 'number'; for example I3 = Input #3 (input numbering starts at zero). The value of Q(x) is the result of ITE statement number 'x' (again, numbering starts at zero).

The result of an ITE program is the output of its last statement.

Example ITE program

Here is a simple interpreter for ITE programs, written in python: ite.py

This interpreter has some additional features like comments (start a line with #) and custom output names (start line with <name>:) which are useful when playing with some ideas by hand. If you choose to utilize those features in your generated ITE programs, that's fine, although I'm not sure how that would help. This will be considered the defacto standard for the ITE language for this competition.

Here is an example program: parity4.ite

I0 0 1
I1 Q0 I0
Q1 0 1
I2 Q2 Q1
Q3 0 1
I3 Q4 Q3

As its name suggests, this is the parity function for input size 4. It returns 1 if the 4 inputs bits have an odd number of 1s, otherwise it returns 0. Here is an example of testing it on some values.

$ python ite.py parity4.ite 0110
0
$ python ite.py parity4.ite 0111
1
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  • \$\begingroup\$ Welcome to PPCG, this is a great challenge! I haven't put much thought into it but what's the reason for such a high weight on G2? G2 could become a special case for some clever approaches (just a guess) in which case it would be quite a hefty penalty (or they would have to hardcode its output). \$\endgroup\$ – ბიმო Jan 17 '18 at 15:06
  • \$\begingroup\$ @BMO I think the required number of statements may scale roughly proportional to the number of inputs. So I was trying to "weight" them evenly. Now that you mention it, G2=1 is possible, so maybe that is not a good one. \$\endgroup\$ – PPenguin Jan 17 '18 at 16:59
  • \$\begingroup\$ I was hoping to test both a "small" input size (easy to solve by hand), "medium" input size (hopefully possible to at least follow by hand), and "large" input size (probably too big to follow by hand). I guess G2 is too small. Maybe it would be better to just check G20 and G5? \$\endgroup\$ – PPenguin Jan 17 '18 at 17:04
  • \$\begingroup\$ I haven't tried it yet, so it's difficult to say but G2 is not very interesting and it has quite a significant weight. I didn't mean that you should exclude it, but maybe it's a good idea or at least change the weights - maybe using G3 would be an option as well, I think it's a good idea to use small ones that are verifiable by hand. Tbh. finding out a good weighting system is not easy, maybe others with experience could help you out there? \$\endgroup\$ – ბიმო Jan 17 '18 at 18:06
1
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Solve the Square-Sum problem

Based on these (very good) Numberphile videos:

The Square-Sum problem and its extra footage.

The Problem:

Given a list of integer numbers [1,n] where n≥15; n≠18, 19, 20, 21, 22, 24, your task is to arrange those numbers in a way such that the sum of two consecutive numbers is a square number.

Example for n=15:

Original sequence: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Square-sum of it: 8 1 15 10 6 3 13 12 4 5 11 14 2 7 9
                   | |  |  | | |  |  | | |  |  | | |
                  3² 4² 5² 4²3²4² 5² 4²3²4² 5² 4²3²4²

This problem can be solved by creating a graph of every sum of two numbers in the sequence that result in a square number:

Graph

From that graph, it's possible to find its Hamiltonian Path:

Hamiltonian Path

This path, if existing, is the solution to the square-sum problem.

Rules:

---Under Construction---

Sandbox:

  • Suggestions?
  • Dupe?
  • Test cases are under construction
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1
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Word ladder

A word ladder is a puzzle where the aim is to create the smallest sequence of steps between two fixed words (a starting word and a target word), where each step changes one letter to produce a new word. All the intermediate words must be recognised in a dictionary (which will be supplied).

If the target word is longer than the starting word, a step may add a letter at any position instead of changing one; if it's shorter than the starting word, a step may remove a letter instead of changing one.

Examples:

HAND
BAND
BOND
FOND
FOOD
FOOT
FINGER
FINER
FINE
TINE
TONE
TOE
EYES
EYED
DYED
DEED
TEED
TEND
TENT
TENTH
TEETH

The challenge

Write a program or function which accepts a dictionary of words and the two fixed words (i.e. a starting word and a target word), and produces an ordered list of intermediate words following the rules above. You may choose to output the starting word, the target word, both, or neither.

You may use any of the standard methods of input and output, and must not bypass the rules with any of the standard loopholes.

Scoring

(I need some help with this part).

The score is the number of dictionary lookups your program makes during a test run (or average of several test runs, if it's not deterministic) on a set of inputs with a simple English dictionary. Q: does this test set need to be prepared and included in the question?


