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This "sandbox" is a place where Code Golf users can get feedback on prospective challenges they wish to post to main. This is useful because writing a clear and fully specified challenge on your first try can be difficult, and there is a much better chance of your challenge being well received if you post it in the sandbox first.

Sandbox FAQ

Posting

To post to the sandbox, scroll to the bottom of this page and click "Answer This Question". Click "OK" when it asks if you really want to add another answer.

Write your challenge just as you would when actually posting it, though you can optionally add a title at the top. You may also add some notes about specific things you would like to clarify before posting it. Other users will help you improve your challenge by rating and discussing it.

When you think your challenge is ready for the public, go ahead and post it, and replace the post here with a link to the challenge and delete the sandbox post.

Discussion

The purpose of the sandbox is to give and receive feedback on posts. If you want to, feel free to give feedback to any posts you see here. Important things to comment about can include:

  • Parts of the challenge you found unclear
  • Comments addressing specific points mentioned in the proposal
  • Problems that could make the challenge uninteresting or unfit for the site

You don't need any qualifications to review sandbox posts. The target audience of most of these challenges is code golfers like you, so anything you find unclear will probably be unclear to others.

If you think one of your posts requires more feedback, but it's been ignored, you can ask for feedback in The Nineteenth Byte. It's not only allowed, but highly recommended! Be patient and try not to nag people though, you might have to ask multiple times.

It is recommended to leave your posts in the sandbox for at least several days, and until it receives upvotes and any feedback has been addressed.

Other

Search the sandbox / Browse your pending proposals

The sandbox works best if you sort posts by active.

To add an inline tag to a proposal, use shortcut link syntax with a prefix: [tag:king-of-the-hill]. To search for posts with a certain tag, include the name in quotes: "king-of-the-hill".

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Tamagochi

I can't believe there has never been a Tamagochi challenge on code golf! Edit: There has never been a Tamagochi challenge, but there was a Tamagotchi, whatever that is.

Rules:

  • The output must begin with "You found an egg!"
  • Text-adventure style tamagochi.
  • Prints status changes to stdout.
  • Three actions at any moment:
    • Rub/pet
    • Feed
    • Info
  • At the start of the program, you must wait for an egg to hatch.
  • If not fed for 4 minutes, pet moves down a hunger status
  • If fed twice in 4 minutes, pet moves up a hunger status.

Accommodations for golfing languages:

  • The language can't access system time:
    • You now have to implement a command wait x, that waits for x minutes.
    • Each newline advances the time by 30 seconds.
  • The language can't prompt:
    • Read the input from a file, and provide the file you used to test.
  • The language can't read from files:
    • Well, that sucks. Maybe another lang?

Info:

Shows the following:

  • Pet name
  • Pet age
  • Pet hunger
  • Pet happiness

Pet Statuses/behavior:

Initial conditions: Hungry (0 food), Sad (0 pets), Age: 0s

Happy: The pet is happy. Transitions to sad in 3 minutes if no interaction.
Sad: Pet needs a petting within 2 minute or becomes sick. Takes t/15 pats to return to happy, where t is in seconds.

Hungry: Pet needs to be fed within 2 minutes, or becomes sick.
Overfed: Pet needs to not be fed more than twice in 4 minutes, or becomes sick. If currently sick and fed by player, advance death timer by 1 minute.
Fed: Reverses the death timer if not sad or dead.

Old: Pet's age + time not in "Happy" and "Fed" > 1h
Sick: Pet will die in 5 minutes, if status causing sick is not cured. If sick with no status, remove sick in one minute.

If a pet dies, prints name, condition(s) and time.
    "Mr. Johnson died of old age, 1h:23m"
    "Tamagotchi died of sadness 0h:7m"

The smallest Tamagochi wins.

Example

The following is an example simulation, where > could be a prompt, or other input as mentioned in accommodations.

Whenever a pet gains or loses a status, it must output {pet name} is no{w | longer} {status}

Termagotchi
You found an egg!
...
The egg is hatching!
...
The egg has hatched!
What would you like to name your pet?
> Mr. Johnson
Mr. Johnson is now hungry.
Mr. Johnson is now sad.
> Info
Mr Johnson
Age: 13s
Hungry, Sad
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
Mr. Johnson is now fed.
Mr. Johnson is now happy.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
...
Mr. Johnson is now sad.
...
Mr. Johnson is now sick.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
> Pet
You petted Mr. Johnson.
Mr. Johnson is now happy.
> Info
Mr Johnson
Age: 14m:27s
Happy, Sick
> Feed
You fed Mr. Johnson.
...
Mr. Johnson is now not sick.
...
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
Mr. Johnson is now overfed.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
Mr. Johnson is now sick.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
> Feed
You fed Mr. Johnson.
Mr. Johnson died of overfed, 23m:11s
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  • 2
    \$\begingroup\$ This isn’t TikTok, there’s no need to say “unalive”. There’s no special algorithm here (except HNQ); it just shows the most recently modified or answered question first. \$\endgroup\$
    – Bbrk24
    Sep 16 at 22:22
  • 2
    \$\begingroup\$ Also keep in mind that popcons have been soft-banned here and don’t tend to be seen favorably. \$\endgroup\$
    – Bbrk24
    Sep 16 at 22:23
  • 3
    \$\begingroup\$ This is heavily underspecified \$\endgroup\$
    – pajonk
    Sep 17 at 6:17
  • 1
    \$\begingroup\$ Things to avoid when writing challenges: Bonuses in code golf. It's also unclear how any of the rules should be implemented in a program. \$\endgroup\$ Sep 17 at 9:04
  • \$\begingroup\$ @pajonk Is this still underspecified? \$\endgroup\$ Sep 17 at 19:15
  • 1
    \$\begingroup\$ Still pretty underspecified. The introduction ("You found an egg!...") is unspecified, it's unclear whether the ">" prompt is necessary, the initial values for age/hunger/happiness are unspecified, none of the status change outputs are specified. \$\endgroup\$ Sep 17 at 22:46
  • \$\begingroup\$ Also, the example suggests that languages must have both a way to "prompt" for input during the program's run and access to system time, which excludes certain classes of languages. Not that this is necessarily a bad thing, just something to consider. \$\endgroup\$ Sep 17 at 22:49
  • \$\begingroup\$ Also, related question \$\endgroup\$ Sep 17 at 22:53
0
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Digits of Infinity (computing A206636)

In this PDF, https://www.vixra.org outlines a way to find the last \$ n \$1, 3 digits of infinity and a method to do so.

Let us define the infinity sequence2, taking the function \$ f(n) \$.

\$ f(1) = 2^2 = 4\$
\$ f(n) = 2^{f(n-1)}\$

Starting from \$ f(3) \$, the last \$ n - 2 \$ digits are the same for all \$ f(n) \$ numbers with \$ n \gt 2 \$ in this sequence.

Your task: given an integer \$ n \$ through standard I/O, return the last \$ n \$ digits of infinity.

Input

n, an integer (or the closest to one in your language), \$ \ge 1 \$ (if 1-indexed; you can also take a zero-indexed input, but the number of digits outputted will then have to be n+1). Most programs will probably compute \$ f(n+2) \$ for the output, which is permissible (but not compulsory; I'd love to see any other creative way for large n, though no bonus points). Input will be less than or equal to the highest number n such that your program can compute in under 2 minutes.

Output

The last n (or n+1 if 0-indexed) digits of infinity (through accepted I/O).

Test Cases:

Input -> Output

1 -> 6
2 -> 36
3 -> 736
10 -> 3432948736
22 -> 8098615075353432948736

This is , so shortest answer wins!

Note: my bet is that most programs that are well-golfed will not be able to calculate these digits easily; \$ f(5) \$ has over 19000 digits! However, if your program, given infinite time, infinite memory, and unbounded integer types, can compute this, it's valid.

1. Apparently, the digits of infinity are infinite.
2. This is OEIS A206636.
3. I do not believe in this method, I just picked it out because I thought it would make for a good challenge.

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  • 3
    \$\begingroup\$ Infinity is not a number. Therefore, it cannot have digits. The paper seems a bit sketchy to my knowledge of different infinities. \$\endgroup\$
    – Seggan
    Sep 14 at 15:32
  • 2
    \$\begingroup\$ What are the differences between viXra.org and arXiv.org? "Warranted or not, it has a reputation of being an alternative to arXiv for cranks and to host a lot of junk science, fake proofs or even outright nonsense" \$\endgroup\$ Sep 14 at 23:32
  • 5
    \$\begingroup\$ I would suggest it be named differently, like "A206636". This removes the dependency on viXtra. I also agree with the above, infinity is a concept, not a number, unless they are talking about p-adics, although that's unlikely. \$\endgroup\$ Sep 15 at 1:01
  • 2
    \$\begingroup\$ I'd upvote because this would be a challenge that really punishes naive approaches, due to the tetrative growth. Also, is there a limit on the inputs? Because -1 is also an integer, and so is 2^127-1 \$\endgroup\$ Sep 15 at 1:05
  • 2
    \$\begingroup\$ This paper shows such a violent misunderstanding of infinity it's comical. \$\endgroup\$
    – ATaco
    Sep 15 at 1:16
  • \$\begingroup\$ Alright, everyone; I don't actually believe that the digits of infinity can be calculated with such a simple sequence; I just chose this because I just thought the sequence was an interesting one. And yes, there is a limit; only from 1 may the inputs be passed. \$\endgroup\$ Sep 15 at 4:04
  • 1
    \$\begingroup\$ I my opinion allowing solutions that compute f(n+2) and then take the last n digits, makes the challenge less interesting. I would suggest some requirement for reasonable running time (e.g. "the program has to be able to compute the result for n=10 in less than a minute on a modern computer"). \$\endgroup\$
    – bsoelch
    Sep 15 at 11:23
  • \$\begingroup\$ Would it be allowed that the program only works up to n=18 (largest result that fits in a signed 64-bit integer), or do you require big-int support \$\endgroup\$
    – bsoelch
    Sep 15 at 17:14
  • \$\begingroup\$ @bsoelch about your earlier comment; it's a mistake with my framing: I meant that most trivial programs will do this, and it's not compulsory (that would be a non-observable requirement), and the second comment, I believe my last part makes the ruling on that clear (if your code *practically* can compute up till n=18, and theoretically can compute for any n, then it's valid) \$\endgroup\$ Sep 17 at 9:36
  • \$\begingroup\$ If infinity did indeed have digits, it would have to be an infinite stream of 0s, since it has to be a multiple of every power of 10. \$\endgroup\$ Sep 25 at 7:44
  • \$\begingroup\$ False; I could make a bigger infinity by adding 1. \$\endgroup\$ Sep 25 at 9:05
  • \$\begingroup\$ @UndoneStudios but that can’t be an infinity, because it is not divisible by 10. Infinity must be an “integer” multiple of every single number. \$\endgroup\$ Sep 25 at 10:21
  • \$\begingroup\$ You are assuming a value of infinity as a value; it is not; but the point is it cannot be an infinite stream, because that would make it indivisible by... it's a complicated topic, and that's the reason why we don't consider *infinity* to be a value, which I already explained in my earlier comment. Also, such a definition would be recursive and would include itself as well, causing issues in calculation. \$\endgroup\$ Sep 25 at 13:02
  • \$\begingroup\$ Your definition is one of multiple definitions, but it is absolutely not the definition I hold when thinking of infinity as having digits. \$\endgroup\$ Sep 25 at 13:03
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really shitty sloppy wip but i just want to start this post so that i can be past the first hurdle next time i look at this. feel free to ask anything just know this is like step 0;

implement this weird algorithm which will be given a more descriptive name

here is the algorithm in js:

f = x => x.reduce((a, b) => [b, ...f(a)], [])

implement this program in your language of choice;

rules

it has to run in faster time complexity than this naive implementation, which is like, exponential i think.

shortest code wins

notes: i might make it so you only have to output the result of running this on range lists like [0 1 2 3 ... n], so only the permutation that the algorithm results in, rather than for arbitrary input, since generating the permutation is one thing and then applying it is another

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Find an eigenvalue of a 3x3 Matrix

Write a program of function that given a 3x3 matrix as input outputs an Eigenvalue of that matrix

Examples/Test-cases:

[[1,0,0],[0,1,0],[0,0,1]]    -> 1.0
[[1,2,3],[4,5,6],[7,8,7]]    -> -0.22165260583979401
[[5,3,4],[2,6,7],[0,4,10]]   -> 1.887934888738847
[[-3,2,5],[0,6,7],[0,0,-10]] -> -3.0
[[0.2915131378594483, 0.41257765061649787, 0.9253019986284902], [0.21696836678486353, 0.5331738150906348, 0.3247753676328128], [0.20672257620794932, 0.3453811902047663, 0.4771215769253173]] -> -0.03135020654472091
[[0.2447175622890705, 0.38693057299215594, 0.8576673327257548], [0.47607062999761074, 0.1126298515845301, 0.9707452917395663], [0.7524371727807047, 0.502675518344781, 0.6725321940186385]] -> -0.2768104753672565

Rules

  • You can take the matrix in any convenient format
  • The input matrix will be 3x3, the entries will be in the interval [-10,10]
  • The error of your result should be at most 10^-5
  • Your program may fail for some inputs as long as the probability of failure for a Matrix with uniformly distributed entries is 0
  • You can choose any eigenvalue as output, and may return different values on different calls
  • You are not allowed to use built-in functions that directly compute a eigenvalue/eigenvector of a matrix
  • You are allowed to use other matrix functions but are encouraged to solve the problem without matrix built-ins

Example solution in Python (non-golfed)

Uses a derivative-free variation of Newtons algorithm on the determinant

def det(M):
  return (M[0][0]*M[1][1]*M[2][2]+M[0][1]*M[1][2]*M[2][0]+M[0][2]*M[1][0]*M[2][1]-
          M[2][0]*M[1][1]*M[0][2]-M[2][1]*M[1][2]*M[0][0]-M[2][2]*M[1][0]*M[0][1])

def copy(M):
  return [[a for a in R]for R in M]

def subtX(M,x):
  N=copy(M)
  for i in range(len(M)):
    N[i][i]-=x;
  return N

def eigenValue(M):
  x0=0;x1=1;y0=1
  while abs(y0)>1e-5:
    N0=subtX(M,x0)
    N1=subtX(M,x1)
    y0=det(N0);y1=det(N1)
    x0,x1=x0-y0*(x1-x0)/(y1-y0),x0
  return x0

Attempt This Online!


Meta

  • Is this duplicate/ and interesting question ?
  • Is my explanation clear ?
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Interpret a Turing Complete (strict) Subset of your Language

  • Write a program which can interpret some programs exactly the same way as your language, where these can be used to model any computation.
  • Demonstrate how to do this.
  • Your Interpreter may have features your language doesn't have, but your demonstration may not use them.
  • You may not use a built-in which interprets the source language, like eval()

The feature set does not need to be made of characters or something, you just need to say what it is.

It's [code-golf] until i can think of something better. how do you do tags in markdown?

Example: a javascript interpreter which only allows String.replace, functions, and the ternary conditional thing ? : may be able to be used as a convoluted slashes emulator.

Discussion:

  • This challenge was originally intended to make all languages equally interesting, but I think it still favors turing tarpits and golfing languages.
  • As with many Challenges which already exist, this one also gives actually interpreted languages kind of a leg up.
  • Making it illegal for turing completeness to arise from interpreter quirks is propably not that important. (like, ACE in my brainfuck interpreter?)
  • Banning eval might introduce rules-lawyering on what eval actually is, like, are Regexes allowed? is a built-in which evaluates arithmetic allowed? I'd say yes. It might also further favor turing tarpits, though it would nerf golfing languages which propably have an eval construct. It might also make the program more laborious to write, obviously, but
  • Allowing eval might make writing the program boring as well, as that's an established technique.
  • Making this [code-golf] is boring, maybe i should make it about the conciseness of an example program? It wouldn't devolve into HQ9+, but its discriminatory, like how is slashes supposed to calculate a factorial?
New contributor
Jan H is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
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    \$\begingroup\$ Welcome to cgcc, and interesting idea. Can you define "useful" more (maybe even formally)? Also, don't forget to add a winning criterion (such as code-golf) \$\endgroup\$ Sep 26 at 21:11
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Implement the RegPack decompressor

The JavaScript compressor RegPack uses a very simple string compression algorithm. Given a piece of code, it will make a list of characters that aren't used in that code and use them to delimit repeated strings that are inserted back into the string.

To show how strings are compressed, it's necessary to show how the decompressor works. If you give RegPack the tongue-twister How much wood would a woodchuck chuck if a woodchuck could chuck wood?, it will spit out How much } w|a }~~if a }~c|~}?~chuck }wood|ould along with the list of characters |}~.

The decompressor starts by splitting this string on the first character in the char list, |, resulting in ["How much } w", "a }~~if a }~c", "~}?~chuck }wood", "ould "]. It then pops the last item, "ould ", and joins what remains by this, resulting in "How much } would a }~~if a }~could ~}?~chuck }wood".

It then does the same thing for }, replacing ~ with wood to result in "How much wood would a wood~~if a wood~could ~wood?~chuck ", and finally replaces ~ with "chuck " to result in the whole thing, How much wood would a woodchuck chuck if a woodchuck could chuck wood?.

The advantage of this algorithm is that it's very simple and short to implement. RegPack itself implements it in 39 bytes of JavaScript: for(i of<chars>)with(_.split(i))_=join(pop()) (where <chars> is a hardcoded char list), which basically performs the steps described above.

Your challenge is to, given a compressed string and a list of characters, decompress it using the above algorithm.

Testcases

'a|b|c|hello', '|' => ahellobhelloc
'He||o, wor|d!|l', '|' => Hello, world!
'| | & &&|house|green', '|&' => green green greenhouse greenhouse
'N~give}up,n~let}down~ever gonna } you ', '}~' => Never gonna give you up,never gonna let you down
'How much } w|a }~~if a }~c|~}?~chuck }wood|ould ', '|}~' => How much wood would a woodchuck chuck if a woodchuck could chuck wood?
'She sells~ells by the~ore~ sea sh', '~' => She sells sea shells by the sea shore
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Factorial Numbers

Write a function or program to print "factorial numbers" as defined in this xkcd comic. Test cases are conveniently provided by the comic too.

You will take an integer number N as input.

You can either

  1. output the factorial number representation of N
  2. output the factorial number representation of all numbers up to and including N in order (note: must include N; this is different from default rules)

You can assume that the input is not "illegal", but your program must work for all legal inputs. Default loopholes and I/O rules apply. If this can be done in 1 built-in method, you may post it but it will not compete.

This is code-golf so shortest wins. The competition will be between each language, so non-golfing languages should compete.

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4
  • \$\begingroup\$ Duplicate \$\endgroup\$
    – emanresu A
    yesterday
  • \$\begingroup\$ @emanresuA ah wow. But the post is 10 years old and the newest answer is 5 years old. Perhaps there are innovations in golfing languages that make this interesting again. What can be done about this? The comic was posted yesterday too. Thanks. \$\endgroup\$ yesterday
  • 1
    \$\begingroup\$ Unfortunately, the thing about good challenge ideas is that a lot of them have already been done. If you wanted to raise interest in that challenge you could post an answer to it. \$\endgroup\$
    – emanresu A
    yesterday
  • \$\begingroup\$ Thanks. I might try that. \$\endgroup\$ yesterday
0
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Golf my code


For this challenge, I'll use edit histories of answers to create a dataset of answers that have been golfed. Your task will be to write a program/function that, given a submission that was golfed in the future, will attempt to golf the submission.

You may choose the language, out of a set I'll choose based on the quantity and quality of data available, that your inputs will be in. You may choose to take inputs from multiple languages, which will not be differentiated (e.g., you can choose to score your answer over a combined Python + Jelly dataset).

The first part of your score will be the sum of bytes golfed by your program for each input, with any submissions that don't become shorter (including becoming longer) or become invalid having no impact on your score (might change this later, since otherwise you have no reason not to use a dataset of all languages).

Your final score will be your score, minus the number of bytes in your program. So, if you golf a total of 1920 bytes off the Python answers dataset, with 1080 bytes of code, your final score will be 840. Higher scores are better.

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1
  • 1
    \$\begingroup\$ I get the idea that the program is supposed to golf answers in a specific language, but I don't understand how we're expected to do that and programmatically return correct golfed answers, please add an example \$\endgroup\$
    – noodle man
    20 hours ago
-1
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Bike saddle drawn through a fractal

Based on the Mandelbrot image in every language, and on the observation the 3rd layer (0 indexed) always looks like a bike saddle, I had a little bit different challenge:

  • Language must be capable of graphical output or drawing charts (saving files disallowed)
  • Render a window or control that is resizable by mouse action. As example, it can be a typical GUI Window with the typical frame that allows resizing
  • After resizing the GUI element, the fractal should be updated according to the new pixel space
  • The fractal coordinates range from approximately -2-2i to 2+2i
  • The pixels outside of the 3rd layer (0 indexed) of Mandelbrot set should have one color; the ones inside 3rd and inner layers should have another. The only two colors used should be clearly distinguishable
  • At least 99 iterations
  • ASCII art not allowed

Winning conditions:
Shortest version (size in bytes) for each language will get a mention in this post, ordered by size.
No answer will ever be 'accepted' with the button.

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2
  • \$\begingroup\$ @Mark Jeronimus: credits to you. \$\endgroup\$
    – sergiol
    May 27, 2017 at 8:48
  • \$\begingroup\$ "The only two colors used should be clearly distinguishable" Clarification? \$\endgroup\$
    – Joao-3
    Aug 15 at 14:30
-1
\$\begingroup\$

The 2017 Loader contest

Here's a thing: Let's do the bignum bakeoff again.

Because why not.

What to do

Write a program in less than 256 characters that outputs the biggest number you can.
Yep, that's it. Biggest return value wins.

We'll run the program on a VM with infinite memory. (How do we do this?)

Rules

  • 256 chars max, excluding whitespace
  • Different leagues for each language
  • Output however you want
    • No explicitly printing numbers until your loop runs out. Print the number you generate directly. {1}
  • Program must terminate
  • No implementation-dependent shenanigans.
  • Implementation-independent shenanigans is encouraged.
  • ints are infinite.
  • Program must return the same number every time
  • Submission must include the approximate return value in any suitable googological notation.
  • Whitespace is space, tab, newline, formfeed, and return
    • BrainF***: Whitespace is all non-[]+-<> characters

{1} Allowed ways to return: printf("%d", num); return num;, etc.
Banned ways to return: for(;num>0;num--)printf("99999");, etc.


This is not a dupe of...

This because you can put any characters you want, not just non-digits; because we're hard-limiting the characters.


Suggested rules

  • No floats: float double long double, etc
  • No strings or chars
  • No bitfeilds
  • No looking at Command-line args

Next year's contest will be named after this year's winner, for no particular reason.

http://djm.cc/bignum-rules-posted.txt


Sandbox

  • How do you even test these programs?
  • What other rules should we have?
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9
  • \$\begingroup\$ You don't actually explain the rules of the challenge, we would have to go to that link to find out what we are supposed to do. Aside from that, I think this has a lot of problems with your typing restrictions if these are not limited to C, but limiting it to C wouldn't really fit the spirit of the site. I think you may want to rethink how you want to approach this question. \$\endgroup\$ May 29, 2017 at 16:43
  • \$\begingroup\$ @FryAmTheEggman "Typing restrictions"? (Added proper instructions) \$\endgroup\$ May 29, 2017 at 16:45
  • 1
    \$\begingroup\$ Your post doesn't describe how people win. Is it by the largest possible number? Anyway, the problems are things like not counting whitespace, which can easily result in degenerate answers, as well as things like I/O streams and whatnot. All of your extra rules seem entirely based around C with no regard for other languages, which will not go well. \$\endgroup\$ May 29, 2017 at 16:48
  • 6
    \$\begingroup\$ In answer to "Because why not": because it will be closed as a dupe. \$\endgroup\$ May 29, 2017 at 17:59
  • \$\begingroup\$ Here's a couple of rules I would consider. 1. Program must generate the same result every time (e.g. not based on timer, probability, or the like). 2. Submissions should include, if not the exact resulting number, at least a best estimate, in scientific notation if need be. \$\endgroup\$ May 30, 2017 at 18:32
  • \$\begingroup\$ Scientific notation? People will post answers that far, far exceed that. In fact, Mathematica, 22: Fold[Power,2~Range~9999] It's 2^3^4^...^9999. That's not being represented anytime soon. \$\endgroup\$ May 31, 2017 at 3:31
  • 1
    \$\begingroup\$ This is a duplicate, and is also going to come down a lot to whether or not you allow programs that exceed the computational capacity of any existing computer. (If you require programs to work on a physical computer, the best they can possibly do is to use the entirety of memory as a counter and print out 9s over and over again. If you don't, the answers can easily be large enough that you need to use notation invented specifically for describing the number, because all other notations are not enough.) \$\endgroup\$
    – user62131
    May 31, 2017 at 22:40
  • \$\begingroup\$ If your code can simulate a Turing machine, it becomes hard to judge who the winner is, and whether an answer is valid at all. \$\endgroup\$
    – anatolyg
    Jun 1, 2017 at 20:35
  • 1
    \$\begingroup\$ Re your latest edit: you're wrong. The question it's a dupe of also has a hard limit to the number of characters; in fact it's a harder one, but the best answers could be copied with slight tweaking to take advantage of the extra space. And the digit restriction turned out not to be a serious problem: the winning answer would gain extremely little from being able to use digits. \$\endgroup\$ Jun 2, 2017 at 9:07
-1
\$\begingroup\$

Do nothing

Write a program which terminates normally (not in an error), producing no output on the standard output stream (or the language's closest equivalent), nor on the standard error stream, regardless of what content is present on the standard input stream. (Note that this is intentionally overriding the normal I/O defaults; this is a challenge entirely about input/output handling.)

Additionally, your program may not have any other side effects (e.g. writing files, changing persistent state), unless they're an unavoidable consequence of running a program on the operating system you're using (e.g. on Linux, it's OK to change the "next process ID number to be assigned" value inside the kernel, because that happens whenever you run a program).

Finally, to avoid numerous uninteresting 0-byte (or boilerplate-plus-0-byte) solutions, you may not use a language in which the shortest program that does nothing (i.e. complies with the above specification) is also the shortest (or tied for the shortest) program which runs without error (but possibly reacts to input or produces output). In other words, you can't use a language unless doing nothing is more verbose than doing something.

Clarifications

  • Intentionally exiting the program early is permitted. If you do exit the program manually, on a system that uses exit codes, you may do so with any exit code.
  • Crashing the program is not permitted, even if it (for some reason) exits with a "success" code after the crash.
  • "No output" means 0 bytes of output, not even a trailing newline.
  • Likewise, your program must be able to handle any finite sequence of bytes on the standard input stream, even if it isn't, say, made of characters in the current encoding (but rather of arbitrary octets). You do not need to handle infinite input, though (e.g. your program won't be connected to /dev/zero or the like).
  • You don't have to actually read input; it's your choice as to whether you want to read and discard it, or not read it at all.

Victory condition

As a challenge, shorter is better, measured in bytes. (Remember that if you need to run the program in an unusual way, that incurs a byte penalty, under standard PPCG rules.)

Because languages which are particularly suited for this task (such as Perl and Python) are excluded by the rules, there's not much point in talking about the best answer cross-language; rather, the aim is to find the best answer you can in the language which you submit in. (Historically, on this sort of challenge, answers that are more unusual, interesting, or better-explained have tended to get more votes.)

Sandbox questions

Is this too trivial? We were discussing it in chat as a joke, and realised that it's actually possibly more interesting than it sounds. I'm fairly sure the spec's correct (although would definitely appreciate knowing if something's wrong here!), but would appreciate feedback on how much people would hate me if I posted it to main.

\$\endgroup\$
2
  • \$\begingroup\$ you can't use a language unless doing nothing is more verbose than doing something.you can't use a program unless your program is more verbose than any other program which does something. You must provide a shorter program which does something to prove your solutions validity. \$\endgroup\$
    – Adám
    Jun 8, 2017 at 1:03
  • \$\begingroup\$ @Adám: If you did that, people would just add a comment byte or two to create a program of the shortest possible length that was longer than a program that did something. That isn't particularly interesting. \$\endgroup\$
    – user62131
    Jun 8, 2017 at 1:21
-1
\$\begingroup\$

Plan and Chain a route through OEIS

Your Task is to reach so many OEIS sequences you could make with chaining your last sequence with a operation to a new sequence.

You must avoid last sequence minus last sequence plus first sequence or something similar that your new sequence is based on the first sequence except to make the second sequence.