Sandbox questions

I don't really want to make this a , as we'll just end up with simple brute-force algorithms; I really want to see creative use of the dictionary, either by pre-processing or perhaps by ordering candidate words.

Is there a way we can define a "dictionary lookup" and somehow separate the word generation/validation from knowledge of the fixed words, without making assumptions that the language has functions or other methods of isolating code?

Can we require the dictionary to be a separate process, and provide a reference implementation? I don't think we can, without excluding languages without reasonable inter-process communication (I'm thinking of PostScript, possibly JavaScript, and microcomputer BASIC).

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  • \$\begingroup\$ I think this could be a test-battery challenge, with both different words and different dictionaries as tests. Different dictionaries are needed to avoid languages searching in a build-in English dictionary and only validating their finds in the provided dict. \$\endgroup\$ – Laikoni Jan 18 '18 at 14:33
  • \$\begingroup\$ I mentioned English because I would like entries to be able to use heuristics to choose a good way to search first - perhaps simple vowel/consonant rules, perhaps something more sophisticated (digraph tables?). Promising an arbitrary dictionary would prevent that kind of thinking, especially if there's nothing to say that "XYQQZ" won't be in it. @Laikoni, could your concern be addressed by a rule to outlaw built-in dictionaries? ("You must use only the supplied dictionary", for example) \$\endgroup\$ – Toby Speight Jan 18 '18 at 14:42
  • \$\begingroup\$ I see your point and also like the idea to incentive some form of language processing. However banning built-in dictionaries comes with the general problem of banning built-ins, namely what counts as a built-in dictionary. Just from the top of my head, if the scoring is only about look-ups in a provided English dictionary and built-in dicts as well as adding a dict in to your code are a banned, how about assessing built-in texts to sample a rough dictionary? I know that some languages can asses their own documentation from within the language itself. \$\endgroup\$ – Laikoni Jan 18 '18 at 14:52
  • \$\begingroup\$ Altogether, it might be a good idea to make the score a weighted combination of code length and the number of lookups. \$\endgroup\$ – Laikoni Jan 18 '18 at 14:53
  • \$\begingroup\$ How would you define "dictionary lookup"? A program may "copy" the dictionary and count that as one dictionary lookup. A check whether a word is in the dictionary? /// Also for the problem of built-in dictionary the solution is really simple: scramble the letters, and use different languages, or just use a random dictionary. For example bunny with the scramble b->x, u->y, n->q, y->z may well become xyqqz, and of course it won't change the challenge. /// What if there is no solution? \$\endgroup\$ – user202729 Jan 20 '18 at 4:48
  • \$\begingroup\$ The core question is essentially codegolf.stackexchange.com/q/2478/194 so as code-golf I would vote to close this as a dupe. But with the current rules (and in particular the requirement to produce the smallest sequence of steps) I'm not sure how viable the proposed scoring system is. Basically answers will have to be equivalent to A* and there aren't that many admissible heuristics. In particular, heuristics for whether something is a word or not would only meet spec if they encode the entire dictionary. \$\endgroup\$ – Peter Taylor Jan 20 '18 at 9:07
  • \$\begingroup\$ Thanks @Peter and others. I didn't manage to find the code-golf version, so the link is useful. I obviously need to think a bit further about the rules and scoring (in fact, I posted to Sandbox hoping to garner further ideas). I'm starting to agree that the dictionary can be abstract if the answer is allowed to generate heuristics from it before processing inputs. If I get any better ideas, I'll come back to this and update it. \$\endgroup\$ – Toby Speight Jan 22 '18 at 8:47
  • \$\begingroup\$ The obvious way to address the A* issue is to not require it to be a shortest path, but then you have to balance path length vs dictionary queries in the score, which is going to be messy. \$\endgroup\$ – Peter Taylor Jan 22 '18 at 18:32
  • \$\begingroup\$ About "dictionary lookup"... check if a word in the dictionary using a black-box function seems good enough. Hopefully it won't make programs take awfully long time to run. / Restrict to a-z? Adding Unicode would be impossible to guess. \$\endgroup\$ – user202729 Jan 23 '18 at 7:34
1
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Objective

Given a 2D array (of x by x size), write a program or function to alternatively shift elements of the array along the anti-diagonals. (anti-diagonals are right to left, top to bottom). (first anti-diagonal moves down second anti-diagonal moves up with elements wrapping when they reach the end of the anti-diagonal)

Example

a b c d
e f g h
i j k l
m n o p

Will become:

a e i g
b c j n
f m h o
d k l p

I will follow the tradition of selecting the shortest working code as the best answer

**edited for user202729 suggestion

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  • 1
    \$\begingroup\$ Should it be "antidiagonals"? \$\endgroup\$ – user202729 Jan 22 '18 at 13:58
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    \$\begingroup\$ Dupe? \$\endgroup\$ – Peter Taylor Jan 23 '18 at 8:22
  • \$\begingroup\$ @PeterTaylor im trying to shift the anti-diagonals not reverse them \$\endgroup\$ – Karan Shishoo Jan 23 '18 at 8:55
  • \$\begingroup\$ So is the question I linked. \$\endgroup\$ – Peter Taylor Jan 23 '18 at 9:22
  • \$\begingroup\$ @PeterTaylor look at the 4x4 test case and compare it with mine. I have a different result for that case. I am asking people to shift the elements along the anti diagonals, not to rotate the anti diagonals themselves. \$\endgroup\$ – Karan Shishoo Jan 23 '18 at 9:39
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    \$\begingroup\$ Although the specification of this proposal is not especially clear, I think that the only difference is that the question I linked rotates all anti-diagonals in the same direction whereas this rotates them alternately in one direction and the other. \$\endgroup\$ – Peter Taylor Jan 23 '18 at 12:18
  • \$\begingroup\$ @PeterTaylor i will again clarify i am not rotating them i am shifting them. for example if an anti diagonal was say - 1 2 3 4 5 6 my outcome would be: 6 1 2 3 4 5 (or 2 3 4 5 6 1 depending on which antidiagonal it was) instead of 6 5 4 3 2 1 (which is the rotation of that antidiagonal) \$\endgroup\$ – Karan Shishoo Jan 23 '18 at 12:27
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    \$\begingroup\$ Shifting and rotating are different words for the same thing: the only difference is that rotating makes it clearer that it wraps round rather than losing one element from one end and introducing a new one at the other end. You're thinking of reversal. \$\endgroup\$ – Peter Taylor Jan 23 '18 at 12:38
  • \$\begingroup\$ @peter Taylor your right... I goofed up while matching the arrays thanks for the catch \$\endgroup\$ – Karan Shishoo Jan 23 '18 at 13:03
1
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Shape sequence sums

0. DEFINITIONS

For the purposes of this challenge, a sequence refers to a list of numbers whose absolute values increment in steps of 1. A sequence begins with a value of 1, 0, or -1.
A positive sequence refers to the natural numbers: 1, 2, 3, 4, and so on.
A negative sequence refers to the additive inverses of the natural numbers: -1, -2, -3, -4, and so on.

1. CHALLENGE

Given an integer n, return a list of sequences such that the sum of all the numbers in the list is equal to n. Sequences must alternate in sign (see test cases). Solutions must produce the list with the fewest sequences; that is, the sign should change a minimal number of times. (Read: Don't do 1, 2, -1 over and over again.) The resulting list must be flat, not nested. The shortest working solution wins.

2. TEST CASES

 17: 1, 2, 3, 4, 5, 6, -1, -2, -3, 1, 2, -1
 18: 1, 2, 3, 4, 5, 6, -1, -2
 19: 1, 2, 3, 4, 5, 6, -1, -2, 1
 21: 1, 2, 3, 4, 5, 6
-21: -1, -2, -3, -4, -5, -6
 -5: -1, -2, -3, 1
  0: 0 or [] (null set)

You may choose to begin each sequence with 0 instead of 1 or -1. However, if you do this, every sequence must begin with a zero, not just the positives, the negatives, the first sequence, or any other strict subset. This also means that input 0 requires a list containing a single 0.