Your starting OEIS sequence is in every case https://oeis.org/A001477

Given as Input an positive Integer and a Letter that matches [A-Z] or [a-Z]

Example

PHP, 171 bytes

for($a=0;$a<=$argv[1];$a++)$r[]=[$a,$b=$a&1,$c=$a+!$b,$d=(($c-!$b)/2^0)+$b,$A[$b]=$e=$d*$c,$f=$e+$A[!$b],$g=$a?$g*sqrt($f):1,$h=$g%2];echo$r[$argv[1]][ord($argv[2])%32-1];

Try it online!

The example gives back the n value of a OEIS sequence for the following letters. A letter greater h is for this example a invalid input

  • a https://oeis.org/A001477 numbers
    $a Valid first sequence

  • b https://oeis.org/A000035 mod 2
    $b=$a&1 Valid use the variable in the sequence before

  • c https://oeis.org/A109613 odd numbers
    $c=$a+!$b Valid Can use sequences before

  • d https://oeis.org/A110654 a(n) = floor(n/2) + n mod 2
    $d=(($c-!$b)/2^0)+$b Valid an invalid example is $d=(($a/2)^0)+$b cause it not use the sequence before

  • e https://oeis.org/A000217 triangular
    $A[$b]=$e=$d*$c Valid you can create help variables

  • f https://oeis.org/A000290 square
    $f=$e+$A[!$b] Valid use a help variabale and the variable of the sequence before. $f=$A[!$b]+$A[!$b] Invalid causes it makes the same value but use indirectly the variable of the sequence before

  • g https://oeis.org/A000142 factorial $g=$a?$g*sqrt($f):1 Valid cause your condition is not always the case that it have no relationship to the sequence before.

  • h https://oeis.org/A019590 Fermat's Last Theorem $h=$g%2 Valid but now we have the problem to find the next sequence

Could You make a full alphabet? My alphabet ends with the letter h

\$\endgroup\$
9
  • \$\begingroup\$ I'm rather confused as to what is being asked here. It might be helpful to state how one can get from one sequence to another. \$\endgroup\$
    – Wheat Wizard Mod
    Jun 10, 2017 at 20:47
  • \$\begingroup\$ @WheatWizard I could understand you. The problem is at the moment to make rules that avoid that a trivial solution exits. There are too many sequences in OEIS. The way from every sequence to the next should not end in a simple addition or multiplication. But evrything else should be allowed to get more creative solutions \$\endgroup\$ Jun 10, 2017 at 20:56
  • \$\begingroup\$ (1) The first sentence says that the aim is to build the longest chain possible, but the scoring mechanism rewards average code length per element in the chain rather than number of chains. I would think it most likely as it stands that the winner would be a chain of length 1 or at most 2. (2) If you delete everything from the header Example to the end, do you think that the question still makes sense? If not (and I don't think it does), it needs a lot of work. (3) What do the two values in the input mean? Why is the second one a letter rather than a number? \$\endgroup\$ Jun 10, 2017 at 21:10
  • \$\begingroup\$ (4) I'm not sure how feasible it is to write objective rules which forbid "trivial" expressions. (5) It is not clear how to interpret the rule about the 32nd term where either it is not known or the sequence is finite and shorter than 32 terms. \$\endgroup\$ Jun 10, 2017 at 21:12
  • \$\begingroup\$ @PeterTaylor (1) Think you that popularity Contest is a better winning criteria? (2+3) to limit the chaining length to 26. The goal is to show relationsships between two or more sequences. (4+5) Yes it is not easy and I can drop it if I switch to popularity Contest \$\endgroup\$ Jun 10, 2017 at 21:26
  • \$\begingroup\$ @WheatWizard I allow now trivial solutions \$\endgroup\$ Jun 10, 2017 at 21:53
  • \$\begingroup\$ I'm not clear on the purpose of the inputs if we're just supposed to hard code our way from one sequence to the next​. Replacing your PHP example with more generic, more verbose pseudo-code might help. \$\endgroup\$
    – Shaggy
    Jun 11, 2017 at 0:16
  • \$\begingroup\$ @programmer5000 exists a limit of correct tags? \$\endgroup\$ Jun 11, 2017 at 11:39
  • \$\begingroup\$ @Shaggy See it as restriction for ways to code. You must have a chaining to the sequence before. So far I know any working code is a pseudocode \$\endgroup\$ Jun 11, 2017 at 11:48
-1
\$\begingroup\$

Braid Badly Boundlessly


Your program or function must, given a string in any standard input format, output an infinite stream of delimiter-separated strings where each string is determined from the previous by a braiding algorithm. The program starts with printing the input string.

The algorithm is described as follows: Infinitely alternate between

(1) splitting the string into three substrings then swapping the first two substrings and flattening.

and

(2) splitting the string into three substrings then swapping the last two substrings and flattening.

starting with (1).

The three substrings should be of non-increasing length with the maximum length no more than 1 greater than the minimum length of the three substrings. (This means that when the length of the given string is a multiple of three, the three substrings should be the same length. When the length of the given string is one more than a multiple of three, the first substring should be one character longer than each of the last two substrings. When the length of the given string is two more than a multiple of three, the first and second substrings should each be one character longer than the last substring.)

Example

Let the input be "abcdefg". Let the delimiter be a newline.

Then the program would first print "abcdefg".

It applies (1) which splits the string into ["abc","de","fg"] and swaps the first two elements, reaching ["de","abc","fg"]. It flattens to get "deabcfg" which it prints and uses for the next step.

The program applies (2) to "deabcfg" to split into ["dea","bc","fg"] and swaps into ["dea","fg","bc"], flattening to reach "deafgbc".

The program applies (1) to "deafgbc" and the process repeats ad infinitum.

Then the output would be the newline-separated

abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
abcdefg
[...]

Specifications

  • Note that the string should not be split at the beginning and then only swapped later. The string should be split on each and every iteration
  • The delimiter between lines could be whichever character is convenient. You may assume it does not appear in the input string.
  • The string input shall be at least three characters
  • The input consists solely of printable characters (0x20-0x7F)
  • Of course, standard loopholes are forbidden.

I/O

  • The input and output should be taken in standard I/O methods.
  • The input and output should be taken as string, list of characters, or equivalent.
  • The output should be output continuously, which means you may assume infinite memory.

Test cases

For the test cases, we will assume that the delimiter is a newline. Just the portion before the endless stream is repeats is shown.

input
--
output
-----
abcdefg
--
abcdefg
deabcfg
deafgbc
fgdeabc
fgdbcea
bcfgdea
bcfeagd
eabcfgd
eabgdcf
gdeabcf
gdecfab
cfgdeab
cfgabde
abcfgde
-----
abc
--
abc
bac
bca
cba
cab
acb
-----
abcdefgh
--
abcdefgh
defabcgh
defghabc
ghadefbc
ghabcdef
bcdghaef
bcdefgha
efgbcdha
efghabcd
habefgcd
habcdefg
cdehabfg
cdefghab
fghcdeab
fghabcde
abcfghde
abcdefgh
-----
Braid
--
Braid
aiBrd
aidBr
dBair
dBrai
radBi
raidB
idraB
idBra
Brida
-----
Cycle
--
Cycle
clCye
cleCy
eCcly
eCycl
yceCl
ycleC
leycC
leCyc
Cylec
-----
O Canada!
--
O Canada!
anaO Cda!
anada!O C
da!anaO C
da!O Cana
O Cda!ana
-----
A man, a plan, a canal - panama!
--
A man, a plan, a canal - panama!
an, a canalA man, a pl - panama!
an, a canal - panama!A man, a pl
 - panama!Aan, a canal man, a pl
 - panama!A man, a plan, a canal
 man, a pla - panama!An, a canal
 man, a plan, a canal - panama!A
n, a canal  man, a pla- panama!A
n, a canal - panama!A man, a pla
- panama!A n, a canal man, a pla
- panama!A man, a plan, a canal 
man, a plan- panama!A , a canal 
man, a plan, a canal - panama!A 
, a canal -man, a plan panama!A 
, a canal - panama!A man, a plan
 panama!A m, a canal -an, a plan
 panama!A man, a plan, a canal -
an, a plan, panama!A m a canal -
an, a plan, a canal - panama!A m
 a canal - an, a plan,panama!A m
 a canal - panama!A man, a plan,
panama!A ma a canal - n, a plan,
panama!A man, a plan, a canal - 
n, a plan, panama!A maa canal - 
n, a plan, a canal - panama!A ma
a canal - pn, a plan, anama!A ma
a canal - panama!A man, a plan, 
anama!A mana canal - p, a plan, 
anama!A man, a plan, a canal - p
, a plan, aanama!A man canal - p
, a plan, a canal - panama!A man
 canal - pa, a plan, anama!A man
 canal - panama!A man, a plan, a
nama!A man, canal - pa a plan, a
nama!A man, a plan, a canal - pa
 a plan, a nama!A man,canal - pa
 a plan, a canal - panama!A man,
canal - pan a plan, a ama!A man,
canal - panama!A man, a plan, a 
ama!A man, canal - pana plan, a 
ama!A man, a plan, a canal - pan
a plan, a cama!A man, anal - pan
a plan, a canal - panama!A man, 
anal - panaa plan, a cma!A man, 
anal - panama!A man, a plan, a c
ma!A man, aanal - pana plan, a c
ma!A man, a plan, a canal - pana
 plan, a cama!A man, anal - pana
 plan, a canal - panama!A man, a
nal - panam plan, a caa!A man, a
nal - panama!A man, a plan, a ca
a!A man, a nal - panamplan, a ca
a!A man, a plan, a canal - panam
plan, a cana!A man, a al - panam
plan, a canal - panama!A man, a 
al - panamaplan, a can!A man, a 
al - panama!A man, a plan, a can
!A man, a pal - panamalan, a can
!A man, a plan, a canal - panama
lan, a cana!A man, a pl - panama
lan, a canal - panama!A man, a p
l - panama!lan, a canaA man, a p
l - panama!A man, a plan, a cana
A man, a pll - panama!an, a cana
\$\endgroup\$
-1
\$\begingroup\$

Rock Paper Scissors, but it's a big, custom tournament

We all know "Rock, Paper, Scissors", and it's pretty variated.

A world tournament is held every year, and it's dang popular.

However, the contestants are able to bring their own ways of play to the plate, and they play with them.

The challenge:

Create a program that, by process of elimination through RPS, determines the winner of the tournament.

The tournament rules:

  • No slackers. (Let the amount of players be an integer equally divisible by 2. [In other words, an even number.])

  • You can bring 2 of either of the 4 variants:

    None: Play regular RPS.

    RPSLV: Play "Rock, Paper, Scissors, Lizard, Spock" (play diagram shown here).

    Best out of three: Play 3 rounds; if by round 2, a player wins the round and has two points, they auto win. Else, winner of the next round wins.

    Double RPS: Play with four hands (two hands used by each player).

  • You cannot bring two of the same variant.

  • In order to use a variant, the two players must have the same type of variant. If there are no matching variants, the gameplay is automatically None.

  • However, if there are more than one variant matches, a game of mode None will be played. The winner of the game mentioned decides what mode they play for the match they will play to see who goes to the next round.

  • In the case of a tie, replay until a win occurs (for all modes)

  • There can be only one winner.

The coding rules:

  • All choices must be randomized (no strategies, to make this simple.).

  • No standard loopholes.

  • Give an explanation as much as you can. (If possible, include a "Try it out online" sample.)

Sample Input/Output:

You must make a table variable with all the player numbers, from 1 to n, with two variants for each player.

n = the amount of players you intend to enter.

Example Input:

Player # | Var 1 | Var 2
1        | RSPLV | None
2        | None  | x2 RPS
3        | x2 RPS| Boo3
4        | Boo3  | x2 RPS
...      |...    | ...

Make a func() that:

1: Checks the variants of the next two availible players on the list, starting at player 1, then does the second to third last rules depending on what happens.

2: Makes the pair engage in battle, gameplay depending on the chosen variant.

3: Finally, boot the loser off the game and add the winner to the next list (round). (The "boot the loser" part isn't that required, but I recommend so as to not make the program add a player to the next table.)

Output (uses table from input):

 Round 1:
 1 vs. 2 // None, since the None variant matches both of them
 ["Rock"/*1*/,"Scissors"/*2*/]
 1 wins

 3 vs. 4 // They have more than one match, so they fight for who decides
 ["P"/*3*/,"S"/*4*/]
 4 wins, and chooses Best out of 3 
 Match 1:
 ["P"/*3*/,"R"/*4*/] // 1(3) - 0(4)

 Match 2:
 ["P"/*3*/,"S"/*4*/] // 1(3) - 1(4)

 Match 3:
 ["P"/*3*/,"R"/*4*/] // 2(3) - 1(4)
 3 wins

 Round 2:
 1 vs. 4 //No matches, defaults to None
 ["R"/*1*/,"R"/*4*/] // No-one wins
 ["R"/*1*/,"S"/*4*/]
 1 wins the tournament

Misc. requirements (some optional):

A {!} means it is required.

  • {!} Print each match, and who wins.

  • {!} Print the tournament winner.

  • {!} The number of players must be flexible.

  • Print the table for each round.

Scenarios:

None:

a vs. b //Either they have no matches, or they have both None matches
["R"/*a*/,"S"/*b*/]
a wins

RPSLV (will make this one quick):

a vs. b //RPSLV chosen
["V"/*a*/,"L"/*b*/]
b wins

Best out of Three:

Scenario 1: (a tie occurs at match 2)

a vs. b //Boo3 chosen
Match 1:
["P"/*a*/,"S"/*b*/] // 0(a) - 1(b)

Match 2:
["P"/*a*/,"P"/*b*/] // tie
["P"/*a*/,"S"/*b*/] // 1(a) - 1(b)

Match 3:
["R"/*a*/,"S"/*4*/] // 2(a) - 1(b)
a wins

Scenario 2: (a player has two points by the end of match 2)

a vs. b //Boo3 chosen
Match 1:
["P"/*a*/,"S"/*b*/] // 0(a) - 1(b)

Match 2:
["S"/*a*/,"P"/*b*/] // 0(a) - 2(b)
b automatically wins

Double RPS:

a vs. b //x2 RPS chosen
[("R", "P")/*a*/, ("S", "S")/*b*/] // lock
[("P", "P")/*a*/, ("S", "S")/*b*/]
b wins

Both the coding and tournament rules apply to your code.

For sandbox use only (won't be included in real question)

I don't know if this kind of problem is suitable for code golf, it could be a programming puzzle, I'm not sure. Go ahead in the comments and tell me what mode it should be, and if I should improve it. (Also, sorry for the mix of Python lists and C++ comments, if it confuses you.) A ** means the choice is random.