 17: 0, 1, 2, 3, 4, 5, 6, 0, -1, -2, -3, 0, 1, 2, 0, -1
  0: 0

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  • 1
    \$\begingroup\$ Is there any requirement that answers provide an output with the smallest number of sequences, the fewest total numbers, or just any list of numbers which can be partitioned into alternating positive and negative sequences? I might recommend some restriction else repeating 1, 2, -1 will eventually reach any number \$\endgroup\$ – Kamil Drakari Jan 23 '18 at 20:48
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    \$\begingroup\$ Can the output for 0 be [], ie. is the empty sequence a sequence? \$\endgroup\$ – ბიმო Jan 23 '18 at 20:49
  • \$\begingroup\$ @Kamil & BMO: Thanks, I've updated to address these. Also added requirement that list be flat. \$\endgroup\$ – Joe Jan 23 '18 at 21:49
  • \$\begingroup\$ Why do you require flatness? \$\endgroup\$ – CalculatorFeline Jan 24 '18 at 1:07
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    \$\begingroup\$ Idk, I just feel like it. I like flat lists :P \$\endgroup\$ – Joe Jan 24 '18 at 2:32
  • \$\begingroup\$ Title suggestion: "Shape sequence sums" \$\endgroup\$ – Esolanging Fruit Jan 24 '18 at 5:31
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    \$\begingroup\$ 1. I think that this question would be a lot simpler to understand if it were rewritten in terms of triangle numbers rather than sequences. 2. Most of the test cases are wrong. Every integer can be produced with just two sequences. \$\endgroup\$ – Peter Taylor Jan 24 '18 at 12:57
1
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Different tasks, same characters, level 2

In this challenge, you need to solve 3 different tasks using the same set of characters. You can rearrange the characters, but you can't add or remove characters.

The winner will be the submission that solves all tasks using the smallest number of characters. All tasks must be solved in the same language.

Note that it's the smallest number of characters, not the smallest number of unique characters.

Twist: If one or more characters can be removed from a script without breaking it, then your submission is disqualified. This means that comments are out of the picture, as well as long variable names to get the character counts to match up.

You do not have to prove that it's impossible to remove characters and still have a functioning script, but you should try to make it impossible. If nobody bothers to look at it, then your submission is valid. If nobody sees a way to remove one or more characters, then your submission is valid. If however, someone looks at your post and sees something that can be removed without breaking it, then your submission is invalid.


Tasks:

I'll create 3 tasks that are fairly simple typical code-golf tasks.


So, what do you think about the idea?

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    \$\begingroup\$ I don't think the twist is going to be easily enforceable. For any program longer than a dozen bytes the computation time on checking that it fits this requirement becomes immense. \$\endgroup\$ – Post Rock Garf Hunter Nov 28 '17 at 22:53
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    \$\begingroup\$ I think I'll let the burden of disproof (is that a thing?) lie with the viewers. Those posting answers will do their best to make it impossible to remove fluff without breaking it. If someone finds a way to do it, then the submission is invalid. If every character is there for a reason (it has a function) then it should be fairly hard to find something that can be removed that OP wouldn't already know of (for instance reversing something twice). It's not CNR, but if people find ways to golf an answer without breaking it, then it's invalid. \$\endgroup\$ – Stewie Griffin Nov 29 '17 at 7:22
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    \$\begingroup\$ If nobody bothers to look at it, then your submission is valid. If nobody sees a way to remove one or more characters, then your submission is valid. If however, someone looks at your post and sees something that can be removed without breaking it, then you submission is invalid. \$\endgroup\$ – Stewie Griffin Nov 29 '17 at 7:27
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    \$\begingroup\$ I think that would be generally effective; in practical languages with longer code, fluff is easier to spot in the syntax, and in recreational golfing languages the shorter code will be easier to manually check. \$\endgroup\$ – FlipTack Nov 29 '17 at 8:17
  • \$\begingroup\$ So if there exists a subsequence of the original program that also do the task the original program does (not necessarily equivalent), and there is someone point it out, the submission is invalid? \$\endgroup\$ – user202729 Nov 29 '17 at 13:32
  • \$\begingroup\$ Do the removed characters need to be contiguous? \$\endgroup\$ – AdmBorkBork Nov 29 '17 at 14:41
  • \$\begingroup\$ @AdmBorkBork no. It's to avoid stuff like unnecessary long variable names etc. And then you'd need to remove character multiple places... \$\endgroup\$ – Stewie Griffin Nov 29 '17 at 15:53
  • \$\begingroup\$ Cool! I've had an idea like this, but using different languages to solve the same task (with the exact same twist) \$\endgroup\$ – Sanchises Jan 25 '18 at 21:15
  • \$\begingroup\$ @Sanchises you may go ahead and post it if you'd like! Either this version or a polyglot version. :) Interested? \$\endgroup\$ – Stewie Griffin Jan 25 '18 at 21:35
  • \$\begingroup\$ Oh you may have this one. I'm still stuck on thinking of one task.... \$\endgroup\$ – Sanchises Jan 25 '18 at 21:36
  • \$\begingroup\$ You have a very nice track record when it comes to challenges, so I'd like to see it :) \$\endgroup\$ – Stewie Griffin Jan 25 '18 at 21:37

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