\$\endgroup\$
4
  • \$\begingroup\$ Hi and welcome to PPCG, and thanks for using the sandbox! I had a hard time following what you intended from this challenge. The rules are rather disorganised with many points early on not making sense until later. For example, you say: "No slackers. (Let p be a number equally divisible by 2.)" before it is clear that you intend for us to implement a single elimination tournament. I had no idea what "p" was supposed to mean, or why this should matter. I'd recommend trying to explain this to someone verbally, perhaps, to try to organise your thoughts better. Good luck! \$\endgroup\$ Jul 15, 2017 at 21:50
  • \$\begingroup\$ Ah, thanks. I will edit the problem. \$\endgroup\$ Jul 15, 2017 at 22:03
  • \$\begingroup\$ I'm not quite sure what we're supposed to implement. The controller for the tournament and what else? Do we also implement the players, so that we're simulating the entire thing? Or do we have to provide some kind of API for the players? In the first case, how does "The winner decides what mode they play" work? \$\endgroup\$ Jul 16, 2017 at 7:14
  • \$\begingroup\$ Again, any multi-choice is random. \$\endgroup\$ Jul 16, 2017 at 19:29
-1
\$\begingroup\$

Quick! Tell me all the numbers from 1 to 100,000!

Your task is to write a program or function that, when run, output all the numbers from 1 to 100 thousand as quickly as possible to STDOUT. It's that simple. All answers are tested on an HP Compaq nx9420 with an Intel Core Duo @ 1.83 GHz and 3 gigs of RAM using the time command.


Of course, standard loopholes are strictly forbidden.
This is , so may the fastest code win and the best programmer prosper...

\$\endgroup\$
9
  • 3
    \$\begingroup\$ Have you tried running an example to see if the times are variable enough to be meaningful? As-is, this is going to be strongly dependent upon how fast the code can do I/O, which makes the challenge pretty uninteresting, IMO. \$\endgroup\$ Jul 19, 2017 at 18:16
  • \$\begingroup\$ @AdmBorkBork Might be interesting \$\endgroup\$
    – ckjbgames
    Jul 19, 2017 at 21:12
  • 1
    \$\begingroup\$ As far as I can tell, this takes less than a tenth of a second, which means submissions will probably be differentiated solely by noise on your computer. \$\endgroup\$ Jul 20, 2017 at 2:37
  • \$\begingroup\$ upvoted, though I think the differenciation is really difficult, unless you test it on a raspberry PI (for example) having ONLY the program and its compiler installed. \$\endgroup\$ Jul 20, 2017 at 13:36
  • \$\begingroup\$ @FryAmTheEggman How could I improve on that? \$\endgroup\$
    – ckjbgames
    Jul 20, 2017 at 23:38
  • 1
    \$\begingroup\$ @V.Courtois I do have a Pi, and I think I will use that (it has Raspbian installed). \$\endgroup\$
    – ckjbgames
    Jul 20, 2017 at 23:39
  • \$\begingroup\$ The time is still so small even a basic operating system will have to much noise in process creation, etc, for this to work out. You need to make what we are computing substantially more complicated for this to be reasonable. \$\endgroup\$ Jul 21, 2017 at 0:10
  • \$\begingroup\$ @FryAmTheEggman K \$\endgroup\$
    – ckjbgames
    Jul 21, 2017 at 1:20
  • \$\begingroup\$ @ckjbgames good then :) \$\endgroup\$ Jul 21, 2017 at 5:26
-1
\$\begingroup\$

What's that character? (Part 1)

Recently I ran a command on my laptop that returned a bunch of characters - some printable, some non-printable. I'm having trouble figuring out what those characters are, so I could use some help. Unfortunately, I'm running low on disk space, so you'll have to write me the shortest program you can that I can run.

Challenge

Given a list of ASCII characters, return their names as written on www.asciitable.com, my go-to site for looking up character points.

Input

You may take a string, a list of characters, or a list of ASCII code points (e.g. 'a' -> 97).

You may optionally take the length of the string/list as well. Note that for C, you must take this parameter, since the string could contain NUL bytes, so strlen won't work here.

Output

Output is flexible as usual; you may print or return from a function as you see fit. You should output a list of strings.

The Table

0 NUL
1 SOH
2 STX
3 ETX
4 EOT
5 ENQ
6 ACK
7 BEL
8 BS
9 TAB
10 LF
11 VT
12 FF
13 CR
14 SO
15 SI
16 DLE
17 DC1
18 DC2
19 DC3
20 DC4
21 NAK
22 SYN
23 ETB
24 CAN
25 EM
26 SUB
27 ESC
28 FS
29 GS
30 RS
31 US
32 Space
33 !
34 "
35 #
36 $
37 %
38 &
39 '
40 (
41 )
42 *
43 +
44 ,
45 -
46 .
47 /
48 0
49 1
50 2
51 3
52 4
53 5
54 6
55 7
56 8
57 9
58 :
59 ;
60 
63 ?
64 @
65 A
66 B
67 C
68 D
69 E
70 F
71 G
72 H
73 I
74 J
75 K
76 L
77 M
78 N
79 O
80 P
81 Q
82 R
83 S
84 T
85 U
86 V
87 W
88 X
89 Y
90 Z
91 [
92 \
93 ]
94 ^
95 _
96 `
97 a
98 b
99 c
100 d
101 e
102 f
103 g
104 h
105 i
106 j
107 k
108 l
109 m
110 n
111 o
112 p
113 q
114 r
115 s
116 t
117 u
118 v
119 w
120 x
121 y
122 z
123 {
124 |
125 }
126 ~
127 DEL

Test Cases

[0, 97, 7, 22] -> [NUL, a, BEL, SYN]

More to come...

Meta

  • Would it be more interesting to use the UTF-8 names for the printable characters (0x20 - 0x7E), and the ASCII names for the control characters?
\$\endgroup\$
4
  • \$\begingroup\$ hand copy the table from the website please dont. Try a Google search: theasciicode.com.ar/ascii-codes.txt \$\endgroup\$
    – Stephen
    Jul 23, 2017 at 22:39
  • \$\begingroup\$ @StepHen good call, thanks \$\endgroup\$ Jul 23, 2017 at 23:24
  • \$\begingroup\$ Downvoter: I would much like your feedback rather than just your vote \$\endgroup\$ Jul 24, 2017 at 1:39
  • 1
    \$\begingroup\$ IMO just have take a letter and output the code. Since that part is boilerplate str.chars.map( real program ). Also for ASCII char names NUL is it ok is we output them in lower case? e.g. nul (obviously ascii letters would have fixed case) \$\endgroup\$
    – Downgoat
    Jul 24, 2017 at 1:42
-1
\$\begingroup\$

Lennyface parser and selector

Your mission

Create, in the language of your choice, a program that outputs a randomly selected lennyface (artistic minifigures, see this) from an input - a string composed of numbers and lennyfaces. You will have to : first, parse this input; second, extract a probability mass function f from the parsed input; third, select and output a lennyface respecting f. Read the rules for more details.

Rules

  • Input : A string with lennyfaces and numbers (positive AND negative integers), separated by newlines. You may take input by STDIN or function parameter for example.
  • Output (STDOUT for example) : the randomly-selected lennyface, as a string.
  • The input creates a probability mass function f. If l is a lennyface, then f(l)=(sum of all numbers since the previous lennyface)/x where x is obtained afterwards by summing each of those numerators. @Sandbox : is it clear enough?
  • If (sum of all numbers since the previous lennyface) is equal to zero or negative, you must do as if the numerator is equal to 1 in f's definition.
  • A line with a number contains only this number ; same for a line with a lennyface. So you can assume there will never be a number in a lennyface.
  • If there is nothing on a line (two newlines in a row), you must consider it as a lennyface.
  • You must consider that the last line of the string is directly before its first line. See Test 1 for an example.
  • You can assume there will be at least 1 lennyface in the list; it cannot be composed just by numbers (don't forget that an empty line is a lennyface too).

Example

Given this input list :

( ͡° ͜ʖ ͡°)
2
¯\_ツ_/¯
34
-4
8
└[⸟‿⸟]┘

1

You must have 1/42 chances of outputting ( ͡° ͜ʖ ͡°), 2/42 chances of outputting ¯\_ツ_/¯, 38/42 chances of outputting └[⸟‿⸟]┘ and 1/42 chances of outputting nothing (line 7).

Test cases

Test 1

(⌐■_■)
3

Must output (⌐■_■) with 3/3 chances.

Test 2

ʢ◉ᴥ◉ʡ

Must output ʢ◉ᴥ◉ʡ with 1/1 chance.

Test 3

0
\(ᗝ)/

Must output \(ᗝ)/ with 1/1 chance.

Test 4

( ͡° ͜ʖ ͡°)
2
¯\_ツ_/¯
34
4
☞   ͜ʖ  ☞

0

Must output ( ͡° ͜ʖ ͡°) with 1/42 chance, ¯\_ツ_/¯ with 1/21 chance, ☞  ͜ʖ  ☞ with 19/21 chances and nothing with 1/42 chance.

Test 5

1



( ͡° ͜ʖ ͡°)

Must output ( ͡° ͜ʖ ͡°) with 1/4 chance and nothing with 3/4 chance, since there are 3 empty lines.

Test 6

42

-1
( ͡° ͜ʖ ͡°)

Must output nothing with 43/44 chance and ( ͡° ͜ʖ ͡°) with 1/44 chance.

@Sandbox : should I add test cases?

This is , so shortest code in bytes wins. Standard loopholes apply.

Note : Please do not be discouraged if the parsing is difficult to handle in your language, or if testing is hard because of randomness. Your solution might be very interesting algorithmically, not obviously in terms of golfing. Just please explain in your answer why it works.

Moreover, this is the first code-golf I create, so please let me know if something is not appropriate or if I should give more details on a point. And overall, if you downvote, explain me why so I can improve it.

\$\endgroup\$
16
  • \$\begingroup\$ Yours tests seems a bit contraditory. The number is the chance of the next face (line), so what's the point of the empty line in the example / test 4? By the same logic, the test1 should have a 3/4 of outputting nothing? What is the point of the 0 in the test 4? \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:03
  • \$\begingroup\$ Why is the chance of outputting ( ͡° ͜ʖ ͡°) 1/42 and not 0 ? (since there are no numbers above it) \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:04
  • \$\begingroup\$ Sorry ! I forgot to copy paste the fact that the minimal chance is 1! \$\endgroup\$ Jul 3, 2017 at 14:05
  • \$\begingroup\$ Also, a common thing to do on challenges involving randomness, and therefore, hard to test, is to ask people to provide a mandatory explanation, or at least ask them to show why it works. \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:05
  • \$\begingroup\$ @Dada thanks. I note this. \$\endgroup\$ Jul 3, 2017 at 14:06
  • \$\begingroup\$ @Rod the empty line is a lennyface, as said here : If there is nothing on a line, you must consider it as a lennyface. \$\endgroup\$ Jul 3, 2017 at 14:08
  • \$\begingroup\$ @V.Courtois I meant and empty line without a preceding number \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:09
  • \$\begingroup\$ As I said, the minimum is one (sorry again for forgetting it). \$\endgroup\$ Jul 3, 2017 at 14:10
  • 1
    \$\begingroup\$ If only positive integers are to be expected, you should write it. Otherwise, give some details and examples about what you consider "numbers". \$\endgroup\$
    – Dada
    Jul 3, 2017 at 14:12
  • \$\begingroup\$ @Dada editing. In fact I said the minimum is 1, but you can have things like 2,-1,-3,17 and then your lennyface ; that means the probability is 15/ total. \$\endgroup\$ Jul 3, 2017 at 14:14
  • \$\begingroup\$ @V.Courtois just a small suggestion, to make the "list as circle" more explicit you could change the value to something else than 0 or 1, this way it would not overlap the "missing number" rule \$\endgroup\$
    – Rod
    Jul 3, 2017 at 14:15
  • \$\begingroup\$ @Rod does it? Sorry if I'm not getting what you are saying, but the list is always a circle, meaning if your list is 2,3,( ͡° ͜ʖ ͡°),4,5,☞  ͜ʖ  ☞,6, you have 6+2+3 chance of getting ( ͡° ͜ʖ ͡°) and 4+5 chance of getting ☞  ͜ʖ  ☞. \$\endgroup\$ Jul 3, 2017 at 14:18
  • \$\begingroup\$ thanks for editing @musicman523 \$\endgroup\$ Jul 4, 2017 at 7:21
  • 5
    \$\begingroup\$ KISS. This is far more complicated than common sense would require. Deliberately overcomplicating things to make it "more difficult" is a guaranteed method to make a bad question. \$\endgroup\$ Jul 4, 2017 at 7:32
  • 1
    \$\begingroup\$ The challenge has two parts as far as I can tell. a) Create a probability mass function from an input by parsing b) sample from the probability mass function. Part a) needs to be rewritten as it is at best ambiguous and at worst just incorrect. \$\endgroup\$
    – user9206
    Jul 5, 2017 at 7:50
-1
\$\begingroup\$

Golf Cubically code

Your task is to optimize Cubically source code using one or more optimizations in this post.

How this challenge works:

  • You will choose one or more optimizations below and write a program (in the language of your choice) that performs those optimizations on a Cubically program.
  • Your program will take a Cubically program as input using any allowed input methods, and output a Cubically program using any allowed output methods.
  • The first answer to successfully perform all optimizations wins!

Optimizations

1. Face turn arguments

Before a face turn is performed, the interpreter calculates turns = turns mod 4. So R5 would be equivalent to R1 which is equivalent to R, R7 is equivalent to R3 which is equivalent to R', etc. Also note that R11111 is equivalent to R5, and R22 is equivalent to nothing at all.

Performing this optimization will mean evaluating all arguments to an R, L, U, D, M, E, or S command and shortening them as much as possible.

Test cases:

Relevant code -> Optimization
R11           -> R2
R1            -> R
L33           -> L2
U22           ->
D222          -> D2
M11111        -> M
E00001        -> E
S9            -> S

2. Repeated face turn

When multiple calls to the same face turn command are present right next to each other, they can clearly be golfed. For example, R2R1 is equivalent to R3. UUU is equivalent to U3. F2F2F2F2 is equivalent F8.

Test cases:

Relevant code -> optimization
R2R2R2        -> R6            (R2 if you also choose optimization 1)
LLL           -> L3
UU            -> UU or U2
D3D2D1        -> D6            (D2 if you also choose optimization 1)

3. "Set notepad to" commands

There are some commands that, instead of adding to/subtracting from/multiplying by/dividing by the notepad, just assign to it. Here are all such commands:

_^=<>⊕«»·|:

When called with multiple arguments, since each argument calls the command separately, only the final argument is relevant. So =123 is equivalent to =3, _00000 is equivalent to _0, and :12345678987654321 is equivalent to 1.

Test cases:

Relevant code -> Optimization
_333          -> _3
=12321        -> =1
+54321        -> +54321
:55           -> :5
/55           -> /55

4. Repeated non-face-turn commands

When multiple face turn commands are present right by each other, their arguments can simply be added together. Commands do not act this way. While R2 calls R with 2, =2 calls = with the face sum of the front face (face index 2).

To perform this optimization, when multiple commands outside of RLUDFBMES appear next to each other, simply remove the duplicated commands without removing the arguments.

Relevant code -> Optimization
_1_1_1_1      -> _1111         (_1 if you also choose optimization 3)
%11%22%33     -> %112233       (%3 if you also choose optimization 3)
+12345+67+8   -> +12345678

5. Nonexistent commands

Go check out the Cubically commands page and you'll see that there are plenty of characters that are not commands. For example, there are no commands that are lowercase letters.

To perform this optimization, remove all nonexistent commands and their arguments from the Cubically source. If the commands also have arguments, you must remove the arguments so that they are not passed to the previous command.

Test cases:

Relevant code -> Optimization
moo cow moo   -> 
moo2cow2moo   -> 
misteR2 FOO   -> R2F
FEAR ME.      -> ERME
u1U2u3U4u5U6  -> U2U4U6   (nothing if you also choose optimization 1, U12 if you also choose optimization 2)

6. Non-implicit commands

There are lots of implicit commands in Cubically (RLUDFBMES()$~&E!), but there are plenty that need to be called with arguments. So %%%% is equivalent to nothing at all while %%2%% is equivalent to %2.

Test cases:

Relevant code -> Optimization
%%%%          -> 
$$$$          -> $$$$
++2++2++2     -> +2+2+2                 (+222 if you also choose optimization 4)
+++>--<-      -> Not Brainf**k, sorry!  (:P)

Sandbox

I'll add more optimizations later.

\$\endgroup\$
2
  • \$\begingroup\$ Clarification on R123: That's the same as R6 and R2, not R3, right? Digits are summed, there are multidigit numbers? That would be better to specify \$\endgroup\$
    – isaacg
    Aug 17, 2017 at 20:13
  • \$\begingroup\$ A few things: first, I can't find the tag "fgitw", is there a typo? Second, does optimization 1 require handling F and B as well, or just the currently listed ones? Third, in optimization 3 most of the listed commands seem invalid because the notepad is used in calculation and then overwritten with the output; for example =11 is not the same as =1 in most circumstances. In fact, I think only _: are valid. Fourth, is the winning answer one which performs all optimizations in a single program, or one which contains a separate program for each optimization? \$\endgroup\$ Aug 18, 2017 at 18:03
-1
\$\begingroup\$

Hungry for Apples?

enter image description here

This challenge is simple, given an integer 0 <= n or 0 < n, output an ASCII-apple with that many bites taken out of it.


No bites (0):

         //
     .-.:|.-.
   .'   ''   '.
   ;          ;
  :            :
  :            :
  :            :
   :          ;
   '.        :
     '-_.._-'

Bite 1:

         //
     .-.:|.-.
   .'   ''   '.
   ;          ;
   '-.         :
     }         :
   .-'         :
   :          ;
   '.        :
     '-_.._-'

Bite 2:

         //
     .-.:|.-.
   .'   ''   '.
   '-.        ;
     }         :
     }         :
     }         :
   .-'        ;
   '.        :
     '-_.._-'

Bite 3:

         //
     .-.:|.-.
   .'   ''   '.
   '-.        ;
     }      .-'
     }      {
     }      '-.
   .-'        ;
   '.        :
     '-_.._-'

Bite 4:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }      {
     }      {
     }      {
   .-'      '.
   '.        :
     '-_.._-'

Bite 5:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }".    {
     } }    {
     } }    {
   .-'"     '.
   '.        :
     '-_.._-'

Bite 6:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }"~".  {
     } } }  {
     } } }  {
   .-'"~"   '.
   '.        :
     '-_.._-'

Bite 7:

         //
     .-.:|.-.
   .'   ''   '.
   '-.      .-'
     }"~"~".{
     } } } }{
     } } } }{
   .-'"~"~" '.
   '.        :
     '-_.._-'

Bite >7:

[empty output]

Rules

  • You may have trailing spaces, make it consistent though.
  • You may have exactly 1 trailing newline.
  • You are NOT doing an animation here, you are taking in n and outputting an apple.
  • You may error on integers less than 0, as the spec provides n > 0.
  • You must have empty output (no error) on n > 7/8.
    • You threw out the core; you didn't error the core into non-existence.

This is

\$\endgroup\$
3
  • 3
    \$\begingroup\$ I feel this would be better if there was some more symmetry in the 5, 6, and 7 bytes so that people could possibly make better compression. \$\endgroup\$ Aug 4, 2017 at 18:26
  • \$\begingroup\$ @AdmBorkBork better? \$\endgroup\$ Aug 22, 2017 at 21:26
  • 1
    \$\begingroup\$ Yes, much better. \$\endgroup\$ Aug 23, 2017 at 12:33
-1
\$\begingroup\$

Proper Kerning

Kerning is the adjustment of spacing between pairs of letters in order to obtain an aesthetic result. When kerning is applied automatically by a program (typically whatever editor you're using), it is said to be automatic. There are two types of automatic kerning. The one used in this challenge is metric kerning. With metric kerning, the amount of space between pairs of letters is dictated by the kerning tables found in the font file.

Given a TrueType font file, output the kerning values for each mapping in the kerning table for ASCII characters 48 - 122 inclusive.

Example

calibri.ttf

l="A" r="C" v="-15"
l="A" r="G" v="-15"
l="A" r="J" v="23"
l="A" r="O" v="-23"
l="A" r="Q" v="-23"
l="A" r="T" v="-160"
l="A" r="U" v="-32"
l="A" r="V" v="-89"
l="A" r="W" v="-80"
l="A" r="Y" v="-150"
l="A" r="t" v="-52"
l="A" r="v" v="-38"
l="A" r="y" v="-41"
l="A" r="?" v="-68"
l="B" r="A" v="-20"
l="B" r="T" v="-48"
l="B" r="V" v="-25"
l="B" r="W" v="-24"
l="B" r="X" v="-44"
l="B" r="Y" v="-57"
l="B" r="Z" v="-20"
l="B" r="f" v="-20"
l="B" r="t" v="-20"
l="B" r="v" v="-20"
l="B" r="x" v="-15"
l="B" r="y" v="-20"
l="C" r="G" v="-18"
l="C" r="J" v="12"
l="C" r="O" v="-18"
l="C" r="Q" v="-18"
l="C" r="T" v="10"
l="D" r="A" v="-30"
l="D" r="J" v="-22"
l="D" r="T" v="-23"
l="D" r="V" v="-24"
l="D" r="W" v="-14"
l="D" r="X" v="-31"
l="D" r="Y" v="-39"
l="D" r="Z" v="-22"
l="E" r="A" v="-22"
l="E" r="C" v="-24"
l="E" r="G" v="-24"
l="E" r="O" v="-32"
l="E" r="Q" v="-32"
l="E" r="S" v="-20"
l="E" r="Z" v="-10"
l="E" r="a" v="-34"
l="E" r="c" v="-28"
l="E" r="d" v="-30"
l="E" r="e" v="-37"
l="E" r="f" v="-64"
l="E" r="o" v="-37"
l="E" r="q" v="-30"
l="E" r="t" v="-24"
l="E" r="v" v="-48"
l="E" r="w" v="-34"
l="E" r="y" v="-48"
l="F" r="A" v="-115"
l="F" r="C" v="-18"
l="F" r="G" v="-18"
l="F" r="J" v="-109"
l="F" r="O" v="-18"
l="F" r="Q" v="-18"
l="F" r="S" v="-29"
l="F" r="X" v="-22"
l="F" r="Z" v="-11"
l="F" r="a" v="-55"
l="F" r="c" v="-28"
l="F" r="d" v="-20"
l="F" r="e" v="-30"
l="F" r="o" v="-28"
l="F" r="q" v="-20"
l="F" r="s" v="-35"
l="G" r="T" v="-10"
l="G" r="V" v="-10"
l="G" r="W" v="-9"
l="G" r="Y" v="-30"
l="G" r="v" v="-29"
l="G" r="w" v="-22"
l="G" r="x" v="-14"
l="G" r="y" v="-30"
l="J" r="A" v="-35"
l="J" r="X" v="-20"
l="K" r="C" v="-78"
l="K" r="G" v="-80"
l="K" r="O" v="-97"
l="K" r="Q" v="-97"
l="K" r="S" v="-18"
l="K" r="U" v="-29"
l="K" r="W" v="-34"
l="K" r="a" v="-34"
l="K" r="c" v="-40"
l="K" r="d" v="-33"
l="K" r="e" v="-37"
l="K" r="f" v="-25"
l="K" r="m" v="-32"
l="K" r="n" v="-32"
l="K" r="o" v="-37"
l="K" r="p" v="-32"
l="K" r="q" v="-33"
l="K" r="r" v="-32"
l="K" r="s" v="-18"
l="K" r="t" v="-38"
l="K" r="u" v="-32"
l="K" r="v" v="-101"
l="K" r="w" v="-95"
l="K" r="y" v="-85"
l="L" r="C" v="-22"
l="L" r="G" v="-47"
l="L" r="J" v="25"
l="L" r="O" v="-45"
l="L" r="Q" v="-45"
l="L" r="T" v="-150"
l="L" r="U" v="-44"
l="L" r="V" v="-147"
l="L" r="W" v="-118"
l="L" r="Y" v="-167"
l="L" r="f" v="-23"
l="L" r="t" v="-38"
l="L" r="v" v="-78"
l="L" r="w" v="-72"
l="L" r="y" v="-79"
l="O" r="A" v="-23"
l="O" r="J" v="-27"
l="O" r="T" v="-55"
l="O" r="V" v="-25"
l="O" r="W" v="-22"
l="O" r="X" v="-64"
l="O" r="Y" v="-55"
l="O" r="Z" v="-38"
l="O" r="x" v="-12"
l="O" r="z" v="-10"
l="P" r="A" v="-151"
l="P" r="J" v="-140"
l="P" r="T" v="-9"
l="P" r="V" v="-10"
l="P" r="X" v="-35"
l="P" r="Y" v="-11"
l="P" r="Z" v="-29"
l="P" r="a" v="-44"
l="P" r="c" v="-43"
l="P" r="d" v="-34"
l="P" r="e" v="-41"
l="P" r="f" v="12"
l="P" r="o" v="-41"
l="P" r="q" v="-34"
l="P" r="s" v="-32"
l="P" r="t" v="12"
l="P" r="y" v="12"
l="Q" r="J" v="41"
l="Q" r="T" v="-47"
l="Q" r="V" v="-25"
l="Q" r="W" v="-12"
l="Q" r="X" v="12"
l="Q" r="Y" v="-46"
l="Q" r="g" v="59"
l="Q" r="j" v="79"
l="Q" r="x" v="31"
l="Q" r=";" v="60"
l="Q" r="]" v="32"
l="R" r="C" v="-18"
l="R" r="G" v="-19"
l="R" r="O" v="-20"
l="R" r="Q" v="-20"
l="R" r="S" v="-27"
l="R" r="T" v="-20"
l="R" r="V" v="-28"
l="R" r="W" v="-18"
l="R" r="Y" v="-30"
l="R" r="e" v="-36"
l="R" r="o" v="-42"
l="R" r="v" v="-26"
l="R" r="w" v="-33"
l="R" r="y" v="-33"
l="S" r="A" v="-15"
l="S" r="J" v="-9"
l="S" r="T" v="-14"
l="S" r="V" v="-14"
l="S" r="W" v="-15"
l="S" r="X" v="-13"
l="S" r="Y" v="-20"
l="S" r="v" v="-23"
l="S" r="w" v="-17"
l="S" r="y" v="-25"
l="T" r="A" v="-160"
l="T" r="C" v="-42"
l="T" r="G" v="-59"
l="T" r="J" v="-65"
l="T" r="O" v="-58"
l="T" r="Q" v="-58"
l="T" r="S" v="-10"
l="T" r="T" v="28"
l="T" r="a" v="-160"
l="T" r="c" v="-177"
l="T" r="d" v="-147"
l="T" r="e" v="-182"
l="T" r="g" v="-151"
l="T" r="m" v="-127"
l="T" r="n" v="-127"
l="T" r="o" v="-182"
l="T" r="p" v="-127"
l="T" r="q" v="-147"
l="T" r="r" v="-127"
l="T" r="s" v="-153"
l="T" r="u" v="-127"
l="T" r="v" v="-92"
l="T" r="w" v="-86"
l="T" r="x" v="-90"
l="T" r="y" v="-93"
l="T" r="z" v="-142"
l="T" r=";" v="-114"
l="T" r=":" v="-134"
l="U" r="A" v="-45"
l="U" r="J" v="-40"
l="V" r="A" v="-96"
l="V" r="C" v="-18"
l="V" r="G" v="-25"
l="V" r="J" v="-80"
l="V" r="O" v="-27"
l="V" r="Q" v="-27"
l="V" r="S" v="-12"
l="V" r="V" v="9"
l="V" r="a" v="-114"
l="V" r="c" v="-103"
l="V" r="d" v="-87"
l="V" r="e" v="-102"
l="V" r="g" v="-100"
l="V" r="m" v="-50"
l="V" r="n" v="-50"
l="V" r="o" v="-86"
l="V" r="p" v="-50"
l="V" r="q" v="-87"
l="V" r="r" v="-50"
l="V" r="s" v="-90"
l="V" r="u" v="-50"
l="V" r="y" v="-35"
l="V" r="z" v="-82"
l="V" r=";" v="-108"
l="V" r=":" v="-73"
l="W" r="A" v="-93"
l="W" r="C" v="-22"
l="W" r="G" v="-22"
l="W" r="J" v="-88"
l="W" r="O" v="-22"
l="W" r="Q" v="-22"
l="W" r="S" v="-10"
l="W" r="X" v="-13"
l="W" r="a" v="-71"
l="W" r="c" v="-78"
l="W" r="d" v="-72"
l="W" r="e" v="-75"
l="W" r="g" v="-54"
l="W" r="m" v="-60"
l="W" r="n" v="-60"
l="W" r="o" v="-86"
l="W" r="p" v="-60"
l="W" r="q" v="-72"
l="W" r="r" v="-60"
l="W" r="s" v="-73"
l="W" r="u" v="-60"
l="W" r="v" v="-34"
l="W" r="y" v="-53"
l="W" r=";" v="-156"
l="X" r="C" v="-57"
l="X" r="G" v="-65"
l="X" r="O" v="-57"
l="X" r="Q" v="-57"
l="X" r="S" v="-20"
l="X" r="d" v="-44"
l="X" r="e" v="-39"
l="X" r="g" v="-9"
l="X" r="o" v="-38"
l="X" r="q" v="-44"
l="X" r="t" v="-31"
l="X" r="u" v="-38"
l="X" r="v" v="-55"
l="X" r="w" v="-49"
l="X" r="y" v="-43"
l="Y" r="A" v="-152"
l="Y" r="C" v="-67"
l="Y" r="G" v="-67"
l="Y" r="J" v="-112"
l="Y" r="O" v="-66"
l="Y" r="Q" v="-66"
l="Y" r="S" v="-17"
l="Y" r="Z" v="-10"
l="Y" r="a" v="-134"
l="Y" r="c" v="-159"
l="Y" r="d" v="-131"
l="Y" r="e" v="-147"
l="Y" r="f" v="-62"
l="Y" r="g" v="-142"
l="Y" r="i" v="-32"
l="Y" r="j" v="-49"
l="Y" r="m" v="-94"
l="Y" r="n" v="-94"
l="Y" r="o" v="-153"
l="Y" r="p" v="-94"
l="Y" r="q" v="-131"
l="Y" r="r" v="-94"
l="Y" r="s" v="-115"
l="Y" r="t" v="-44"
l="Y" r="u" v="-94"
l="Y" r="v" v="-69"
l="Y" r="w" v="-62"
l="Y" r="x" v="-70"
l="Y" r="y" v="-65"
l="Y" r="z" v="-100"
l="Y" r=";" v="-138"
l="Y" r=":" v="-154"
l="Z" r="A" v="-11"
l="Z" r="C" v="-25"
l="Z" r="G" v="-24"
l="Z" r="O" v="-24"
l="Z" r="Q" v="-24"
l="Z" r="W" v="-7"
l="Z" r="Y" v="-7"
l="Z" r="a" v="-10"
l="Z" r="c" v="-12"
l="Z" r="d" v="-18"
l="Z" r="e" v="-31"
l="Z" r="o" v="-29"
l="Z" r="q" v="-18"
l="Z" r="v" v="-45"
l="Z" r="w" v="-38"
l="Z" r="y" v="-37"
l="a" r="f" v="-12"
l="a" r="t" v="-19"
l="a" r="v" v="-34"
l="a" r="w" v="-14"
l="a" r="x" v="-19"
l="a" r="y" v="-38"
l="b" r="f" v="-17"
l="b" r="s" v="-10"
l="b" r="t" v="-9"
l="b" r="v" v="-10"
l="b" r="w" v="-10"
l="b" r="x" v="-41"
l="b" r="y" v="-10"
l="b" r="z" v="-28"
l="c" r="a" v="-17"
l="c" r="o" v="-17"
l="e" r="f" v="-18"
l="e" r="t" v="-11"
l="e" r="v" v="-10"
l="e" r="w" v="-10"
l="e" r="x" v="-31"
l="e" r="y" v="-13"
l="e" r="z" v="-20"
l="f" r="a" v="-40"
l="f" r="c" v="-45"
l="f" r="d" v="-53"
l="f" r="e" v="-51"
l="f" r="f" v="-20"
l="f" r="g" v="-60"
l="f" r="o" v="-43"
l="f" r="q" v="-53"
l="f" r="s" v="-27"
l="f" r="v" v="13"
l="f" r="w" v="6"
l="f" r="y" v="10"
l="f" r="z" v="-20"
l="g" r="a" v="-38"
l="g" r="c" v="-12"
l="g" r="d" v="-19"
l="g" r="e" v="-17"
l="g" r="g" v="19"
l="g" r="o" v="-14"
l="g" r="q" v="-19"
l="g" r="t" v="-31"
l="h" r="f" v="-12"
l="h" r="t" v="-19"
l="h" r="v" v="-34"
l="h" r="w" v="-14"
l="h" r="x" v="-19"
l="h" r="y" v="-38"
l="k" r="a" v="-35"
l="k" r="c" v="-48"
l="k" r="d" v="-56"
l="k" r="e" v="-66"
l="k" r="o" v="-69"
l="k" r="q" v="-56"
l="k" r="s" v="-19"
l="k" r="t" v="-10"
l="k" r="u" v="-26"
l="m" r="f" v="-12"
l="m" r="t" v="-19"
l="m" r="v" v="-34"
l="m" r="w" v="-14"
l="m" r="x" v="-19"
l="m" r="y" v="-38"
l="n" r="f" v="-12"
l="n" r="t" v="-19"
l="n" r="v" v="-34"
l="n" r="w" v="-14"
l="n" r="x" v="-19"
l="n" r="y" v="-38"
l="o" r="v" v="-9"
l="o" r="w" v="-8"
l="o" r="x" v="-40"
l="o" r="y" v="-11"
l="o" r="z" v="-27"
l="p" r="f" v="-17"
l="p" r="s" v="-10"
l="p" r="t" v="-9"
l="p" r="v" v="-10"
l="p" r="w" v="-10"
l="p" r="x" v="-41"
l="p" r="y" v="-10"
l="p" r="z" v="-28"
l="q" r="g" v="10"
l="r" r="a" v="-42"
l="r" r="c" v="-30"
l="r" r="d" v="-28"
l="r" r="e" v="-27"
l="r" r="g" v="-28"
l="r" r="o" v="-33"
l="r" r="q" v="-28"
l="r" r="s" v="-35"
l="r" r="v" v="19"
l="r" r="w" v="11"
l="r" r="y" v="10"
l="s" r="f" v="-19"
l="s" r="t" v="-23"
l="s" r="v" v="-31"
l="s" r="w" v="-10"
l="s" r="x" v="-22"
l="s" r="y" v="-37"
l="s" r="z" v="-18"
l="t" r="a" v="-25"
l="t" r="c" v="-25"
l="t" r="d" v="-23"
l="t" r="e" v="-22"
l="t" r="o" v="-20"
l="t" r="q" v="-23"
l="t" r="t" v="-29"
l="v" r="a" v="-30"
l="v" r="c" v="-25"
l="v" r="d" v="-20"
l="v" r="e" v="-20"
l="v" r="f" v="11"
l="v" r="g" v="-28"
l="v" r="o" v="-19"
l="v" r="q" v="-20"
l="v" r="s" v="-9"
l="v" r="t" v="10"
l="v" r="v" v="12"
l="v" r="w" v="12"
l="v" r="y" v="12"
l="v" r="z" v="-26"
l="w" r="a" v="-23"
l="w" r="c" v="-20"
l="w" r="d" v="-18"
l="w" r="e" v="-18"
l="w" r="f" v="6"
l="w" r="g" v="-18"
l="w" r="o" v="-19"
l="w" r="q" v="-18"
l="w" r="s" v="-18"
l="w" r="t" v="4"
l="w" r="v" v="12"
l="w" r="w" v="8"
l="w" r="y" v="12"
l="w" r="z" v="-17"
l="x" r="a" v="-37"
l="x" r="c" v="-46"
l="x" r="d" v="-44"
l="x" r="e" v="-54"
l="x" r="o" v="-55"
l="x" r="q" v="-44"
l="x" r="s" v="-12"
l="x" r="t" v="6"
l="x" r="u" v="-20"
l="y" r="a" v="-31"
l="y" r="c" v="-26"
l="y" r="d" v="-24"
l="y" r="e" v="-25"
l="y" r="f" v="10"
l="y" r="g" v="-26"
l="y" r="o" v="-24"
l="y" r="q" v="-24"
l="y" r="s" v="-19"
l="y" r="t" v="10"
l="y" r="v" v="12"
l="y" r="w" v="8"
l="y" r="y" v="10"
l="y" r="z" v="-17"
l="z" r="a" v="-34"
l="z" r="c" v="-45"
l="z" r="d" v="-46"
l="z" r="e" v="-46"
l="z" r="f" v="-10"
l="z" r="g" v="-17"
l="z" r="o" v="-45"
l="z" r="q" v="-46"
l="z" r="s" v="-22"
l="z" r="u" v="-10"
l="z" r="v" v="-18"
l="z" r="w" v="-22"
l="z" r="y" v="-18"

Scoring

This is , so the shortest answer (in bytes) wins.

Meta

I know this challenge is going to need a lot of work before it's ready for main. Please hold criticisms for now. Helpful ideas and thoughts are welcome.

\$\endgroup\$
7
  • \$\begingroup\$ I'm not sure that the problem is well defined. There's a reason it's called font hinting: the rendering application is free to take it into account or not, or even to apply more complex logic. E.g. some fonts have multiple sets of font hints for different contexts. There are other complex issues. A font can have Latin and Cyrillic letters and define hints for kerning between pairs of Latin and pairs of Cyrillic but not between Latin and Cyrillic; however, some letters may have identical glyphs, so a judgement on whether the kerning is "correct" might be ambiguous. Then there's antialiasing. \$\endgroup\$ May 24, 2017 at 6:15
  • \$\begingroup\$ @PeterTaylor Good notes. I will likely restrict the character set. I just wanted to start getting ideas down in the sandbox. \$\endgroup\$
    – Poke
    May 24, 2017 at 6:51
  • \$\begingroup\$ Very ambiguous. \$\endgroup\$
    – anna328p
    May 25, 2017 at 17:48
  • \$\begingroup\$ @Mendeleev It's not done yet. I'm aware it's ambiguous. \$\endgroup\$
    – Poke
    May 26, 2017 at 16:10
  • \$\begingroup\$ Looking at developer.apple.com/fonts/TrueType-Reference-Manual/RM06/… I can see a number of issues to address. 16- vs 32-bit entries? Should multiple tables be combined or printed separately? All tables or only tables with certain coverage values? Which of the four defined formats need to be supported? Do you have a test case which covers glyph index differing from codepoint? \$\endgroup\$ Sep 16, 2017 at 17:28
  • \$\begingroup\$ @PeterTaylor I have a proof of concept that I wrote (it's the reason I have taken so long to update this) and I'm planning to address all of your questions. Thanks for doing a bit of research to help me out, though :] \$\endgroup\$
    – Poke
    Sep 16, 2017 at 18:57
  • \$\begingroup\$ Downvoter, why? \$\endgroup\$
    – Poke
    Oct 4, 2017 at 21:03
-1
\$\begingroup\$

Six Flags over HTTP

Let's say you need to transmit six boolean flags in a URL string. Obviously you could do it with six ones or zeroes, but you want better compression. With a little math you can pack them into two characters using 0-7 octal.

How about mapping all six to a single ASCII character? Here we have a problem: you are not allowed to use , / ? : @ & = + $ # or space. Now the range of printable ASCII no longer has 64 valid characters in a row.

In Javascript (or another language that can run from a web page, if any), what is the shortest code for a pair of functions to encode and decode this data, between an array of six booleans and a single character?

\$\endgroup\$
2
  • \$\begingroup\$ -1 language restriction, most languages have HTTP libraries so I think any language should be allowed \$\endgroup\$
    – ASCII-only
    Sep 24, 2017 at 13:11
  • \$\begingroup\$ This challenge could be improved by rephrasing it to: "Write a bijective function between an array of six booleans and a single printable character excluding the characters ,/?:@&=+$# ". Mentioning that the encoder and decoder should be separate programs/functions would be helpful. Also, may the encoder and decoder share code? \$\endgroup\$ Sep 24, 2017 at 22:08
-1
\$\begingroup\$

Count letter frequency

Inspired by question Tweetable hash function challenge, you should take the English dictionary used there and produce a program or function that outputs the the absolute and relative frequency of each character. It is CASE SENSITIVE and the APOSTROPHE is also accountable as a real letter.

Example of a valid output format (but with stupid guessing values):

A      5566    20%
...
Z        60     0.2%
a     27000    30%
...
z       120     0.01%
'       450     3.5%

It is , but no answer will be accepted. Wanna know shortest script for each language.

\$\endgroup\$
1
  • 1
    \$\begingroup\$ -1 (01) Don't rely on another challenge to define yours; include all the information we need in your write-up. (02) Make an effort to come up with some actual test cases - do you honestly expect us to verify our solutions against "stupid guessing values"? \$\endgroup\$
    – Shaggy
    Sep 30, 2017 at 0:55
-1
\$\begingroup\$

Is it a perfect loop?

Your task is to take a GIF or an animated image in any reasonable format as input (including taking the file name of a GIF in the current directory), and output whether it is a "perfect loop" - that is, the frames transition seamlessly from the end to the start, and a human cannot notice where it starts and ends at first glance. Return or print a truthy value if it is a perfect loop, otherwise print or return a falsy value.

Scoring

Winners will be determined from the percentage of test cases they get correct. In the event of a tie, highest votes wins. You can view test cases at https://ghostbin.com/paste/m3yaw. Show your score against the test cases when you post.

Input

If you are not taking input in a GIF, please provide a program that will convert a GIF to your desired format.

Images corresponding to a truthy value have been taken from /r/perfectloops and for falsy test cases, /r/almostperfectloops and /r/gifs.

Restrictions

  • Hard coding is not allowed (violates standard loophole 1 and 2).
  • You must provide consistent results for the same GIF (no randomness)
  • Remember, this is not , so byte count is not needed in your solution. Just post the language name and add the percentage correct when I comment.
\$\endgroup\$
2
  • \$\begingroup\$ I'm not sure it's as simple as comparing the first to the last frame, if it is we'd have duplicate frames. is this challenge allowing HTTP requests? \$\endgroup\$
    – tuskiomi
    Oct 17, 2017 at 21:15
  • \$\begingroup\$ If hashing the inputs is not allowed, then you should clearly define what constitutes a “perfect loop”. It's not good to extrapolate from a handful of test cases where the pass/fail cases are very similar. \$\endgroup\$
    – japh
    Oct 18, 2017 at 14:31
-1
\$\begingroup\$

Highest code size∕output ratio to generate a large executable section inside an elf file.

Your challenge is to create the shortest code in your language of choice or the tools of your choice (like objcopy) that will create an elf file with a the executable section as large as possible.
I mean that if I extract the.text section of the elf binary, the resulting extracted file should be at least 90% of the elf binary.

Requirements

  • The program should takes the desired section size as input.
  • The .text section name needs to corresponds to the executable section.
  • The type of the .text section should bePROGBITSand it should contains instructions.
  • The elf file should have a .shstrtab section.
  • The .text section should be readable and writable.
  • The target architecture should be Pnacl or armelv7 or x86_64.
  • The elf file should be valid and pass Google nacl’s validation whitelist in order to be loaded (but I don´t care if the sandbox segfault).
    If you have no idea about what Google native client is, just create a script that call the patched version of binutils from the nacl_sdk, or make sure the elf file is valid and can be executed on Linux.

Of course, you normally can’t use a compiler because it would takes too much computational years in order to finish.

Winner

The answer with the highest code size∕program output ratio.

\$\endgroup\$
9
  • 1
    \$\begingroup\$ Why not make scoring output size / code size? \$\endgroup\$
    – anna328p
    Apr 4, 2017 at 3:49
  • \$\begingroup\$ Make it a code-challenge \$\endgroup\$
    – anna328p
    Apr 4, 2017 at 3:49
  • \$\begingroup\$ This is essentially the same challenge as this one, and would be closed as a duplicate. Although it's not exactly the same, some answers to the previous question would require very little modification and answers to this question would also require very little modification to be answers to the other one. \$\endgroup\$ Apr 4, 2017 at 8:37
  • \$\begingroup\$ @Alt-F4 : it was a code challenge. \$\endgroup\$ Apr 4, 2017 at 21:52
  • \$\begingroup\$ @PeterTaylor : they were no answer to the previous question. In order to be closed as a duplicate the target needs to be already answered. You known it was closed an unclear, so please suggest change to make this answer clearer. \$\endgroup\$ Apr 4, 2017 at 21:54
  • \$\begingroup\$ Huh? It's open and has 15 answers. \$\endgroup\$ Apr 4, 2017 at 22:09
  • \$\begingroup\$ @PeterTaylor sorry, I thought to an another question that was closed as unclear and didn’t take time to read your link. In that case NO, the aim is to not use the compiler in order to actually build the file. This normally can’t be done with a compiler or an assembler. \$\endgroup\$ Apr 4, 2017 at 22:16
  • \$\begingroup\$ Can't it? Why not? \$\endgroup\$
    – wizzwizz4
    Dec 16, 2017 at 19:55
  • \$\begingroup\$ Wait... shortest code that generate any program? Or what? Don't think this is a good idea... \$\endgroup\$
    – DELETE_ME
    Jan 6, 2018 at 12:10
-1
\$\begingroup\$

Removing a Letter adds a Letter

Your program should output nothing when unaltered, however, when any single character is removed it should have an output length of 1. This extends to any number of characters being removed from the program, as long as there is, at minimum, a single character remaining.


For example, if my program were abcdefg, it should output nothing if unaltered.

However, if I were to remove a and d from this program to get bcefg, it should output any two printable characters that represent 16 bytes of information (2 characters for 2 characters removed).

  • So if bcefg outputs (00,AA,etc...) this is valid.

Taking this further, if we were to remove all but the letter g we'd need an output of 6 characters.

  • So if g outputs ('000000','@$^%@(',etc...) this is valid.

Your program must function for all possible combinations of removals that are possible, that is to say each single letter in your program should be a valid program.


Rules

  • You may "lock" pieces of the code, each locked byte counts for 2-bytes instead of 1-byte.
    • Locked bytes will never be removed.
    • For instance, if my program was abcdefg and bcd is locked, the shortest program we'll get is abcd,bcde,bcdf and bcdg.
    • If bcd was locked in abcdefg it'd be 10 bytes, not 7.
  • The program may output any byte to represent 1 removed character, N-bytes for N removed chars in the code itself.
\$\endgroup\$
4
  • \$\begingroup\$ The rule only leads to totally locked code \$\endgroup\$
    – l4m2
    Mar 13, 2018 at 0:13
  • \$\begingroup\$ @l4m2 hah. I disagree. \$\endgroup\$ Mar 13, 2018 at 0:58
  • \$\begingroup\$ But more constructively, increase the penalty? Limit locked chars? \$\endgroup\$ Mar 13, 2018 at 1:04
  • \$\begingroup\$ Maybe require an unlocked percent? \$\endgroup\$
    – l4m2
    Apr 6, 2018 at 10:52
-1
\$\begingroup\$

Sandbox:

Is this question already available (duplicate)?

Are things too vague?

Does providing the example help or hinder?

Tidy the Pantry (easy)

I hate grocery shopping, particularly the part where I put groceries away--so I'm calling upon the collective hive-mind to handle that.

Challenge

Your challenge is to take a 1D-list of groceries and a 2D pantry as input; and output an newly assorted pantry. The two variables can be of your type choice, and in any order, but please specify what item types your program requires (e.g. string, array, etc.).

Rules & Additional info.

Scoring

  • This is code golf, so the shortest answer in bytes wins

Rules

  • The pantry should be ordered alphabetically (A - Z, left to right, top to bottom)
    • For simplicity, the pantry is case-insensitive
  • The pantry must retain its horizontal size (but trailing newlines are optional)
  • "Pockets" (empty spaces) should be filled between items (i.e. only the last item is allowed to have a trailing pocket)
  • If the pantry is too small for the incoming groceries, then the pantry must replace older items (Z being the oldest, A the youngest)
    • Z from groceries is younger than A in pantry
  • Standard loopholes are forbidden

Examples ([ and ] are used for readability)

Input (4x4 pantry):

[A][A][ ][ ]
[ ][ ][B][ ]
[C][ ][ ][ ]
[ ][ ][ ][D]

AAD

Output:

[A][A][A][A]
[B][C][D][D]
[ ][ ][ ][ ]
[ ][ ][ ][ ]

Input (2x2 pantry):

[A][B]
[C][D]

XYZ

Output:

[A][X]
[Y][Z]

Example solution

JavaScript ES6 (989 bytes)

// (String, String) -> String
let organise = (pantry, groceries) => {
  let n = pantry.split("\n").sort((a, b) => b.length - a.length); // used at the end of the function for horizontal sizing
  n = n[0].length;

  pantry = pantry
    .replace(/\W/g, "") // get rid of all non-alphanumeric characters
    .split("");         // turn the string into an array

  // we need the properties of the new array
  // so the extra `pantry = pantry` is needed
  pantry = pantry
    .slice(0, pantry.length - groceries.length) // go ahead and remove the last overlapping elements
    .concat(groceries)                          // add the groceries to the pantry
    .join("")                                   // turn into a string
    .split("")                                  // turn into an array
    .sort()                                     // sort the array
    .join("");                                  // turn into a string

    return pantry.replace(RegExp(`(.{${n}})`, 'g'), "$1\n");
};

/** Testing below **/

console.log("Test #2:\n" + organise(
`AJCHDJE
JJ   JA
    ASD
OOQ I U
Q     W
      R`,

'AHJBCJHDHHATTGEH'
))


Test Cases:

Test #1, 4x4 pantry

TVCX <- pantry
ABCD
ATDJ
UAIK

XYXY <- groceries
----
AAAB <- expected output
CCDD
IJKT
XYXY

Test #2, 7x6 pantry

AJCHDJE
JJ   JA
    ASD
OOQ I U
Q     W
      R

AHJBCJHDHHATTGEH
-------
AAAAABC
CDDDEGH
HHHHJJT
T

Test #3, 10x10 pantry

AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA

ZZZZZZZZZZZZZZZZZZZZ
----------
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
AAAAAAAAAA
ZZZZZZZZZZ
ZZZZZZZZZZ

Test #4, 16x16 pantry pantry

ASDFGHJKLZXCVBNM
QJKAJ  KAKSJD  J
KJASDKFHI YOIER
W   OSDOFJ    DK
E PPPASP     AS
R
TASD 
YAAAAAAAAAAAA
U          JHOLK
IIAUSHODUYOAISUO
OASD  AUSODI 
PIASND JUASJNOIJ
A ASJDH PPOIO 
QHIAIUSOIUOOO
WYYAIUSNNAJSDASD
EAISDUUIOPJPIJPJ
ROQPEWIHRNXCAISD

QWERTYUIOP
----------------
AAAAAAAAAAAAAAAA
AAAAAAAAAAAAAAAA
ABCCDDDDDDDDDDDD
DDDEEEEEFFFGHHHH
HHHIIIIIIIIIIIII
IIIIIIJJJJJJJJJJ
JJJJJJKKKKKKKKLL
MNNNNNNOOOOOOOOO
OOOOOOOOOOPPPPPP
PPPPPPQQQQRRRRRS
SSSSSSSSSSSSSSSS
SSSTTUUUUUUUUUUU
UVWWY

Test #5, 2x2 pantry

HE
LO

[no groceries]
--
HE
LO
\$\endgroup\$
6
  • 1
    \$\begingroup\$ why divide the program score? \$\endgroup\$
    – RedClover
    Feb 26, 2018 at 19:03
  • 1
    \$\begingroup\$ I recommend you do count by bytes otherwise someone is just going to encode their entire program in Chinese characters and win. \$\endgroup\$
    – hyper-neutrino Mod
    Feb 26, 2018 at 19:09
  • \$\begingroup\$ @labela--gotoa To get a golfed score (smaller programs get a smaller score), should I change it? \$\endgroup\$ Feb 26, 2018 at 19:13
  • \$\begingroup\$ @EphellonDantzler I don't understand why not just normal scoring...? \$\endgroup\$
    – RedClover
    Feb 26, 2018 at 19:14
  • \$\begingroup\$ LOL, that's why I set in in Sandbox first @labela--gotoa \$\endgroup\$ Feb 26, 2018 at 19:16
  • 1
    \$\begingroup\$ Some notes on your reference implementation: 1 It appears far too soon in the challenge. 2 It's not 1768 bytes. 3 You need to ungolf it and make it readable or it's not much use. 4 As it's JS, create a Snippet for it. 5 Is it necessary? It seems to be thrown in there to try to patch over any holes in the challenge spec. \$\endgroup\$
    – Shaggy
    Feb 26, 2018 at 23:17
-1
\$\begingroup\$

Interpret pseudocode

Wikipedia says pseudocode

is intended for human reading rather than machine reading.

and

A program in pseudocode is not an executable program.

I don't care.

Make a pseudocode interpreter that can run pseudocode that fits the rules described below*. This is based on the IB pseudocode guide, but it is simplified quite a bit to make it fit for the challenge.


Pseudocode specifications

This is a simplified pseudocode to make the challenge less tedious. The pseudocode language has no strings, no arrays, no classes, no methods, and no variables other than integers.

Basic syntax

Comments that start at // and end at a newline (like java one-line comments). // is not necessarily followed by a space, and the comment may be empty. Example:

A = 2 + 3 // I can't write five because my keyboard is broken

Statements are separated by newlines. Lines may be empty (without statements). The exact number of spaces doesn't matter, and spaces are not required. The language is case sensitive.

Variables

All variables are global, and can be accessed anywhere. They do not need to be declared. To keep things simple, all variables can be assumed to be integers. All variable names are UPPERCASE, and consist only of letters. Your program should at least handle integers from -256 to 256. A wider range is not a requirement.

Variables are assigned values using this syntax:

VARIABLE = Expression

Where VARIABLE can be any uppercase name and expression can be any integer expression, as discussed below.

Examples:

A = 5
B = A + 3
NUMBER = A * B

Expressions

An expression can be:

  • An integer, like 42
  • A variable, like NUMBER
  • A binary operation on two other expressions, like NUMBER + 5. There are only four operations: +, -, *, /. Division rounds integers down.

Expressions can be surrounded by parentheses to indicate that they need to be evaluated first. To keep things simple, all expressions are evaluated from left to right no matter what the operations are (unless there are parentheses that specify otherwise), so

A = 2 - RM * 9 + 3 / NUMBER
B = 1 + 2 * (3 - 4) / 6

is equivalent to

A = (((2 - RM) * 9) + 3) / NUMBER
B = ((1 + 2) * (3 - 4)) / 6

Boolean expressions

Boolean expressions can compare two expressions using == (equality), != (not equal to), < (less than), and > (greater than). They are only used for control flow, as discussed below (there are no boolean variables).

Control flow

There are four types of control flow. They can be infinitely nested in all combinations.

If

if (booleanExpression) then
    // statements (discussed below)
endif

If-else

if (booleanExpression) then
    // statements (discussed below)
else
    // other statements
endif

Loop while

loop while (booleanExpression)
    // do stuff
endloop

Where booleanExpressions are boolean expressions. The ifs work the same as in normal programming languages. The while loop is a simple while loop.

The booleanExpressions will always be surrounded by (). The pseudocode is very flexible with spaces, and any number of spaces is valid.

Loop for

loop VARIABLE from Expression1 to Expression2
    // things to do over and over again
end loop

Where Expression1 and Expression2 are expressions that are evaluated before the loop begins and their values are stored until the loop finishes. The content of the loop is executed for every integer from the result of Expression1 to that of Expression1, inclusive. At every iteration, the index variable (VARIABLE in this case) is updated.

Example:

loop I from 3 to 5
    output(I)
endloop

Outputs:

3
4
5

Statements

Output

output(Expression) outputs the evaluated expression. It's like println in programming languages. So:

output(1+1)

prints 2, followed by a newline.

output() with no arguments should print a newline.

Other statements

If the interpreter encounters any other statement that looks like a method call with no arguments, it should pretend it's executing it. For example,

lightsoff()
gohome()

should print (together with a newline):

executing lightsoff
executing gohome

In other words, executing [Method name] should be printed. All statements will be lowercase and will consist entirely of letters.

Keywords cannot be statements. You do not have to deal with the following (it will not appear in the pseudocode): - if() - endif() - loop() - while() - etc.

However, statements that start with keywords are valid. For example, loophole() should print executing loophole, even though loop() itself is not valid.


Challenge rules

  • Your program should take a string as input. It can also take something equivalent, like an array of characters. But you can't take an array of strings; your program must itself separate the lines and tokens. You can also take a file as input.
  • Your program should print the output of the pseudocode in any reasonable form.
  • No standard loopholes.
  • There are no restrictions on what your program should do when given invalid pseudocode.
  • This is code golf. The shortest code in bytes wins.

Example output

1

A = 3
output(A) // prints 3
B = 4 + A * 2
output(B)
helloworld()
output(A + B + 1 * 3)

Should give:

3
14
executing helloworld
54

2

loop NUM from 2 to 20 // cycle through possible prime numbers
    COUNT = 0
    loop DIV from 2 to NUM // cycle through possible divisors
        if(NUM/DIV*DIV == NUM) then // if the number is exactly divisible
            COUNT = COUNT + 1
        endif
    endloop
    if (COUNT == 2) then // if number is prime
        output(NUM)
    endif
endloop

Should give:

2
3
5
7
11
13
17
19

3

Tricky cases that your interpreter should handle:

// empty comment:
//
// empty line:

    // more comment testing // ///
////

if     (3<4) then
    endoftheworld() // a statement
    ifff()
    endifnot()
    // endif in a comment doesn't count
endif
// loops can be empty:
loop I from 0 to 10
endloop
output(I) // variables are global
if(1<2)
    if(3<4) // nesting is ok
        ok()
    endif
endif
// spacing doesn't matter:
output   (2+   8   - 1   )
loop             while(2<1)
    neverhappened()
endloop

Should output:

executing endoftheworld
executing ifff
executing endifnot
10
excecuting ok
9

*Technically, once pseudocode follows rules as strict as those described here, it is arguably not pseudocode anymore. Wikipedia says it's called skeleton code.


Any suggestions?

I double-checked all the specifications, but if anything seems reasonably unclear, please let me know.

\$\endgroup\$
4
  • \$\begingroup\$ Actually that's because the challenge is uninteresting. \$\endgroup\$
    – Xwtek
    May 3, 2018 at 2:11
  • \$\begingroup\$ @Akangka thanks for the feedback. How do you think it could be made more interesting? \$\endgroup\$ May 3, 2018 at 16:47
  • \$\begingroup\$ Unfortunately, there is nothing to improve. You have to find other challenge. Also, it is not pseudo-code. \$\endgroup\$
    – Xwtek
    May 4, 2018 at 3:03
  • \$\begingroup\$ @Ok, thanks. I'll try to think of something. Also, read the *note. :) \$\endgroup\$ May 5, 2018 at 19:39
-1
\$\begingroup\$

Common Logic Gates

Given positive integer n, make a common n-to-1 gate with fewest input, i.e. make a function f: {0,1}k ↦ {0,1} with smallest k that, for each function g: {0,1}n ↦ {0,1}, there exists {ak}, such that each element ai in the sequence map to one of 0, 1, x1, x2, x3, ..., xn, satisfying that, for each {xn}, g(x1, x2, x3, ..., xn) = f(a1, a2, a3, ..., an).

Samples:

To make a common 1-to-1 gate, your circuit must take at least 2 input:

f(A,B) = A XOR B

For a buffer gate (g = x1 ↦ x1), let A=0 and B=Input (a1 = 0, a2 = x1); for a not gate (g = x1 ↦ ¬x1) , let A=1 and B=Input (a1 = 1, a2 = x1).

Alternatively, you can use f(A,B) = A AND NOT B. For a buffer gate, let B=0 and A=Input; for a not gate, let A=1 and B=Input.

To make a common 2-to-1 gate, the circuit must take at least 4 input bits: (The two inputs are represented as a and b)

f(A,B,C,D) = ((A AND B) OR (C AND NOT B)) XOR D

(ab)
00 01 10 11 A B C D
0  0  0  1  a b 0 0
0  0  1  0  0 b a 0
0  1  1  0  a a a b
0  1  1  1  1 b a 0
1  0  0  0  1 b a 1
1  0  0  1  0 a 1 b
1  1  0  1  0 b a 1
1  1  1  0  a b 0 1

Output can be an boolean expression with reasonable logic gates, or just the output corresponding to all possible input of the n-to-1 function f (the truth table of f). If there are more than one possible functions, you can output any of them.

Shortest code in bytes win.

Code that matches the requirement:

function solve(n) { // n positive int
    var res = [], tmp=[], inmap=[], need=[];
    for (var i=1; ; i++) {
        for (var _res=0; _res<2**(2**i); _res++) {
            var valid = 1;
            for (var j=0; j<2**i; j++)
                tmp[j] = Math.floor(_res/2**j)%2;
            for (var _need=0; _need<2**(2**n); _need++) {
                for (var j=0; j<2**n; j++) 
                    need[j] = Math.floor(_need/2**j)%2;
                var valid2 = 0;
                for (var _inmap=0; _inmap<(n+2)**i; _inmap++) {
                    var valid3 = 1;
                    for (var j=0; j<i; j++) 
                        inmap[j] = Math.floor(_inmap/(n+2)**j)%(n+2) - 1;
                    for (var j=0; j<2**n; j++) {
                        var bits = 0;
                        for (var k=0; k<i; k++) {
                            if (inmap[k]==-1 || (inmap[k] && (j>>(inmap[k]-1))%2))
                                bits |= 1 << k;
                        }
                        if (tmp[bits] != need[j]) 
                            valid3 = 0;
                    }
                    valid2 |= valid3;
                }
                if (!valid2) valid = 0;
            }
            if (valid) 
                res.push (tmp.slice());
        }
        if (res.length) 
            return res[AnyNonNegativeIntegerLessThan(res.length)];
        // binary index input
    }
}

function AnyNonNegativeIntegerLessThan(x) { if(R>=x) throw ("end"); return R;}
for (R=0; ; R++) { console.log (solve(1)); }

\$\endgroup\$
19
  • \$\begingroup\$ You don't define what an n-to-1 gate is anywhere in your question. \$\endgroup\$
    – Wheat Wizard Mod
    Mar 27, 2018 at 1:00
  • \$\begingroup\$ @user202729 @user56656 n-to-1 gate means a gate with n input and 1 output. common n-to-1 logic gate mean a logic gate that can be used to replace any n-to-1 gate with some proper wiring. You can treat a logic gate as a ROM(so you can decide for each input what the output is) \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 1:15
  • \$\begingroup\$ Output gates or ROM \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 1:25
  • \$\begingroup\$ You should put the definitions in the challenge. "that can be used to replace any n-to-1 gate with some proper wiring" is still not very clear, you should define more carefully what you mean by proper wiring. \$\endgroup\$
    – Wheat Wizard Mod
    Mar 27, 2018 at 3:22
  • \$\begingroup\$ I assume you mean functions g: {0,1}^n -> {0,1}, right? Why do you specify x_0 and x_-1? Shouldn't x just be a vector with indices 1,2,3,...,n? \$\endgroup\$
    – flawr
    Mar 27, 2018 at 14:07
  • \$\begingroup\$ Is {a_k} just a subset of {1,2,3,...,n}? Or can we have a_1=a_2=a_3=1 for example? \$\endgroup\$
    – flawr
    Mar 27, 2018 at 14:09
  • \$\begingroup\$ {a_k} seems not a multiset. It should be an array or say a sequence of numbers \$\endgroup\$
    – l4m2
    Mar 27, 2018 at 14:43
  • \$\begingroup\$ So you're asking for something which outputs answers to codegolf.stackexchange.com/q/24983/194 ? \$\endgroup\$ Mar 28, 2018 at 11:33
  • \$\begingroup\$ @PeterTaylor No. it requires to use NAND gate to make up one circult that do the thing. Also 24983 is a 1-of-4 (74LS153), not a 4-to-1 gate common 2-to-1 \$\endgroup\$
    – l4m2
    Mar 28, 2018 at 12:41
  • \$\begingroup\$ (+) Any reason for downvoting? Downvoting in the sandbox indicates that the challenge is incomplete, if you don't leave a comment the OP can't know what is wrong. \$\endgroup\$
    – DELETE_ME
    Mar 29, 2018 at 4:48
  • \$\begingroup\$ @user202729, there are already comments indicating that this question is going to attract close votes as unclear if it's posted to main in the current state. \$\endgroup\$ Mar 29, 2018 at 10:59
  • \$\begingroup\$ @user56656 Are the issues fixed now? \$\endgroup\$
    – DELETE_ME
    Mar 31, 2018 at 15:16
  • \$\begingroup\$ @flawr Are the issues fixed now? \$\endgroup\$
    – DELETE_ME
    Mar 31, 2018 at 15:16
  • 1
    \$\begingroup\$ No I still think the explanation is quite bad and the notation is not very clear \$\endgroup\$
    – flawr
    Mar 31, 2018 at 16:15
  • \$\begingroup\$ A reference implementation is no substitute for a clear specification. The first paragraph is where you need to focus your efforts. \$\endgroup\$ Mar 31, 2018 at 19:32
-1
\$\begingroup\$

Is the program 32 or 64 bits?

Assignment is simple to explain: write the shortest code you need to determine whether an executable binary program supplied as parameter is 32 or 64 bits.

If there is a different kind of bitness, you can also do for it, but is not mandatory.

What I really don't want is telling me you support other bitnesses and after I get 32 or 64 as a result.

Valid outputs for 32:

32
32bit
32bits
32 bit
32 bits

The same pattern for 64.

No accepted answer.

\$\endgroup\$
12
  • \$\begingroup\$ I think you're missing a word somewhere in the region of "determine supplied" \$\endgroup\$ Apr 4, 2018 at 19:43
  • \$\begingroup\$ @KamilDrakari thanks. \$\endgroup\$
    – sergiol
    Apr 4, 2018 at 19:53
  • \$\begingroup\$ Executable on Windows or Linux machine? What if (... maybe ...) the program is a valid executable for both "bitness" but do different things? \$\endgroup\$
    – DELETE_ME
    Apr 5, 2018 at 1:30
  • \$\begingroup\$ Of the output formats you allow, I think the first one will result in the shortest code in every single language. Because of this, you might as well just specify that the output should be the number 32 or the number 64. \$\endgroup\$
    – N. Virgo
    Apr 5, 2018 at 8:03
  • \$\begingroup\$ This made me wonder what to do about shell scripts, which are executable programs, but require another file to interpret them and as such aren't 32-bit or 64-bit per se. Maybe it would be best to specify "executable binary file" to not have to deal with that mess. \$\endgroup\$
    – Angs
    Apr 5, 2018 at 11:22
  • \$\begingroup\$ @Angs: Thanks. Changed. \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:27
  • \$\begingroup\$ @user202729: I don't care. Windows, Linux, Mac, whatever, ... \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:28
  • \$\begingroup\$ @Nathaniel: It is intentional. If you have a language feature called bitness(program) returning 32bits you do not need to waste more bytes removing the bits part! \$\endgroup\$
    – sergiol
    Apr 5, 2018 at 11:30
  • \$\begingroup\$ The word "challenge" is not really true, at least for ELF. It's absolutely trivial. \$\endgroup\$ Apr 6, 2018 at 20:20
  • \$\begingroup\$ @PeterTaylor : Changed, thanks. \$\endgroup\$
    – sergiol
    Apr 6, 2018 at 21:20
  • \$\begingroup\$ The real "challenge" is to know the executable file format, so this becomes more of a puzzle than a challenge. And for puzzles, people can just copy others' solution and port to other languages. // Consider having some popular file format in the challenge itself so people don't have to look up them? \$\endgroup\$
    – DELETE_ME
    Apr 7, 2018 at 11:19
  • \$\begingroup\$ @user202729: My initial idea was to ask only for Windows .exe files but I changed my mind because it was too limiting. Without such restrictions the question becomes multi-platform. \$\endgroup\$
    – sergiol
    Apr 7, 2018 at 11:38
-1
\$\begingroup\$

Divide two strings


One day, I saw the challenge to multiply two strings and I thought I might be able to do one better.

That challenge was fake. It was elementwise maximum. It was not real multiplication. So I set out to make something real. Real division between two strings.

I quickly realized that this would make an amazing challenge, as the algorithm was surprisingly complex and interesting to implement.

I then realized that it was actually easily reduced into a mere few operations. I'm still doing the challenge, though.

Enough with the backstory. Let's go.

Method

To divide two strings, do the following, where x is the first string and y the second:

  • If x does not contain y, return a space and a period concatenated to x.
    • For example, testx and blah would become .textx, with a space at the beginning.
  • Otherwise, return every occurrence of y in x, a period, then y divided by x with every occurrence of y removed, with all the periods removed.
    • For example, eestestst and est would become estest.est.

Challenge

Write a program or function that, given two strings via standard input, returns the first string divided by the second.

You may assume that neither input string contains a space, newline or period, and that the operation does not require more than 10 layers of recursion.

Test cases

test, es => es. es
test, blah =>  .test
okayye, y => yy. y
testes, es => eses. es
battat, at => atat. at
see, es =>  .see
see, e => ee. e
same, same => same. 
aabb, ab => ab.ab 
eestestst, est => estest.est
aheahahe, aheah => aheah.aheah ah

Scoring

As this is , the submission with the least amount of bytes wins.

Sandbox questions

  • Is this a duplicate?
  • Have I missed anything?
  • Does anything need further explaining?
  • Is there an issue with the concept of the challenge?
\$\endgroup\$
9
  • \$\begingroup\$ What for aabb / ab? \$\endgroup\$
    – l4m2
    Jun 1, 2018 at 12:42
  • \$\begingroup\$ okayye, y => yy. okay typo? \$\endgroup\$
    – l4m2
    Jun 1, 2018 at 12:42
  • \$\begingroup\$ The test case battat, at => atat. by seems like it should be battat, at => atat. bt instead. \$\endgroup\$ Jun 1, 2018 at 13:47
  • 1
    \$\begingroup\$ It seems odd to me that when no characters are matched the output format is {matched characters (empty)}<space>.{unmatched characters} while the format when there are matches becomes {matched characters}.<space>{unmatched characters}. I would much rather see consistent ordering of the . and <space> \$\endgroup\$ Jun 1, 2018 at 13:50
  • \$\begingroup\$ @KamilDrakari 2 / 4 is 0.5, not .05, when 4 is not contained within 2 at all. Thus it makes no sense for test / blah to be . test when blah is not contained within test. We treat a space essentially like a zero would be with normal numbers. \$\endgroup\$
    – LyricLy
    Jun 1, 2018 at 22:15
  • 1
    \$\begingroup\$ @LyricLy 6/4 is 1.5 not 1.05. If you're treating space as 0 then there shouldn't be any space after the dot in any of the test cases. \$\endgroup\$ Jun 1, 2018 at 22:58
  • \$\begingroup\$ @KamilDrakari Actually, you're right. I was entirely mistaken because you get a fraction from 1 / remainder, not original number / remainder. Meaning this entire thing is wrong and I need to figure out a good replacement for 1 in string form. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 3:32
  • \$\begingroup\$ Fixed the issues. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 3:50
  • \$\begingroup\$ I accept downvotes, but I'd appreciate suggestions on how to improve the idea, or at least an explanation of what's wrong with it, so I know why I shouldn't post it. \$\endgroup\$
    – LyricLy
    Jun 2, 2018 at 8:18
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